ESET315_Hwk8_Due_April10

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Texas A&M University *

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Feb 20, 2024

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ESET315 – Hwk8 – Due Monday, April 10 Question 1 (20 points) Checking IP address assignments: In Figure 1, this is the following address assignment: - Fred is configured with IP address 10.1.1.1, mask 255.255.255.240. - Router A’s Ethernet interface is configured with 10.1.1.2, mask 255.255.255.240. - Router A’s serial interface uses 10.1.1.130, mask 255.255.255.252. - Router B’s serial interface uses 10.1.1.131, mask 255.255.255.252. - Router B’s Ethernet uses 10.1.1.200, mask 255.255.255.128. - The Web server uses 10.1.1.201, mask 255.255.255.128. A B Fred Web Server E0 E0 S0 S0 Figure 1 a) (10 points) Is anything wrong with this network? Please justify your work, show all your calculations to support your answer. b) (10 points) How can you fix this network. Apply your solution (your IP addresses/masks) in the drawing below and explain how your solution works
A B Fred Web Server E0 E0 S0 S0 Question 2 (10 points) Given this Wireshark packet below: Frame 2: 60 bytes on wire (480 bits), 60 bytes captured (480 bits) on interface \ Device\NPF_{7C355956-DBED-4E94-8E33-F8D78CE747FC}, id 0 IEEE 802.3 Ethernet Destination: Spanning-tree-(for-bridges)_00 (01:80:c2:00:00:00) Address: Spanning-tree-(for-bridges)_00 (01:80:c2:00:00:00) .... ..0. .... .... .... .... = LG bit: Globally unique address (factory default) .... ...1 .... .... .... .... = IG bit: Group address (multicast/broadcast) Source: Cisco_6e:92:c1 (00:05:5e:6e:92:c1) Address: Cisco_6e:92:c1 (00:05:5e:6e:92:c1) .... ..0. .... .... .... .... = LG bit: Globally unique address (factory default) .... ...0 .... .... .... .... = IG bit: Individual address (unicast) Length: 38 Padding: 0000000000000000 Logical-Link Control DSAP: Spanning Tree BPDU (0x42) 0100 001. = SAP: Spanning Tree BPDU .... ...0 = IG Bit: Individual SSAP: Spanning Tree BPDU (0x42) 0100 001. = SAP: Spanning Tree BPDU .... ...0 = CR Bit: Command Control field: U, func=UI (0x03) 000. 00.. = Command: Unnumbered Information (0x00) .... ..11 = Frame type: Unnumbered frame (0x3) Spanning Tree Protocol Protocol Identifier: Spanning Tree Protocol (0x0000) Protocol Version Identifier: Spanning Tree (0) BPDU Type: Configuration (0x00) BPDU flags: 0x00 0... .... = Topology Change Acknowledgment: No .... ...0 = Topology Change: No Root Identifier: 32768 / 0 / 00:05:5e:6e:92:c2
Root Bridge Priority: 32768 Root Bridge System ID Extension: 0 Root Bridge System ID: Cisco_6e:92:c2 (00:05:5e:6e:92:c2) Root Path Cost: 0 Bridge Identifier: 32768 / 0 / 00:05:5e:6e:92:c2 Port identifier: 0x800d Message Age: 0 Max Age: 20 Hello Time: 2 Forward Delay: 15 (9 points) Draw this packet and all its layers. Make sure to show all header fields, and their sizes. (1 point) What is the application layer protocol? ______________________ Question 3 (12 points) For the diagram in Figure 3, a. (3 points) Circle the root switch. b. (6 points) Draw the minimum spanning tree for the tree, by simply darkening the lines that will be active, and crossing out the lines that will be blocked. c. (6 points) Write the final BPDU values for each switch, assuming all links stay in a functional state throughout.
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Figure 2