Lab 5_ Field Trip and Data Analysis for Oakland Upper Air Radiosonde Launches
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Salvatore Vallejo
April 18, 2023
EPS/CHEM 182
Lab 5: Field Trip and Data Analysis for Oakland Upper Air Radiosonde Launches
Part 1: Field Trip Write-up [For Spring 2023: Part 1 is eliminated.]
Part 2: Predicting where a radiosonde may land
Radiosondes use various computer systems and data analytics to measure atmospheric
properties such as humidity, pressure, temperature, wind speed , and direction at various
conditions. Radiosondes are attached to weather balloons that are launched into the atmosphere
to collect data about the atmospheric conditions.
Radiosondes consists of three components: a sensor package, a radio transmitter, and a
power source. The sensor package has built in sensors to measure atmospheric variables, and the
radio transmitter sends the collected data back to a ground station. The power source is a source
of power and it provides energy to run the sensors and the transmitter. Radiosondes are launched
twice daily, covering many different terrains. Data from radiosondes creates a vertical profile of
the atmosphere which is important for weather forecasting and climate research.
We used
stratoflights
trajectory over Oakland International Airport to conduct radiosonde
data analysis. Parameters: launch site = Oakland International Airport, Flight Info: Helium,
parachute = TA200, Totex parachute = 0.94 m; payload weight (0.4 kg =235 g of radiosonde plus
associated line, train regulator, and parachute); nozzle life = 1.5 kg, default settings.
Figure 1
. Trajectory simulation at Oakland Airport. Prediction made on April 4, 2023 for a
launch at 4:00 PM PDT on April 6, 2023 estimated that the launch altitude occurred at 100 m
and ascended and descended at a right of 5 m/s in a south east direction landing near Newman
county in San Francisco. Flight duration lasted 2 hours and 47 minutes for a 118 km distance
traveled.
Part 3: Radiosonde Data Analysis
We conducted two trajectory launches on 2023-03-16-00Z (4 pm PDT launch 3/15/23
California time) and 2023-04-06-00Z (4 pm PDT launch 4/05/23 California time). Figure 2
shows that the temperature profiles from each launch are similar. On March 16, 2023, the ground
temperature was 14 ºC at the time of launch, and the weather conditions were sunny with clear
skies and a wind speed of S 10 mph. On April 6, 2023, the ground temperature was 12.8 ºC at the
time of launch, and weather conditions were cloudy and a wind speed of S 11 mph. Although the
temperature profiles are similar, there is a difference in relative humidity profiles because the
weather conditions were different. April 6, 2023 has a greater disparity in relative humidity than
March 16, 2023.
Figure 2.
Temperature Comparison for March 16, 2023 and April 6, 2023. Overall trends show
similar temperature values across both dates.
3.1 Variation of Temperature and Relative Humidity with Altitude
Weather.uwyo.edu was used to construct and analyze data for the variation of temperature
and relative humidity with altitude from March 16, 2023 and April 6, 2023.
Set up included: Select "region=north america", "type of plot=text:list", "year=2023",
"month=mar", and set date "from=16/00Z" and "to=16/00Z" for March 16th (06/00Z for April
6). "OAK" on the map was clicked with a site code of # 72493.
Data was copied and imported to Excel for data analysis. Boering et al. describes the
process of transferring data to Excel in the lab manual. Excel graphs were generated by plotting
the altitude on the y-axis and temperature and relative humidity on the x-axis. Tropopause, 1976
Temperature, Typical Cruise altitude were also included.
Figure 3
. March 16, 2023 Altitude vs Temperature and Relative Humidity graph. Blue line is a
graph of temperature (x-axis) vs altitude (y-axis). Orange line is a graph of relative humidity
(x-axis) vs altitude (y-axis). Grey line is a graph of 1976 Temperature (x-axis) vs altitude
(y-axis). Yellow line is a graph of Typical Cruise Altitude (x-axis) vs altitude (y-axis). Skyblue
line is a graph of tropopause (x-axis) vs altitude (y-axis).
Figure 4.
April 6, 2023 altitude vs temperature and relative humidity graph. Blue line is a graph
of temperature (x-axis) vs altitude (y-axis). Orange line is a graph of relative humidity (x-axis) vs
altitude (y-axis). Grey line is a graph of 1976 Temperature (x-axis) vs altitude (y-axis). Yellow
line is a graph of Typical Cruise Altitude (x-axis) vs altitude (y-axis). Skyblue line is a graph of
tropopause (x-axis) vs altitude (y-axis).
