Physics Homework 3

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The University of Oklahoma *

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Feb 20, 2024

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theExpertTA.com | Student: Jocelyn.D.Pranabdev-1@ou.edu My Account Log Out Class Management | Help Problem 1: Suppose a pilot flies 45 km in a direction 60° north of east and then flies 29 km in a direction 15° north of east as shown in the figure. Part (a) Find her distance R from the starting point in kilometers. Grade = 100% Correct Answer Student Final Submission Feedback R = R = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 06, 2023 12:12 AM R = 2 Feb 06, 2023 12:12 AM R = 3 Feb 06, 2023 12:17 AM R = Part (b) Find the angle θ in ° N of E. Grade = 100% Correct Answer Student Final Submission Feedback θ = θ = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 06, 2023 12:18 AM θ = Problem 2: Consider the three vectors shown in the figure. They have magnitudes | A | = 39 , | B | = 9.5 , and | C | = 32.7 , and the labeled angles are θ A = 40°, θ B = 20°, and θ C = 15°. Note that the figure shows the definitions of the angles, but the arrows in the figure may not be to scale. Part (a) In what quadrant is the vector A + B + C ? Grade = 100% Correct Answer Student Final Submission Feedback Q4 Q4 Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 06, 2023 12:18 AM Q3 Note: Feedback provided here but not accessed during assignment. In the quadrant you selected, both x and y are negative. This is not true of the vector you are looking for. 2 Feb 06, 2023 12:18 AM Q2 Note: Feedback provided here but not accessed during assignment. In the quadrant you selected, x is negative while y is positive. This is not true of the vector you are looking for. 3 Feb 06, 2023 12:19 AM Q4 Part (b) What is the magnitude of the vector A + B + C ? Grade = 100% Correct Answer Student Final Submission Feedback | A + B + C | = | A + B + C | = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 06, 2023 12:20 AM | A + B + C | = Note: Feedback provided here but not accessed during assignment. The magnitude of the resulting vector is not equal to the sum of their magnitudes. 2 Feb 07, 2023 10:12 PM | A + B + C | = 3 Feb 07, 2023 10:19 PM | A + B + C | = 23.014 | A + B + C | = Note: Feedback provided here but not accessed during assignment. Check the angle created by vector C with axes of the coordinates. It is measured from the y-axis not from the x. 4 Feb 07, 2023 10:19 PM | A + B + C | = - 23.014 | A + B + C | = 5 Feb 07, 2023 10:20 PM | A + B + C | = + 23.014 | A + B + C | = Note: Feedback provided here but not accessed during assignment. Check the angle created by vector C with axes of the coordinates. It is measured from the y-axis not from the x. 6 Feb 07, 2023 10:41 PM | A + B + C | = 7 Feb 07, 2023 10:44 PM | A + B + C | = - 17.08 | A + B + C | = 8 Feb 07, 2023 11:00 PM | A + B + C | = 17.079 | A + B + C | = 9 Feb 07, 2023 11:00 PM | A + B + C | = - 7.079 | A + B + C | = 10 Feb 07, 2023 11:00 PM | A + B + C | = - 17.079 | A + B + C | = 11 Feb 07, 2023 11:08 PM | A + B + C | = Part (c) What is the angle between the positive x -axis and the vector, measured clockwise in degrees? Grade = 100% Correct Answer Student Final Submission Feedback θ 1 = θ 1 = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 06, 2023 12:20 AM θ 1 = 2 Feb 06, 2023 12:20 AM θ 1 = - 50 θ 1 = 3 Feb 06, 2023 12:21 AM θ 1 = - 320 θ 1 = 4 Feb 06, 2023 12:21 AM θ 1 = 5 Feb 07, 2023 10:21 PM θ 1 = 6 Feb 07, 2023 10:22 PM θ 1 = 7 Feb 08, 2023 1:54 AM θ 1 = Part (d) In what quadrant is the vector - A +2 B + C ? Grade = 100% Correct Answer Student Final Submission Feedback Q3 Q3 Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 07, 2023 10:20 PM Q1 Note: Feedback provided here but not accessed during assignment. In this quadrant, both x and y is positive. 