Extension Science Quiz

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Deakin University *

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111

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Chemistry

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Jan 9, 2024

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Uploaded by BrigadierArmadilloPerson929

Extension Work for Yr 9 Chemistry: Relative Atomic Mass-Using different isotopes of elements. Below is a link above is to my very first ever video of: ‘Chara’s steps to use for finding the Relative Atomic Mass of Chlorine. This video was recorded at the time of the first lockdown R.L. for 2020. It was for my yr 11 VCE Chemistry students. I am sharing this with you, in case you wish to try some extension work for finding the relative atomic mass calculations. Watch the video and try the calculations below. Just a note: In the video, I mention that the calculation has units a.m.u. Ignore that statement. We do not need the units for RAM-as it is simply a measure of the mass of an element compared with that of carbon- 12 isotope. Check the answers to see if you get the correct answer ? !!!! Watch the video CHR has made for this extension Video Details https://screencast-o-matic.com/watch/cYfDfPzqtC CHR_RAM_Cl QUESTIONS Questions to try-I have taken them out of the current Yr 11 Textbook ? !!!!! Q1: Use the data in Table 4.2 to calculate the relative atomic mass of: (a) Oxygen R AM ( O ) = ( 15.995 × 99.76 ) + ( 16.999 × 0.04 ) +( 17.999 × 0.2 ) 100 RAM ( O ) = 1599.94096 100 RAM ( O ) = 15.999

(b) Silver R AM ( Ag ) = ( 106.9 × 51.8 ) + ( 108.9 × 48.2 ) 100 RAM ( Ag ) = 10786.4 100 RAM ( Ag ) = 108 (c) Hydrogen R AM ( H ) = ( 1.008 × 99.986 ) + ( 2.014 × 0.014 ) +( 3.016 × 0.0001 ) 100 RAM ( H ) = 100.81 100 R AM ( H )= 1.008 Read the information below to help you with question 2.

Question: Q2. If chlorine has 2 isotopes, chlorine 35 and 37 are the 2 isotopes for chlorine. One peak is approximately three times the height of the other peak. Draw a mass spectrum of chlorine. Ensure you have correctly labelled the axes and include a title for your graph. Mass Spectrum of Chlorine 100 80 60 40 20 Abundance (%) 32 34 35 36 37 38 39 Relative Isotopic Mass

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Question:3 (question 21 in the answers below) (a) Determine the relative atomic masses of argon and potassium Argon R AM ( Ar ) = ( 35.978 × 0.307 ) + ( 37.974 × 0.06 ) + ( 39.974 × 99.633 ) 100 R AM ( Ar ) = 3996.05 100 RAM ( Ar ) = 39.96 Potassium R AM ( K ) = ( 38.975 × 93.3 ) + ( 39.976 × 0.011 ) + ( 40.974 × 6.69 ) 100 R AM ( K ) = 3910.923 100 RAM ( K ) = 39.11 (b) Explain why the relative atomic mass of argon is greater than that of potassium, even though potassium has a larger atomic number.

ANSWERS Question 1: Question 2.

Answer for question 3 (or 21-as it is labelled in the textbook) REFLECTION Take some time to write some dot points about learning this new yr 11 level work  I was able to process about half the information  The formulas and calculations for finding the relative atomic mass were fairly straightforward  However, the theory regarding it was relatively difficult to understand without assistance

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Moving Forward Are you ready for another extension session? Tell CHR to teach you more-when you next see her in class.

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