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a.) Comment on the general trends in temperature and relative humidity as a function of altitude
for the two flights and their likely causes.
Temperature is the measure of average kinetic energy of particles in a certain space. From
figure 3 and figure 4 we see that the overall trend of temperature is similar. Temperature
decreases with an increase of altitude in the troposphere, but increases as altitude increases in the
stratosphere. Our troposphere houses the storms, clouds, precipitation, where planes fly, and
accounts for almost 80% of the mass of the entire atmosphere. This is due to what is actually
happening in the atmosphere. There is rapid vertical convection in the troposphere. This is
because cold and heavy air is found above warm and light air. There is also slow vertical mixing
in the stratosphere, where warm and light air is more present at the top of the stratosphere.
Temperature near the surface is higher because the earth's surface is heated by the sun. Other
reasons are due to the greenhouse gas effects such as CO2, water vapor and other gasses which
traps outgoing infrared radiation resulting in a heated surface affecting temperature. Figure 3 and
figure 4 also support the observance, from the surface to the troposphere the temperature
decreases and it stalls at the tropopause where it increases in the stratosphere due to the ozone
layer absorbing solar heat. Relative humidity is the ratio of the amount of water vapor in the air
to the amount of water vapor the air can hold at a particular temperature and pressure. Relative
humidity decreases with an increase in altitude because the atmosphere becomes less dense, and
colder air can hold less moisture (pressure is lower at higher altitudes). Gravity plays a role in
tightly holding air molecules at lower altitudes. As a result, the capacity for air at higher altitude
to hold water is lower.
b.) If there are large fluctuations in relative humidity in either of the flights, what might be the
reason?
There are no large fluctuations in relative humidity on March 16, 2023. However, there
are large fluctuations in relative humidity for April 6, 2023. There could be a number of reasons
for the fluctuations. March 16, 2023 had sunny conditions, whereas April 6, 2023 had cloudy
conditions. There could also be rapid vertical mixing in the troposphere. If we were to have the
launch during the winter or summer we can see a change in relative humidity. For example,
during summer, oceans release more water vapor during warmer months. We can also take a look
at the dew point temperature. The dew point temperature is generally highest near earth’s surface
and tends to decrease with increasing altitude in the stratosphere. We see a lot of variation in the
dew point in the troposphere. Note that there is a continuous water cycle incorporating the
condensation and evaporation of water with the addition of clouds in our troposphere. Our
troposphere houses the storms, clouds, precipitation, where planes fly, and accounts for almost
80% of the mass of the entire atmosphere.
c.) Use the US Standard Atmosphere 1976 temperature profile data for midlatitudes from the
excel file on bCourses and include these data on each of the 2 plots for the 2 flights. These data
represent an annually-averaged "typical" temperature profile for midlatitudes. Compare and
contrast the US Standard Atmosphere Profile with the actual profiles. Speculate (as a
"non-meteorologist") on what might cause differences between the profiles we observed and a
"typical" one.
Note: The US Standard Atmosphere 1976 temperature profile data for midlatitudes
consists of annually averaged measurements meaning that the temperatures from each season are
included in the measurements. The temperature profiles for March 16, 2023 and April 6, 2023
have more fluctuations, similar tropospheric temperatures, but lower stratospheric temperatures
than the US Standard Atmosphere 1976 temperature profile. Having an increase of variability on
March 16, 2023 and April 6, 2023 compared to the US Standard Atmosphere 1976 data is
expected because the data is not an average. The stratospheric temperatures are lower for March
16, 2023 and April 6, 2023 than in 1976 because of the thinning of the ozone layer( heats the
stratosphere). The increase/effects of greenhouse gas emissions in the stratosphere depletes the
ozone layer. This causes a decrease in stratospheric temperatures and an increase in tropospheric
temperature. Other possible explanations can be due to local geography since the measurements
were taken at mid latitudes For example, a region near the ocean may have a different
temperature profile than a region located inland. Other factors can be climate patterns, natural
climate oscillations, such as El Niño or low/high pressure systems.
d.) Determine the altitude of the WMO-defined tropopause (given below) for each of the two
flights you are analyzing (Note: there might be more than one tropopause for a given flight!) and
mark it on your plots. It will be helpful for you to plot up the definitions given below along with
the flight data in order to compare slopes (i.e., the lapse rates, −dT/dz).
