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GTSB Problem Set 1 Moshe Hoffman and Erez Yoeli October 2, 2015 If you are working with a partner, you and your partner may turn in a single copy of the problem set. Please show your work and acknowledge any additional resources consulted. 1 The Coordination Game First consider the payoff matrix in Fig. 1, which represents a special case of the coordination game. L L R R 2 0 1 1 Figure 1: A Special Case of the Coordination Game (a) What is the set of strategies for each player? (b) Find both pure Nash equilibria 12 of this game. Is one equilibrium preferred by both players? Now consider the general version of the coordination game is presented in Fig. 2. (c) Show that ( L, L ) and ( R, R ) are the only pure Nash equilibria of this game. (c) Now suppose c > a , but still assume d > b . What are all the pure Nash of this game? 1 For the definition of a Pure Nash equilibrium, check the Game Theory handout, Section 2. 2 Note that pure Nash equilibrium does not require that the players play the same strategy. When the two players do play the same strategy and it is Nash, this is called a symmetric Nash equilibrium . 1
L L R R a b c d a > c , d > b Figure 2: The Coordination Game 2 Hawk-Dove (a) Two animals are fighting over some resource worth v > 0. Each can be a dove (passive) or a hawk (aggressive). If one is aggressive and the other passive, the aggressive opponent gets the resource. If both are aggressive, both animals incur cost c > 0, and each obtains the resource with equal likelihood, where c > v . If both are passive, each obtains the resource with equal likelihood. Write down the set of strategies. Then, in the form of a payoff matrix, write the payoffs each player gets from each strategy profile. Finally, find all pure Nash equilibria. (b) Imagine that there is an imbalance of power between the two animals, and that, if both play hawk, player 1 wins with probably q such that 0 . 5 < q < 1. Assume both animals still incur the cost c of fighting. Write down the payoff matrix of this new game and find all pure Nash equilibria. Does the prediction of the model depend on the likelihood one animal wins? (c) Now, instead, imagine that the imbalance of power causes the costs of fighting to be unequally distributed between the two animals. For example, one animal might incur a cost of - c 8 and the other animal might incur a cost of - 7 c 8 . Write down the payoff matrix of this new game and find all pure Nash equilibria. Does the prediction of the model change this time? (d) Let’s go back to assuming that animals are equally likely to obtain the object and that they pay the same cost c of fighting (i.e. the assumptions in question a. Suppose that before the players play Hawk-Dove, nature randomly assigns one of the players to arrive at the resource first. Suppose, for now, that the players always know who arrived first. Only then do the players play, simultaneously choosing their strategies, as usual. In this setting, a strategy must specify how players will play if they arrive first and how they will play if they arrive second. There are four possible strategies: play hawk always (we can shorten this to hawk), play dove always 2
(dove), play hawk if arrive first and dove if arrive second (this strategy is called bourgeois), and play dove if arrive first and hawk if arrive second (anti-bourgeois). (a) What are the expected payoffs from all four strategy pairs? (b) What are all the Nash equilibria of this game? Justify your answer. (e) Let’s tweak question d to make it more realistic. Suppose again that before the players play Hawk-Dove, nature randomly assigns one of the players to arrive first. But, now suppose that when a player arrives second, there is a probability m that this player mistakenly believes she arrived first. (a) What are the expected payoffs from all four strategy pairs now? (b) Under what conditions on m are the strategy pairs you identified in question db still an equilibrium? 3 War of Attrition In our class, we typically stick to very simple games, and we believe a great deal of insight can be gained from these games. One natural concern is that our results from analyzing such simple games might not carry over if the games were made more complicated or realistic, and thus our insights would not apply to the real world. Throughout the class, we will address this concern. One simplification we often make is to model players as having only 2 or 3 choices, when in practice, they may have many choices, sometimes infinitely many so. We might be concerned that that our results were an artifact of our decision to model players as having only 2 choices (or any finite number). Let’s double check that this is not the case. To do so, we will analyze a game called the War of Attrition, which elaborates on the ideas captured by the Hawk-Dove game by employing continuous strategies. Note that allowing for continuous strategies prevents us from representing a game as a matrix form game, since it fails the condition of having finite strategies. Instead we must represent our payoffs u i as a function of the player’s strategies. With this understanding, we can move on and work with these continuous values. Two animals are fighting over some resource worth v . Now, instead of simply choosing whether to play dove or hawk, the animals must choose for how long to fight before giving up. Let t 1 be the time animal 1 devotes to the fight and t 2 be the time animal 2 devotes to the fight. Fighting is 3
