Module 6 Unit 2 Assignment A

MODULE 6 UNIT 2 new Assignment Part A By: Connie Warburton 1. An automobile airbag inflates when N 2 gas results from the explosive decomposition of sodium azide (NaN 3 ), 2 NaN 3 (s)  2 Na (s) + 3 N 2 (g) Calculate the mass of NaN 3 required to produce 50.0 L of N gas at STP. (5 marks) 50.0 L N 2 x 1 mol / 22.4 L = 2.2321428571 = 2.23 mol N 2 2.23 mol N 2 x 2 mol NaN 3 / 3 mol N 2 = 1.4866666667 = 1.49 mol NaN 3 1 mol NaN 3 = 22.990g + (3 x 14.007g) = 65.011g 1.49 mol NaN 3 x 65.011g / 1 mol = 96.86639 = 96.87g NaN 3 1. How many grams of LiOH are needed to remove all the CO 2 from the enclosed space of a spaceship whose volume is 2.4×10 5 L, according to the reaction : 2LiOH (s) + CO 2 (g) → Li 2 CO 3 (s) + H 2 O (l) The partial pressure of CO 2 is 0.800 kPa and the temperature is 296 K. (5 marks) Vf = 2.4 x 10 5 x 273 K / 296 K x 0.800 kPa / 101 kPa =1.8 x 10 3 L 1.8 x 10 3 L x 1 mol / 22.4 L = 80.3571428571 = 80.4 mol CO 2 80.4 mol CO 2 x 2 mol LiOH / 1 mol CO 2 = 160.8 mol LiOH 1 mol LiOH = 6.94 g + 16.00 g + 1.008 g = 23.948 g 160.8 mol LiOH x 23.948 g / 1 mol = 3850.8384 = 3.9 x 10 4 g 2. In the reaction: 2C 8 H 18 (l) + 25O 2 (g)  16CO 2 (g) + 18H 2 O (g) How many grams of water would be produced if 20 L of oxygen were burned at a temperature of -10.0 °C and pressure 131.7 kPa? (5 marks) Vf = 20 L x 273 K / 263 K x 131.7 kPa / 101 kPa = 27.0708127847 = 27.1L 27.1 L x 1 mol / 22.4 L = 1.2098214286 = 1.21 mol O 2 1.21 mol O 2 x 18 mol H 2 O / 25 mol O 2 = 0.8712 mol H 2 O I mol H 2 O = (2 x 1.008g) + 16.00g = 18.016 g 0.8712 mol H 2 O x 18.016 g / 1 mol = 15.6955392 = 15.7 g H 2 O Submission Instructions Submit your assignment using the drop box on the Assignment page for this unit. Remember to include references. 1