●
Lapse rate is defined as –dT/dz.
●
The first tropopause (i.e., the conventional tropopause) is defined as the lowest level at which
the lapse rate decreases to 2 K/km or less, and the average lapse rate from this level to any
level within the next higher 2 km does not exceed 2 K/km.
●
If above the first tropopause the average lapse rate between any level and all higher levels
within 1 km exceeds 3 K/km, then a second tropopause is defined by the same criterion as
under the statement above. This tropopause may be either within or above the 1 km layer.
●
A level otherwise satisfying the definition of tropopause, but occurring at an altitude below that
of the 500 mbar level will not be designated a tropopause unless it is the only level satisfying
the destination and the average lapse rate fails to exceed 3 K/km over at least 1 km in a layer.
We used excel to calculate the lapse rate for the data. Tropopause was found at 10,100 meters on
March 16, 2023 and 10,550 meters on April 6, 2023. No second tropopause was found. There
was no average lapse rate between any level above the first tropopause and all higher levels
within 1 km exceeded 3 K/km.
Excel was used to calculate the lapse rate for all the data. A trendline was added.
e.) Also plot on your figures the cruise altitude of a typical commercial passenger jet (~35,000 ft
or 10,600 m). Is there concern over whether or not jets spend a lot of time above or below the
tropopause? Why or why not?
A typical commercial passenger jet spends its time in the troposphere, upper
tropopause, and lower stratosphere (tropopause height changes with the different
seasons). There is concern over whether or not jets spend a lot of time above or below
the tropopause, because 10% of the ozone layer is found in the tropopause and 90% of
the ozone layer is found in the stratosphere. Air in the stratosphere does not circulate as
much as it does compared to the troposphere because of slower vertical mixing. The
release of chemicals like nox and greenhouse gasses in the stratosphere remain in the
stratosphere for longer periods of time and has a greater impact on ozone layer
depletion than the release of nox and greenhouse gasses in the troposphere.
3.2 Variation of Pressure with Altitude
To measure the variation of pressure with altitude we took various equations to answer
the questions listed below.
Because a planet’s atmosphere is in the planet’s gravitational field, its density will fall with
altitude. Since vertical motion is generally very small, the assumption of static equilibrium is a
good starting point. If
𝝆
is the density and
p
the pressure at altitude
z
measured vertically
upwards from the surface, we have
dp(z) = –
𝝆
(z)gdz
(1)
(Hydrostatic equation)
where
g
is the acceleration due to gravity at Earth’s surface (9.807 ms
–2
).
From the equation of state for an ideal gas of molecular weight M
r
(28.97 g mol
–1
for “air”) and
temperature T:
𝝆
= M
r
p/RT
(2)
(Ideal gas law)
where R is the gas constant (8.314 J mol
–1
K
–1
).
Equation
(1)
can be rearranged to give
dp(z)/p(z) = –dz/H(z)
which on integration gives, for the pressure
p
at altitude
z
:
p(z) = p(0)exp{
(dz/H(z))}
(3)
−
0
𝑧
∫
where p
0
is the pressure at z = 0 and H(z)=RT(z)/M
r
g, known as the “scale height,” is the
increase in altitude necessary to reduce the pressure by a factor
e
. For the lower atmosphere of
earth H varies between 6 km at T = 210 K to 8.5 km at T = 290 K.
The temperature in the atmosphere varies by less than a factor of 2, while the pressure changes
by six orders of magnitude. If the temperature can be taken to be approximately constant, just to
obtain a simple approximate expression for p(z), then the pressure decrease with height is
approximately exponential:
p(z) = p
0
exp{–z/H}
(4)
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a.) For each of the two flights, plot measured pressure from the radiosonde data (x-axis) versus
altitude.
Figure 5.
March 16, 2023 altitude vs pressure graph. Blue line is radiosonde pressure (x-axis) vs
altitude (y-axis). Orange line is pressure changing with H (x-axis) vs altitude (y-axis). Grey line
pressure with constant H (x-axis) vs altitude (y-axis). Yellow line is 1976 pressure (x-axis) vs
altitude (y-axis).
