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University of Ottawa *

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2130

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Chemistry

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Oct 30, 2023

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1

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A tank of 2 m? volume contains saturated ammonia at a temperature of 40°C. Initially the tank contains 50% liquid and 50% vapor by volume. Vapor is withdrawn from the top of the tank until the temperature is 10°C. Assuming that only vapor (i.e., no liquid) leaves and that the process is adiabatic, calculate the mass of ammonia that is withdrawn. Control volume: Tank. Initial state: Ty, Vig, Vyap; state fixed. Final state: T»,. Exit state: Saturated vapor (temperature changing). Process: Transient. Model: Ammonia tables. Analysis In the energy equation, Eq. 4.21, we note that OQcv. = 0, Wcy. = 0,and m; = 0, and we assume that changes in kinetic and potential energy are negligible. However, the enthalpy of saturated vapor varies with temperature, and therefore we cannot simply assume that the enthalpy of the vapor leaving the tank remains constant. However, we note that at 40°C, hy = 1470.2 kJ/kg and at 10°C, h, = 1452.0 kJ/kg. Since the change in 4, during this process is small, we may accurately assume that 4, is the average of the two values given above. Therefore, (h.),, = 1461.1kJ/kg and the energy equation reduces to mouy miuy = —meh, and the continuity equation (from Eq. 4.20) becomes (my —mi)cy, = —m, Combining these two equations, we have my(he uz) = mh, myu; o ieti BT O
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