HW11-CE357-Stress Distribution and Settlement

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University of Texas *

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357

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Civil Engineering

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Dec 6, 2023

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1 The University of Texas at Austin CE 357 Department of Civil, Architectural Geotechnical Engineering And Environmental Engineering Prof. El Mohtar Homework No. 11 Stress Distribution and Settlement 1. [40 Points] As depicted below, a column imparts a 500 kip load (1 kip = 1000 lbs) to the top of a concrete footing on the ground surface. The footing is rectangular, measuring 5 ft by 8 ft in plan. Assume the footing distributes the column load uniformly to the soil (imparts a uniform pressure to ground surface). 2. (a.) Compute the change in vertical stress below the center of the footing (point A). Plot the change in vertical stress from the ground surface to a depth of 20 ft. Use two methods to compute the change in vertical stress: 2:1 (vertical:horizontal) approximate load distribution Boussinesq’s solution ( Use any of the stress distribution chart solutions that you find best.). Plot the results from both methods on the same graph, with stresses on the horizontal axis and depth on the vertical axis. (b.) Now, using only Boussinesq’s solution, plot the change in vertical stress from the ground surface down to 20 ft below the center (A), corner (B), and the mid-point of one edge (C) of the footing as shown in the sketch. 2. [30 Points] A new hotel is shown below in plan and cross section. The hotel has a 5-story structure along with a 10-story tower. Construction of the hotel imparts a uniform increase in pressure of 500 psf and 1000 psf as indicated. Find the increase in vertical stress at 50 ft below the ground surface at points A, B, and C. Use any of the stress distribution chart solutions that you find best. Elevation Plan View q=500 psf q=1000 psf 100 ft 50 ft 60 ft 60 ft A B C 1 ft 8 ft 4 ft B C A Soil: T = 110 pcf 500 kips 2.5 ft 5 ft
2 3. [30 Points] A spread footing is designed to have dimensions 15 ft by 15 ft and will carry a load of 225 kips. The reinforced concrete (γ=150 pcf) footing is 2.5 ft thick. The footing will be placed at the surface of a clay deposit that is 28 ft thick. The clay layer is underlain by very dense sand. The groundwater table is located 5 ft below the ground surface, but the clay is saturated to the surface due to capillarity. For simplicity, you can ignore capillary stresses when calculating effective stresses above the GWT. The clay (above and below the GWT) has a total unit weight of 118 pcf, an initial void ratio of 0.91, a compression index of 1.0, a recompression index of 0.2, a coefficient of consolidation of 0.18 ft 2 /day, an OCR of 3.0 and a modulus of elasticity (E) of 1.2 x 10 6 psf. Estimate the total settlement at the center and corner of the footing caused by the load and the weight of the footing. Include immediate and consolidation settlements, but ignore secondary compression. In your calculation, use three sublayers with thicknesses of 4 ft, 8 ft and 16 ft for the top, middle and bottom layers. For primary consolidation calculations, use any of the stress distribution chart solutions that you find best to determine the change in stresses at the mid-height of each sublayer under the center of the footing. Ignore any settlement caused by the dense sand layer.
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