2 Feb 07, 2023 10:20 PM Q4 Note: Feedback provided here but not accessed during assignment. In this quadrant, x is positive while y is negative. 3 Feb 07, 2023 10:20 PM Q2 Note: Feedback provided here but not accessed during assignment. In this quadrant, x is negative while y is positive. 4 Feb 07, 2023 10:21 PM Q3 Part (e) What is the magnitude of the vector - A + 2 B + C ? Grade = 100% Correct Answer Student Final Submission Feedback |- A +2 B + C | = |- A +2 B + C | = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 07, 2023 11:15 PM |- A +2 B + C | = Note: Feedback provided here but not accessed during assignment. You may have lost a multiplier of 2 in the y -component of vector B in your calculation. 2 Feb 08, 2023 2:02 AM |- A +2 B + C | = Part (f) What is the angle between the negative x -axis and this vector, measured counterclockwise in degrees? Grade = 100% Correct Answer Student Final Submission Feedback θ 2 = θ 2 = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 2:04 AM θ 2 = Problem 3: After being marooned by his crew on an island in the Atlantic, Captain William Kidd builds a raft to escape and set out to sea on it. The wind seems quite steady, at first blowing him due east for 11 km and then 12 km in a direction 9 degrees north of east. Confident that he will eventually reach safety, he falls asleep. When he wakes up, he notices the wind is now blowing him gently 12 degrees south of east, and after traveling for 21 km in that direction, he finds himself back on the island! Part (a) How far, as the crow flies, in kilometers, did the wind blow him while he was sleeping? Grade = 100% Correct Answer Student Final Submission Feedback r = r = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 07, 2023 2:07 AM r = Part (b) Assuming the wind blew in the same direction all night, while he was sleeping, what direction in degrees north of west, did the wind blow Captain Kidd during the night? Grade = 100% Correct Answer Student Final Submission Feedback θ = θ = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 07, 2023 2:08 AM θ = - 3.28 θ = Note: Feedback provided here but not accessed during assignment. Check the signs of your components. Refer to your diagram. 2 Feb 07, 2023 2:09 AM θ = - 3.283 θ = Note: Feedback provided here but not accessed during assignment. Check the signs of your components. Refer to your diagram. 3 Feb 07, 2023 2:09 AM θ = Problem 4: An airplane starts at rest and accelerates at 6.9 m/s 2 at an angle of 36 ° south of west. Part (a) After 8 s, how far in the westerly direction has the airplane traveled? Grade = 100% Correct Answer Student Final Submission Feedback west = west = 178.63 west = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 2:07 AM west = 2 Feb 08, 2023 2:07 AM west = 3 Feb 08, 2023 2:14 AM west = 4 Feb 08, 2023 2:20 AM west = 5 Feb 08, 2023 2:21 AM west = 209.99 west = 6 Feb 08, 2023 2:22 AM west = - 68.23 west = 7 Feb 08, 2023 2:23 AM west = 178.63 west = Part (b) After 8 s, how far in the southerly direction has the airplane traveled? Grade = 100% Correct Answer Student Final Submission Feedback south = south = 129.78 south = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 2:23 AM south = 129.78 south = Problem 5: A ball is thrown horizontally from the top of a 55 m building and lands 135 m from the base of the building. Ignore air resistance, and use a coordinate system whose origin is at the top of the building, with positive y upwards and positive x in the direction of the throw. Part (a) How long is the ball in the air in seconds? Grade = 100% Correct Answer Student Final Submission Feedback t = t = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 2:36 AM t = Part (b) What must have been the initial horizontal component of the velocity, in meters per second? Grade = 100% Correct Answer Student Final Submission Feedback v 0x = v 0x = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 2:37 AM v 0x = Part (c) What is the vertical component of the velocity just before the ball hits the ground, in meters per second? Grade = 100% Correct Answer Student Final Submission Feedback v y = v y = - 32.86 v y = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 2:39 AM v y = 2 Feb 08, 2023 2:39 AM v y = 3 Feb 08, 2023 2:40 AM v y = Note: Feedback provided here but not accessed during assignment. The magnitude is right, but we asked you to take the positive direction of y up. What is the sign of the y-component of velocity in such a system of coordinates? 4 Feb 08, 2023 2:41 AM v y = Note: Feedback provided here but not accessed during assignment. The magnitude is right, but we asked you to take the positive direction of y up. What is the sign of the y-component of velocity in such a system of coordinates? 5 Feb 08, 2023 2:41 AM v y = - 32.86 v y = Part (d) What is the magnitude of the velocity of the ball just before it hits the ground, in meters per second? Grade = 100% Correct Answer Student Final Submission Feedback v = v = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 2:42 AM v = Problem 6: The world long jump record is 8.95 m (Mike Powell, USA, 1991). Treated as a projectile, what is the maximum range, in meters, obtainable by a person if he or she has a take-off speed of 8.6 m/s? Assume the motion is over level ground and the initial velocity makes an angle of 45° with the horizontal. Grade = 100% Correct Answer Student Final Submission Feedback R = R = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 11:45 AM R = Problem 7: During a baseball game, a baseball is struck, at ground level, by a batter. The ball leaves the baseball bat with an initial speed at an angle above the horizontal. Let the origin of the Cartesian coordinate system be the ball's position the instant it leaves the bat. Ignore air resistance throughout this problem. Part (a) Express the magnitude of the ball’s initial horizontal velocity component, , in terms of and . Grade = 100% Correct Answer Student Final Submission Feedback = v 0 cos( θ ) = v 0 cos( θ ) Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 11:52 AM = v 0 cos( θ ) Part (b) Express the magnitude of the ball’s initial vertical velocity component, , in terms of and . Grade = 100% Correct Answer Student Final Submission Feedback = v 0 sin( θ ) = v 0 sin( θ ) Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 11:53 AM = v 0 sin( θ ) Part (c) Find the ball’s maximum vertical height, , in meters, above the ground. Grade = 100% Correct Answer Student Final Submission Feedback = = 3.00 = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 11:59 AM = 2 Feb 08, 2023 12:00 PM = 3.00 = Part (d) Enter an expression in terms of , , and for the time it takes the ball to travel to its maximum vertical height. Grade = 100% Correct Answer Student Final Submission Feedback = v 0 sin( θ )/g = ( v 0 sin( θ ) )/g Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 12:01 PM = ( v 0 2 sin( θ ) 2 )/( 2 g ) 2 Feb 08, 2023 12:02 PM = ( v 0 2 sin( θ ) 2 )/( - 2 - g ) 3 Feb 08, 2023 12:07 PM = ( v 0 sin( θ ) )/g Part (e) Calculate the horizontal distance, , in meters, that the ball has traveled when it returns to ground level. Grade = 100% Correct Answer Student Final Submission Feedback = = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 12:07 PM = 2 Feb 08, 2023 12:08 PM = 6.0 = 3 Feb 08, 2023 12:09 PM = 4 Feb 08, 2023 12:09 PM = Problem 8: A baseball slugger hits a pitch and watches the ball fly into the bleachers for a home run, landing higher than it was struck. When visiting with the fan that caught the ball, he learned the ball was moving with final velocity at an angle below the horizontal when caught. Assume the ball encountered no air resistance, and use a Cartesian coordinate system with the origin located at the ball's initial position. Part (a) Create an expression for the ball’s initial horizontal velocity, , in terms of the variables given in the problem statement. Grade = 100% Correct Answer Student Final Submission Feedback = v f cos( θ f ) = v f cos( θ f ) Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 1:51 PM = v f cos( θ f ) Part (b) Calculate the magnitude, in meters per second, of the vertical component of the ball’s initial velocity. Grade = 100% Correct Answer Student Final Submission Feedback = = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 1:51 PM = 2 Feb 08, 2023 1:57 PM = 3 Feb 08, 2023 1:57 PM = 56.497 = 4 Feb 08, 2023 2:02 PM = Note: Feedback provided here but not accessed during assignment. Vertical component of velocity is not conserved. Write the equation connecting final and initial velocity, acceleration and displacement in vertical direction. Be careful with signs. 68.64 68.82 74.00 59.50 68.82 42.62 42.78 42.78 12.91 13.02 81.20 107.0 23.01 - 23.01 23.01 17.08 - 17.08 17.08 - 7.079 - 17.08 13.02 14.67 14.67 50.00 - 50.00 - 320.0 320.0 40.00 105.0 14.67 75.32 75.33 78.24 75.33 41.75 41.75 41.75 43.47 43.46 43.46 3.283 3.283 - 3.280 - 3.283 3.283 178.6 178.6 441.6 55.20 220.8 68.23 210.0 - 68.23 178.6 129.8 129.8 129.8 3.350 3.350 3.350 40.30 40.30 40.30 - 32.83 - 32.86 35.80 35.77 32.83 32.86 - 32.86 51.98 51.98 51.98 7.547 7.550 7.550 = 28.7 m/s v 0 = 15.5 v 0, x v 0 v 0, x v 0, x v 0, x v 0, y v 0 v 0, y v 0, y v 0, y h max h max 2.995 m h max h max 3.000 m h max 11.23 m h max h max 3.000 m v 0 g t apex t apex t apex t apex t apex x max x max 43.23 m x max 43.29 m x max 39.02 m x max x max 6.000 m x max 27.66 m x max 43.29 m h = 6.5 m = 34.8 m/s v f = f 33.5 v 0, x v 0, x v 0, x v 0, x v 0, y 22.27 m/s v 0, y 22.28 m/s v 0, y 29.02 m/s v 0, y 56.50 m/s v 0, y v 0, y 56.50 m/s v 0, y 19.21 m/s
initial velocity, acceleration and displacement in vertical direction. Be careful with signs. 5 Feb 08, 2023 2:03 PM = - 19.21 = 6 Feb 08, 2023 2:11 PM = 7 Feb 08, 2023 2:11 PM = - 1.96 = 8 Feb 08, 2023 2:11 PM = 9 Feb 08, 2023 2:17 PM = 10 Feb 08, 2023 2:18 PM = - 23.03 = 11 Feb 08, 2023 2:22 PM = Part (c) Calculate the magnitude, in meters per second, of the ball’s initial velocity. Grade = 100% Correct Answer Student Final Submission Feedback = = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 2:24 PM = Part (d) Find the angle above the horizontal, in degrees, at which the ball left the bat. Grade = 100% Correct Answer Student Final Submission Feedback = = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 2:26 PM = Problem 9: An arrow is shot from a height of 1.7 m toward a cliff of height H . It is shot with a velocity of 29 m/s at an angle of 60° above the horizontal. It lands on the top edge of the cliff 3.62 s later. Part (a) What is the height H of the cliff in m? Grade = 100% Correct Answer Student Final Submission Feedback H = H = 28.40 H = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 5:49 PM H = Note: Feedback provided here but not accessed during assignment. You may have forgotten to square time in the term with g . Check units, for all terms they should be the same (meters). 