LAB#1

docx

School

CUNY LaGuardia Community College *

*We aren’t endorsed by this school

Course

201

Subject

Chemistry

Date

Feb 20, 2024

Type

docx

Pages

2

Uploaded by ColonelJellyfish2871

Report
Lab#1: Measurements and Significant Figures In Lab #1, I learned to measure the density of water by using the formula of density which is D(density)=M(mass)/V(Volume). It is important to pay attention to the units when measuring mass and volume. Additionally, we learned about the significance of figures in a measurement and how to determine the appropriate number of digits to express in a calculation based on these figures. We focused on two particularly important concepts in measurement: accuracy and precision. Accuracy refers to how close a measurement is to the true value and for precision which measures consistency between individual measurements. And then I used Excel to do graphing to visually represent relationships between variables. To conduct my experiment accurately in my lab manual. The experiment is divided into two parts, Part A focuses on measuring the density of water and Part B deals with measuring the accuracy and precision of volumetric devices. In Part A, I needed a clean and dry 50mL graduated cylinder and an analytical balance. Firstly, I measured the empty graduated cylinder and then added water up to 9mL. Next, I used a dropper to add water until it reached the 10mL mark and then weighed it again to determine the mass of the water and the graduated cylinder. I repeated this process for the 30mL and 50mL marks. Part B, I poured about 10mL of water into a 150mL beaker to measure the temperature using a thermometer. Next, I obtained a clean dry 50mL beaker and weighed it empty to determine its mass. Then, I used a graduated cylinder to measure 10mL of water and poured it into the 50mL beaker to determine its mass. I repeated this process two more times to get three values. The goal for Lab #1 was to measure the density of water accurately and precisely and compare the measured value with the true value.
Sample of the calculation 29.1812g - 19.8295g = 9.3517g 49.0974g - 19.8295g = 29.2679g 68.8686g - 19.8295g = 49.0391g D = M/V D = M/V D = M/V = 9.3517g/10.0mL = 29.2679g/30.0mL = 49.0391g/30.0mL = 0.93517g/mL =0.975596667g/mL = 0.980782g/mL Temperature 24c 10.2059+9.8361+10.2775/3 = 10.1056 9.8007+9.8598+9.7967/3 = 9.819066667 997.2994kg 0.997 10.2059 - 10.1056 = 0.1003 9.8007- 9.819066667= 0.01836 9.8361 - 10.1056 = 0.2695 9.8598- 9.819066667=0.04073 10.2775 - 10.1056 = 0.1719 9.7967- 9.819066667= 0.05236 0.1003+0.2695+0.1719/3= 0.18056 0.01836+0.04073+0.05236/3= 0.03715
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help