Figure 6
. April, 2023 altitude vs pressure graph. Blue line is radiosonde pressure (x-axis) vs
altitude (y-axis). Orange line is pressure with constant H (x-axis) vs altitude (y-axis). Grey line
pressure changing with H (x-axis) vs altitude (y-axis). Yellow line is 1976 pressure (x-axis) vs
altitude (y-axis).
b.) Predict the pressure profile by using equation
(4)
above assuming that H is constant and equal
to 8 km [Be sure to check units and do dimensional analysis!]. How well does
(4)
predict the
measured pressure? Where is the largest discrepancy and what is its cause?
We use equation 4 and substitute various values into the variables to calculate the
pressure. An example calculation is done below.
(4)
𝑃 = 𝑃
0
× 𝑒
−𝑧/𝐻
Assuming H = 8 km = 8000 m:
03-16-23:
𝑃 = 1000 × 𝑒
−𝑧/8000
𝑃 = 1001 × 𝑒
−3/8000
𝑃
=
997 ℎ𝑃𝑎
04-06-23:
𝑃 = 1000 × 𝑒
−𝑧/8000
𝑃 = 1000 × 𝑒
−27/8000
𝑃
=
996 ℎ𝑃𝑎
The equation predicts the measured pressure well at low altitudes and high pressures.
However, at higher altitude and lower pressure there is some variation. At higher altitudes,
temperature and scale height are not constant (as assumed in equation 4). The scale height is not
uniform since the altitude required to decrease pressure by a factor of e rises at higher altitudes.
The curve predicted by equation
(4)
with constant H is shifted upwards compared to the other
curves at lower pressures and higher altitudes because the equation assumes H and temperature
to be constant at all altitudes. At the highest altitudes, the temperature approaches the conditions
of equation
(4)
. We see a closer relationship between the curves.
c.) Now use equation
(4)
to predict the pressure as a function of altitude again, but this time let
H
vary as a function of measured
T
. Where is the largest discrepancy and what is its cause? [Hint:
compare equations (3) and (4).]
We use equation 4 and substitute various values into the variables to calculate the
pressure. An example calculation is done below:
𝐻(𝑧) = 𝑅𝑇(𝑧)/𝑀
𝑟
𝑔 = [8. 314 × (𝑇(𝑧) + 273)]/(. 02897 × 9. 807)
𝐻(𝑧) = 𝑅𝑇(𝑧)/𝑀
𝑟
𝑔 = [8. 314 × (285. 95)]/(. 02897 × 9. 807)
𝐻(𝑧) = 𝑅𝑇(𝑧)/𝑀
𝑟
𝑔
=
8364 𝑚
03-16-23:
𝑃 = 1000 × 𝑒
−𝑧/[(8.314×(𝑇(𝑧)+273))/(.02897×9.807)]
03-16-23:
𝑃 = 1000 × 𝑒
[−3/8364]
03-16-23:
𝑃
=
999 ℎ𝑃𝑎
𝐻(𝑧) = 𝑅𝑇(𝑧)/𝑀
𝑟
𝑔 = [8. 314 × (𝑇(𝑧) + 273)]/(. 02897 × 9. 807)
𝐻(𝑧) = 𝑅𝑇(𝑧)/𝑀
𝑟
𝑔 = [8. 314 × (287. 15)]/(. 02897 × 9. 807)
𝐻(𝑧) = 𝑅𝑇(𝑧)/𝑀
𝑟
𝑔
=
8400 𝑚
04-06-23:
𝑃 = 1000 × 𝑒
−𝑧/[(8.314×(𝑇(𝑧)+273))/(.02897×9.807)]
04-06-23:
𝑃 = 1000 × 𝑒
[−3/8400]
04-06-23:
𝑃
=
999 ℎ𝑃𝑎
The curve predicted by equation
(4)
when H varies as a function of measured T is shifted
down from the other pressure vs. altitude curves at low pressure and high altitudes.
Mathematically equation
(3)
is more accurate because equation
(4)
assumes a constant H.
Equation
(3)
calculates the integral of change of altitude over H. It depends on the calculation of
H(z)=RT(z)/M
r
g. We assume that H is constant from equation
(3)
to equation
(4)
. In reality H
depends on H(z)=RT(z)/M
r
g. The discrepancy happens at higher altitudes, we get lower H values
because H decreases at higher altitudes (the calculated pressure values are lower compared to the
pressure values for the other curves). Note: At the highest altitude and lowest pressure values,
curves are similar because the temperature is relatively the same.
d.) Now add the US Standard Atmosphere pressure versus altitude data. Is there much difference
between the US Standard Atmosphere pressure profile and between the two pressure profiles for
the two flights you’ve analyzed? Why do you think this is the case? [If you need a hint, skim the
(former) website by M.J. Majoney, who used to measure vertical temperature profiles from
aircrafts. (See bCourses for the content from the old website in a pdf document.)]