2 Feb 08, 2023 5:49 PM H = - 74.88 H = 3 Feb 08, 2023 5:50 PM H = 28.40 H = Part (b) What is the maximum height reached by the arrow along its trajectory in meters? Grade = 100% Correct Answer Student Final Submission Feedback h max = h max = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 5:54 PM h max = Note: Feedback provided here but not accessed during assignment. You may have forgotten that an arrow has been shot from height h above the ground. 2 Feb 08, 2023 5:54 PM h max = 3 Feb 08, 2023 5:54 PM h max = 4 Feb 08, 2023 5:56 PM h max = - 42.91 h max = 5 Feb 08, 2023 6:46 PM h max = Note: Feedback provided here but not accessed during assignment. You may have forgotten to square sin while squaring the vertical component of velocity. 6 Feb 08, 2023 6:47 PM h max = + 39.1 h max = Note: Feedback provided here but not accessed during assignment. You may have forgotten to square sin while squaring the vertical component of velocity. 7 Feb 08, 2023 6:47 PM h max = - 39.1 h max = 8 Feb 08, 2023 6:50 PM h max = Part (c) What is the arrow’s speed just before hitting the cliff in m/s? Grade = 100% Correct Answer Student Final Submission Feedback v = v = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 6:53 PM v = 2 Feb 08, 2023 6:56 PM v = 3 Feb 08, 2023 6:58 PM v = - 6.48 v = 4 Feb 08, 2023 7:03 PM v = 5 Feb 08, 2023 7:05 PM v = - 44.35 v = 6 Feb 08, 2023 7:05 PM v = 7 Feb 08, 2023 7:06 PM v = 8 Feb 08, 2023 7:09 PM v = Problem 10: An archer shoots an arrow at a target that is a horizontal distance d = 55 m away; the bull’s-eye of the target is at same height as the release height of the arrow. Randomized Variables d = 55 m At what angle, in degrees above the horizontal, must the arrow be released to hit the bull’s-eye if the arrow's initial speed is 35 m/s? Grade = 100% Correct Answer Student Final Submission Feedback θ 0 = θ 0 = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 7:12 PM θ 0 = Problem 11: The velocity of the wind relative to the water is crucial to sailboats. Suppose a sailboat is in an ocean current that has a velocity of 2.9 m/s in a direction 35 ° east of north relative to the Earth. It encounters a wind that has a velocity of 4.1 m/s in a direction of 53 ° south of west relative to the Earth. Part (a) What is the magnitude of the velocity of the wind relative to the water, in meters per second? Grade = 100% Correct Answer Student Final Submission Feedback v AW = v AW = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 7:21 PM v AW = 2 Feb 08, 2023 7:22 PM v AW = Part (b) What is the angle of the velocity of the wind relative to the water degrees south of west? Grade = 100% Correct Answer Student Final Submission Feedback a = a = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 7:22 PM a = 2 Feb 08, 2023 7:22 PM a = - 55.85 a = 3 Feb 08, 2023 7:23 PM a = 4 Feb 08, 2023 7:25 PM a = 5 Feb 08, 2023 7:26 PM a = 6 Feb 08, 2023 7:26 PM a = 7 Feb 08, 2023 7:26 PM a = Problem 12: A jet airplane flying from Darwin, Australia, has an air speed of 256 m/s in a direction 5.0° south of west. It is in the jet stream, which is blowing at 39 m/s in a direction 15° south of east. In this problem you are going to be asked about the velocity of the airplane relative to the Earth. Part (a) What is the magnitude of the velocity of the airplane relative to the Earth in m/s? Grade = 100% Correct Answer Student Final Submission Feedback v PG = v PG = 217.698 v PG = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 7:33 PM v PG = 217.698 v PG = Part (b) What is the angle of the velocity of the airplane relative to the Earth in degrees? Give the angle S of W. Grade = 100% Correct Answer Student Final Submission Feedback β = β = Correct! Grade Summary Deduction for Final Submission 0 % Deductions for Incorrect Submissions, Hints and Feedback [?] 