Lab conservation of energy

STARTING AMOUNT esc C X C 2 F2 W # 3 1000 F3 ADD FACTOR x( ) $ 4 1 97.9 FS de in % 5 2 Convert 23.4 kJ to calories 2.34 x 104 t 4184 kcal 6 P 0.001 J 4.184 COMEC DOLL ANSWER & 7 9.79 × 104 cal 00 8 RESET FO 2 23.4 ( 5590 A FIT 120 Jan 21 del +

< 10:44 Question 6/8 5GW (10 Submit A cake recipe calls for 230.0 mL of buttermilk. How 230.0 many cups is this? DAL STARTING AMOUNT × 1 cups 230.0 mL x = 0.9722 cups 230.0 mL ADD FACTOR DELETE (( ) = 1 cups 230.0 DAE ANSWER RESET ១ 9.722 × 105 0.8706 cups 8.706 × 104 1 L 8.706 × 105 0.9722 quart 10 100 mL 0.001 0.1 6.076 × 103 0.01 9.722 × 104 230.0 0.06076 4 1.0567 1000 6.076 × 104 Tap here for additional resources

The percentage of an additive in gasoline was measured six times with the following results: 0.13, 0.12, 0.16, 0.17, 0.20, and 0.11%. Find the 95% confidence interval for the percentage of additive.

100- 8 8 Relative Intensity $ 20- 0- Relative Intensity 10 200- 80- 40- 20- 0- 10 20 30 m/z 20 20 100 $10 Chlorine OR Bromine OR Neither Chlorine OR Bromine OR Neither 90 100 100- Relative Intensity DO- ģ 20- 0 100 80 10 8 Relative Intensity 3 0- 10 40 30 60 15 m/z Chlorine OR Bromine OR Neither 35 40 45 m/z weytekakumpumakija 30 100 110 55 Chlorine OR Bromine OR Neither

2 Automobile air bags inflate following a serious impact. The impact triggers the following chemical reaction. 2NaN3 (8)→ 2 Na(s) + 3N₂ (9) S W stry.com/myct/itemView?assignmentProblemID=213377858&attemptNo=2&offset=next X 7 # 3 E D 80 C $ 4 R 888 F V % 5 FS T Y G A Part A 6 B If an automobile air bag has a volume of 11.2 L, what mass of NaN3 (in g) is required to fully inflate the air bag upon impact? Assume STP conditions. IVE ΑΣΦ Provide Feedback m = Submit MacBook Air F6 Y H & 7 Request Answer N 40 U J * 8 @ C PwC FB I M ( 9 K DD ? O ) O g L command 3 F10 P . : ; Review I Constants I Periodic Table I { + [ option = 11 ? 1 I 323) Next > 1 delete

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1-10. The table shows fuel efficiency for several automobiles CO2 emission (g CO2/km) Fuel consumption (L/100 km) Car model Gasoline engine 4.6 109 Peugeot 107 266 Audi Cabriolet 11.1 346 Chevrolet Tahoe 14.6 Diesel engine Peugeot 107 4.1 109 8.4 223 Audi Cabriolet SOURCE: M. T Oliver-Hoyo and G. Pinto, "Using the Relationship Between Vehicle Fuel Con sumption and CO2 Emissions to Illustrate Chemical Principles," J. Chem. Ed. 2008, 85, 218. (a) A mile is 5 280 feet and a foot is 12 inches. Use Table 1-4 to find how many miles are in 1 km. (b) The gasoline-engine Peugeot 107 consumes 4.6 L of fuel per 100 km. Express the fuel efficiency in miles per gallon. A U.S. liquid gallon is 3.785 4 L (c) The diesel Cabriolet is more efficient than the gasoline Cabriolet. How many metric tons of CO2 are produced by the diesel and gaso- line Cabriolets in 15 000 miles of driving? A metric ton is 1 000 kg.

26) The floor tiles in SE 27 are about 1 square foot and the lab is about 25 tiles wide and about 36 tiles from front to back. When the emergency shower was demonstrated, in 10. seconds the water in the trash can was about 1 foot deep. One student estimated this was 2.5 gallons. Estimate how deep the room will get in inches after a 15 minute shower. List 3 simplifving assumptions you make in this calculation rea L-36 Tile fiDw ill it cost2 The density of gold is 27l An artist plans to apply gold leaf to a painting with an area of 2.32 f? and a thickness of 1.50

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Please answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466

For each problem, you must: 1) Calculate the degree of unsaturation. -1 2) Assign the principal IR absorption bands above 1500 cm 3) Draw the structure of the compound 4) Label the protons on your structure with letters and assign them to peaks on the NMR spectrum (see the example below). 4.0 C 2H 3.5 3.0 2.5 D 1H 3.0 This peak is a magnified version of this peak A 2.8 2.0 1H B zum 2.6 B 2H Each problem contains the formula of the compound, the IR spectrum (with axes in cm³¹ vs. % transmission), and the ¹H NMR spectrum (with axis in PPM shift). Some NMR spectra show a peak hovering above the baseline. This is a magnified view of one of the actual peaks, to allow you to see splitting more clearly. 1.5 2.4 OHD A 3H 1.0 PPM 0.5

please answer in correlation to the boxes

The percentage of an additive in gasoline was measured six times with the following results: 0.13; 0.12; 0.16; 0.17; 0.20 and 0.11%. What is the 99% confidence interval for the additive percentage?

9:08 PM ☹ & = ikf MB² = 5.12 °C/m 19²2- (-130%) = AT £ 1Jf=18492 ug°c = (5.12 L/m) n = 3.611 ●●● 25 Question 9 of 14 | g 1 3 4 6 7 9 +/- 0 Tap here or pull up for additional resources 8 What mass in grams of NaCl would need to be added to 2051 g of water to increase the boiling temperature of the solution by 1.500 °C? (Kb for water is 0.5100 °C/m) X C 20% 0 Submit x 100

For Q6. I am uncertain on how 20.49 is the answer because I thought we’d use the figure with least sig figs which is 1 sig fig in this problem. I’m confused on why it’s 4 sig figs in the answer.

O University of Tampa - Prod - My x Bb Assignments - Introductory Cher x 101 Chem101 b My Questions | bartleby Ô https://app.101edu.co Not syncing Question 2 of 10 Submit The average adult human burns 2.00 x 10° kcal per day in energy. What is this rate in kJ per hour ? STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) 1 4184 349 1000 0.001 1.15 x 105 4.184 60 2.00 x 10° 2.01 x 10° 24 20.0 J cal kJ min kcal/day kcal hr 9:26 PM P Type here to search a A O G E D 4) 10 5/4/2021

Given the following data, calculate the 95% confidence interval. 0.452    0.453    0.448    0.456    0.458 Average = 0.4534 St. Dev. = 0.003847 1) 0.453 ± 0.004 2) 0.453 ± 0.005 3) 0.4534 ± 0.0048 4) 0.4534 ± 0.0037 5) 0.4534 ± 0.0038