Exam2Spring22

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Texas A&M University *

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315

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Computer Science

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Feb 20, 2024

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ESET 315 Exam 2 –Mar 11 Please sign confirming that you will take this exam following the rules below and according to the Aggie Honor Code: “An Aggie does not lie, cheat or steal, or tolerate those who do.” Signature: ___________________ UIN: _____________________ Rules: This is a closed book, closed notes exam. No calculators are allowed. You will need only a pencil and an eraser. You must show all your work to receive full credit for your answers. There are 4 questions for a total of 85 points. Good luck! References: Subnet Masks table IP Addresses and Subnet Masks: Bit 7 128 Bit 6 64 Bit 5 32 Bit 4 16 Bit 3 8 Bit 2 4 Bit 1 2 Bit 0 1 0 0000 0000 128 1000 0000 192 1100 0000 224 1110 0000 240 1111 0000 248 1111 1000 252 1111 1100 254 1111 1110 255 1111 1111 Page 1 of 8
ESET 315 Exam 2 –Mar 11 HDLC frame (Note: sizes above are in bits) Point-to-Point (PPP) frame (Note: sizes above are in bits) This is a Wi-Fi frame (IEEE 802.11) (Note: sizes above are in bytes) Page 2 of 8
ESET 315 Exam 2 –Mar 11 Question 1 (30 points) Given the Wireshark packet below: Frame 164: 100 bytes on wire (800 bits), 100 bytes captured (800 bits) on interface \Device\ NPF_{9B5130AE-DED7-470E-904A-45CCFF1D9DF2}, id 0 Ethernet II, Src: PcsCompu_76:72:3c (08:00:27:76:72:3c), Dst: ASUSTekC_94:1e:e0 (18:31:bf: 94:1e:e0) Destination: ASUSTekC_94:1e:e0 (18:31:bf:94:1e:e0) Source: PcsCompu_76:72:3c (08:00:27:76:72:3c) Type: IPv4 (0x0800) Internet Protocol Version 4, Src: 192.168.1.172, Dst: 10.8.0.6 0100 .... = Version: 4 .... 0101 = Header Length: 20 bytes (5) Differentiated Services Field: 0x00 (DSCP: CS0, ECN: Not-ECT) Total Length: 86 Identification: 0xc018 (49176) Flags: 0x40, Don't fragment Fragment Offset: 0 Time to Live: 128 Protocol: TCP (6) Header Checksum: 0x0000 [validation disabled] [Header checksum status: Unverified] Source Address: 192.168.1.172 Destination Address: 10.8.0.6 Transmission Control Protocol, Src Port: 4712, Dst Port: 50723, Seq: 221, Ack: 55, Len: 46 Source Port: 4712 Destination Port: 50723 [Stream index: 1] [TCP Segment Len: 46] Sequence Number: 221 (relative sequence number) Sequence Number (raw): 1087335542 [Next Sequence Number: 267 (relative sequence number)] Acknowledgment Number: 55 (relative ack number) Acknowledgment number (raw): 2769092988 0101 .... = Header Length: 20 bytes (5) Flags: 0x018 (PSH, ACK) Window: 1025 [Calculated window size: 262400] [Window size scaling factor: 256] Checksum: 0xccaa [unverified] [Checksum Status: Unverified] Urgent Pointer: 0 [SEQ/ACK analysis] [Timestamps] TCP payload (46 bytes) [PDU Size: 46] IEEE C37.118 Synchrophasor Protocol, Data Frame [correct] Synchronization word: 0xaa01 Framesize: 46 bytes PMU/DC ID number (Stream source ID): 1 SOC time stamp: Feb 24, 2021 16:18:04.000000000 UTC Time quality flags Fraction of second (raw): 317000 Fraction of second: 317 milliseconds Measurement data [Dissected using configuration from frame: 160] Station: "1 " Flags Phasors (1), notation: rectangular, format: integer Phasor #1: "BV000001 ", 80245.099V ∠ 11.064° alt 78753.676+j15399.173V; unscaled: 4301, 841 Frequency deviation from nominal: 2448mHz (actual frequency: 62.448Hz) Rate of change of frequency: 0.000Hz/s Station: "2 " Flags Phasors (1), notation: rectangular, format: integer Phasor #1: "BV000002 ", 79823.624V ∠ 13.099° alt 77746.595+j18090.823V; unscaled: 4246, 988 Frequency deviation from nominal: 2448mHz (actual frequency: 62.448Hz) Rate of change of frequency: 0.000Hz/s Station: "3 " Page 3 of 8
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ESET 315 Exam 2 –Mar 11 Flags Phasors (1), notation: rectangular, format: integer Phasor #1: "BV000003 ", 0.000V ∠ 0.000° alt 0.000+j 0.000V; unscaled: 0, 0 Frequency deviation from nominal: 5536mHz (actual frequency: 65.536Hz) Rate of change of frequency: 0.000Hz/s Checksum: 0x7c4d [correct] [Checksum Status: Good] (9 points) Draw this Wireshark packet showing all the layers (each header) and their sizes. For the Layer 2 header (Data link header), you should show all the header fields and their values . (6 points) Draw this same Wireshark packet but assume that now it is being transmitted over a serial link with HDLC encapsulation. Show the new packet with all its header fields. (3 points) If the source node who sent the packet has IP address 192.168.1.172 with subnet mask 255.255.255.224. What is its subnet number? Please show your work. (3 points) What is the transmission delay of this packet, assuming the source node is connected to a 100BaseTx link. Page 4 of 8
ESET 315 Exam 2 –Mar 11 Question 1 (continued) ( 9 points) Given the source MAC address 08:00:27:76:72:3c, encode the bits of the first byte of this MAC address using the signaling encoding used in 100BaseTx networks. Page 5 of 8
ESET 315 Exam 2 –Mar 11 Question 2 (15 points) Assume you are one of the network adaptors below: a) (9 points) As an adaptor, when you receive the Manchester waveform shown below, what is the actual information bits (0’s and 1’s) that you are receiving? (make sure to show in the figure how you decoded it). b) 6 points) As an adaptor receiving the Manchester signal, please describe your properties/or specifications: Name of physical layer protocol:_______________________________ Media (or cabling) type: __________________________________________ Bit rate: ____________________________________________________ Baud rate (or symbol rate): ______________________ Signaling efficiency:_______________________________ Page 6 of 8
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ESET 315 Exam 2 –Mar 11 Question 3 (20 points) a) ( 6 points) Circle all the networks (or subnets) shown. How many networks did you find? (14 points) Assume Host 1 (H1) above has an IP address 128.194.20.138/29. What is i. the subnet number of this IP address ii. first IP address in the subnet listed in i., iii. last IP address in the subnet listed in i., and iv. broadcast address of the subnet listed in i. v. the number of usable host IP addresses in the subnet listed in i. vi. the class of this address Page 7 of 8
ESET 315 Exam 2 –Mar 11 Question 4 (20 points) (15 points) Suppose you want to transmit the data 100 111 001 and the generator polynomial is x 6 + x 3 + 1. Use polynomial long division to show the CRC calculation. (5 points) What is the transmitted codeword P(x) in polynomial form and in binary? Page 8 of 8

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