0 % Student Grade = 100 - 0 - 0 = 100% Submission History All Date times are displayed in Central Standard Time. Red submission date times indicate late work. Date Time Answer Hints Feedback 1 Feb 08, 2023 7:33 PM β = 2 Feb 08, 2023 7:33 PM β = - 3.22 β = 3 Feb 08, 2023 7:46 PM β = 4 Feb 08, 2023 7:46 PM β = 5 Feb 08, 2023 7:46 PM β = 6 Feb 08, 2023 7:46 PM β = 60.0 β = 7 Feb 08, 2023 7:46 PM β = 90.0 β = 8 Feb 08, 2023 7:46 PM β = 9 Feb 08, 2023 7:48 PM β = Note: Feedback provided here but not accessed during assignment. The answer provided was not correct. We have recognized the following, - Your answer appears to be off by a factor of 10 n , where n is an integer value. Ensure you have represented the number in the correct units. 10 Feb 08, 2023 7:48 PM β = - 86.78 β = Note: Feedback provided here but not accessed during assignment. The answer provided was not correct. We have recognized the following, - Your answer appears to be off by a factor of 10 n , where n is an integer value. Ensure you have represented the number in the correct units. Your answer contains a sign error. 11 Feb 08, 2023 7:48 PM β = - 86.0 β = Note: Feedback provided here but not accessed during assignment. The answer provided was not correct. We have recognized the following, - Your answer appears to be off by a factor of 10 n , where n is an integer value. Ensure you have represented the number in the correct units. Your answer contains a sign error. 12 Feb 08, 2023 7:49 PM β = - 87.8 β = 13 Feb 08, 2023 7:49 PM β = - 85.8 β = Note: Feedback provided here but not accessed during assignment. The answer provided was not correct. We have recognized the following, - Your answer appears to be off by a factor of 10 n , where n is an integer value. Ensure you have represented the number in the correct units. Your answer contains a sign error. 14 Feb 08, 2023 7:49 PM β = - 85.9 β = Note: Feedback provided here but not accessed during assignment. The answer provided was not correct. We have recognized the following, - Your answer appears to be off by a factor of 10 n , where n is an integer value. Ensure you have represented the number in the correct units. Your answer contains a sign error. 15 Feb 08, 2023 7:49 PM β = - 86.5 β = Note: Feedback provided here but not accessed during assignment. The answer provided was not correct. We have recognized the following, - Your answer appears to be off by a factor of 10 n , where n is an integer value. Ensure you have represented the number in the correct units. Your answer contains a sign error. 16 Feb 08, 2023 7:49 PM β = Note: Feedback provided here but not accessed during assignment. The answer provided was not correct. We have recognized the following, - Your answer appears to be off by a factor of 10 n , where n is an integer value. Ensure you have represented the number in the correct units. 17 Feb 08, 2023 7:49 PM β = All content © 2023 Expert TA, LLC v 0, y v 0, y - 19.21 m/s v 0, y 1.960 m/s v 0, y v 0, y - 1.960 m/s v 0, y 68.21 m/s v 0, y 23.03 m/s v 0, y v 0, y - 23.03 m/s v 0, y 22.28 m/s v 0 36.59 m/s v 0 37.52 m/s v 0 37.52 m/s 37.52 37.52 37.52 28.40 28.40 74.88 - 74.88 28.40 33.85 32.91 32.18 28.40 42.91 - 42.91 39.10 39.10 - 39.10 32.91 17.84 17.84 16.86 37.39 - 6.480 44.91 - 44.35 44.35 52.25 17.84 13.05 13.07 13.07 6.999 6.980 1.270 6.980 53.83 55.00 55.85 - 55.85 6.980 34.21 55.79 55.50 55.00 219.8 217.7 217.7 8.480 8.500 3.220 - 3.220 217.7 0.000 45.00 60.00 90.00 181.0 86.78 - 86.78 - 86.00 - 87.80 - 85.80 - 85.90 - 86.50 86.50 8.500
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