CS115_Fall_2023_Lab09_Description (2)

Lab Partner 1 Name Lab Partner 2 Name CS 115 Fall 2023 Lab #09 Due: SUNDAY, November 19, 2023 at 11:59 PM CST Points: 20 Instructions: 1. Use this document template to report your answers. Enter all lab partner names at the top of first page. 2. You don’t need to finish your lab work during the corresponding lab session. 3. ZIP your lab report and java files (if any) into a single ZIP file. Name the ZIP file as follows: LastName_FirstName_CS115_Lab9_Report.zip 4. Submit the final document to Blackboard Assignments section before the due date. No late submissions will be accepted. 5. ALL lab partners need to submit a report, even if it is the same document. Objectives: 1. (10 points) Write and test a user-defined class. 2. (10 points) Write and test a user-defined class and use iterations Problem 1 [10 points]: A) [7 points] Design and implement a class BobsLife that simulates a simple virtual world. In this world there is a person called Bob that is at a location (use a String type to store location) and there are three possible locations:  at home,  at work,  or at the gym. 1

Bob has three integer characteristics: his hunger, his fitness, and the dollars he owns. The class should have an instance method called move that moves Bob from his current location (home, work, or gym) to a new location specified by the method argument . The simulation starts at time 0 (another attribute of Bob). Time moves in steps. The simulation is moved forward by one step manually by calling an instance method nextTime after each move call. Depending on Bob's location when method nextTime is called, the following happens:  If Bob is at home , then his hunger is decreased by 3, because he eats a meal . However, the hunger cannot drop below 0 . Furthermore, his dollars are decreased by 1 because food costs money ,  If Bob is at work , then his hunger is increased by 2, because working makes him hungry . Furthermore, his dollars are increased by 3 (he earns money at his job) . Also: he has a desk job and so his fitness decreases by 1 ,  If Bob is at the gym , then his hunger is increased by 3 because a workout makes him hungry . His dollars are decrease by 2 since the gym costs money . On the positive side his fitness increases by 2 . In addition, this virtual world is quite harsh:  If Bob's hunger goes above 6 then the poor guy starves to death.  If his dollars drop below zero than he is broke and is thrown into jail for a life time sentence.  If his fitness is 0 then he dies of a heart attack. Your class should keep track of whether Bob is dead or in jail (use Boolean data type to keep track of that). If either of these things happens, then it should no longer be possible to move Bob to another location and his characteristics no longer change if the nextTime method is called. The parametrized constructor of the class BobsLife should:  initialize the parameters of the simulation ( time , isDead , inJail ),  and accept arguments for: o Bob's initial location, o and Bob's initial characteristics ( hunger , fitness , dollars ). You only need a private mutator method for the location to verify the argument is correct and set some default location if incorrect. No accessor methods are needed . Finally, write a toString() method for your class that will generate a String type value describing Bob’s “state” at current time (see sample output below). 2

B) [6 points] Implement a class RollDice that in its main method will:  Instantiate one object, called A of class SixSidedDie ,  Instantiate one object, called B of class TwelveSidedDie ,  Use iterations to play: o Game 1: Roll both dice 10 times and sum and display all the rolled values (A and B rolls for each iteration), o Game 2: Keep rolling both dice until the sum of rolled numbers between A and B is 8. Your RollDice program output should look similar to: Game 1 Iteration 1: A rolled 2 and B rolled 1 Iteration 2: A rolled 3 and B rolled 2 Iteration 3: A rolled 5 and B rolled 3 Iteration 4: A rolled 1 and B rolled 10 Iteration 5: A rolled 1 and B rolled 6 Iteration 6: A rolled 5 and B rolled 8 Iteration 7: A rolled 2 and B rolled 6 Iteration 8: A rolled 1 and B rolled 4 Iteration 9: A rolled 4 and B rolled 1 Iteration 10: A rolled 1 and B rolled 10 Final sum of rolls: 76 Game 2 Iteration 1: A rolled 3 and B rolled 1 Iteration 2: A rolled 4 and B rolled 2 Iteration 3: A rolled 3 and B rolled 5 it took 3 iterations to roll a sum of 8. 4