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still costly: fighting costs both animals c > 0 per unit of time. The payoffs of the game are thus: u 1 ( t 1 , t 2 ) = - ct 1 if t 1 < t 2 1 2 v - ct 1 if t 1 = t 2 v - ct 2 if t 1 > t 2 u 2 ( t 1 , t 2 ) = - ct 2 if t 2 < t 1 1 2 v - ct 2 if t 2 = t 1 v - ct 1 if t 2 > t 1 For this problem we will consider that each player can choose a pure strategy, but not a mixed strategy, i.e. players are forbidden to randomize. (a) Let t 1 = 0 and t 2 = v c . Consider what happens when you change the values of t 1 and t 2 according to the above payoffs above (ie., let t 1 be 0 < t 1 < t 2 , t 1 = t 2 , etc.). Is the strategy profile ( t 1 = 0, t 2 = v c ) a Nash Equilibrium? Why? Note that the strategy pair where player 2 devotes 0 and player 1 devotes v c follows the same argument. How does this compare to the Hawk-Dove game we are used to? (b) Using a similar technique, argue that any strategy pair where player 1 devotes t 1 > 0 but t 1 < v c is not a Nash equilibrium. (Note that the same will be true for strategy pairs in which t 2 > 0 but t 2 < v c , by a symmetry argument.) (c) Argue that the strategy pair t 1 = t 2 = 0 is not a Nash equilibrium. Similarly, argue that the strategy pair t 1 = t 2 = v c is not a Nash equilibrium. (d) Are any strategy pairs where player 1 devotes t 1 > v c and player 2 devotes 0 < t 2 < t 1 Nash equilibria? (Note that the same will be true for strategy pairs in which t 2 > v c and 0 < t 1 < t 2 .) (e) What about strategy pairs where t 1 > v c and t 2 = 0? (Note that the same will be true for strategy pairs in which t 2 > v c and t 1 = 0) (f) What’s left? Are there any Nash equilibria other than the two identified in question (a)? If so, how do you interpret the additional equilibria you found? How does the War of Attrition compare to Hawk-Dove? (g) Describe, in general, a method for finding the Nash equilibria of a continuous game. Explain all major steps and justify each. 4 More on the Coordination Game: Mixed Strategies, Risk-Dominance and Mixed Nash (a) Consider the special case of the coordination game presented in Fig. 1. If player 2 is playing L with probability . 1, does player 1 prefer to play L or R ? What about . 9? At what probability 4
is player 1 indifferent between playing L and R ? This number is called the risk-dominance of the coordination game. It will play an important role later in our class. (b) Now consider the general version of the game presented in Fig 2. The parameter p = d - b a - c + d - b is the risk-dominance of the game. If player 2 is playing L with probability < p , does player 1 prefer to play L or R ? What about a probability > p ? Show that player 1 is indifferent between L and R when player 2 plays L with probability p . (c) Based on you answer to b, argue that it is a mixed Nash for both players to play L with probability p , that is, that neither player can benefit by deviating. 3 5 Mixed Nash Equilibria of Hawk-Dove Let’s take another look at the Hawk-Dove game, and find its mixed Nash equilibria. (a) Assume the same problem setup as in question 2, part (a). Describe a mixed strategy. For any mixed strategy, what are the player’s payoffs? (b) Find the mixed Nash equilibrium of this game. (c) Now let’s change the payoffs. Say that the payoff matrix looks as follows: Hawk Dove Hawk a, a b, c Dove c, b d, d ! where a < c and b > d . Find a mixed Nash equilibrium using the same process as above. 6 Population Game: Fisher’s Explanation for 50-50 Sex Ratios Suppose the population size is large and fixed; it doesn’t change from generation to generation. Let f represent the proportion of females in the population, and 1 - f represent the proportion of males. Assume that each offspring must have one male parent and one female parent. Further assume: The cost of having a male and female offspring is the same No inbreeding (a) Suppose the proportion of females is . 7. 3 If you a need more of a reminder, check out the Mixed Nash section of the Game Theory Handout or section 3.1 of Osborne’s textbook. 5
(i) Since the population size is fixed, what is the expected number of offspring for a male parent? A female parent? (ii) For a male parent, what is the expected number of grand-offspring from having a female offspring? A male offspring? For a female parent? These are the payoffs in this game. (b) For any f , what are the payoffs of a male offspring to a male parent? A female offspring? For a female parent? (c) Suppose f > 1 2 . Would you do best by having children at this ratio, or deviating to some other ratio? Justify your answer. (You may ignore the effect of changing your strategy on f since the population is large.) (d) Suppose f < 1 2 . Would you do best by having children at this ratio, or deviating to some other ratio? Justify your answer. (e) What about f = 1 2 ? Based on your answer, and your answers to questions c and d, argue that f = 1 2 is the unique Nash equilibrium of this game. (f) What happens if the population is doubling each generation? What are the payoffs of a male offspring to a male parent? A female offspring? (No need to do female parents–you get the idea.) How would your answers to questions d–e change? (g) Suppose the cost of having a male offspring is 1 2 that of having a female offspring. What are the payoffs of a male offspring to a male parent? A female offspring? What is the unique Nash equilibrium in this case? Suppose the cost of having a male offspring is some proportion m of the cost of having a female offspring. Again, specify the payoffs of a male offspring to a male parent. A female offspring? What is the unique Nash equilibrium as a function of m ? 6
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