The US Standard Atmosphere pressure versus altitude data aligns closely with the two
pressure profiles for the two flights analyzed. Intuitively, pressure does not have much variability
like conditions explained in previous parts. Pressure is essentially the weight of the air in the
atmosphere. Pressure does not change throughout seasons or other effects like temperature.
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- from 4 to 6 please thank youarrow_forwardi)16O and 18O are two different isotopes of oxygen. What is ONE IS TRUE about 18O? it less easily evaporated than 16O it is more volatile and reactive than 16O it is lighter than 16O it is more commonly occurring than 16O II) Ice core samples taken from Antarctica have been used to estimate changes in surface temperatures and the atmospheric concentrations of carbon dioxide and methane. This data indicates that when the temperature is relatively warm, the amounts of carbon dioxide and methane are ___________ Select one: relatively low (negative correlation) sometimes high, sometimes low (no correlation) relatively high (positive correlation) III) The answer to the previous above question indicates that ___________ . Select one: high atmospheric concentrations of carbon dioxide and methane might lead to warmer temperatures high atmospheric concentrations of carbon dioxide and methane might lead to cooler temperatures there is no…arrow_forwardChapter #3, Question #13: Consider the following data for total atmospheric column ozone measurements (as DU) at three locations around the Earth, obtained using the TOMS in 2001. January 15 april 15 july 15 october 15 Tierra del fuego (Chilie, argentina) 323 261 339 206 Nairobi (Kenya) 234 273 266 (Aug. 15) 266 Kiev (Ukraine) 321 420 314 273 Assume that these are typical of values that might be obtained in any other year, and discuss the trends as you move down the columns and along the rows, in terms of your knowledge of stratospheric ozone behavior.arrow_forward
- A friend of yours has seen each of the following items innewspaper articles and would like an explanation: (a)acid rain, (b) greenhouse gas, (c) photochemical smog,(d) ozone depletion. Give a brief explanation of each term andidentify one or two of the chemicals associated with each.arrow_forward5cd_i-5c7IV_IVquz8U4U02epq7z4kBnpYZ5iA/edit & nsions Help EB Ga... estions: 1 2 11 + BIU Key Words: global warming et 3 1. Why is oxygen NOT a greenhouse gas? A 4 > DOE-E X-E greenhouse gas 6 infrared energy 3. The atmosphere on the planet Venus is almost 96 % carbon dioxide. What effect might its concentration of carbon dioxide have on the average surface temperature on Venus? is not a greenhouse gas because it is transparent to infrared light. and greenhouse gasses absorb oxygen infrared radiations. meaning it can not absorb heat. 2. Why is the effect of greenhouse gases in the atmosphere similar to the effect of glass surrounding a greenhouse? Page 3: The Structure of Greenhouse Gases Questions 4. What effect does an increase in the atmospheric carbon dioxide levels (and therefore rising temperatures) have on the amount of water vapor in the atmosphere? Why? 3 7 I 5. Both coal and natural gas can be burned to generate electricity. However, burning natural gas produces about half the…arrow_forwardWhat percent of the chlorine sources are natural?What percent are manufactured compounds?arrow_forward
- Without naturally occurring greenhouse gases, Earth's average global temperature would be near 0°F (or -18°C) instead of the actual value of 59°F (15°C). How do atmospheric greenhouse gases warm Earth? Do not use the word “trapped” in your answerarrow_forwardSuppose you have an 8-hour ozone value of 0.088 ppm, and a PM2.5 value of 35.7 ug/m3. The AQI value is Blank 1 and the responsible pollutant is Blank 2. According to the AQI scale, this falls under the category Blank 3. Note: for the pollutant, choose between ozone and PM2.5 These Breakpoints.. .equal this AQI .and this category Air Quality Index Levels of Health Concern Numerical Value O3 PM25 PM10 CO SO2 NO2 AQI (ppm) 1-hour (H8/m) (H8/m²) (ppm) 8-hour (ppm) (ppb) (ppb) 8-hour 24-hour 24-hour 1-hour 1-hour Good 0 to 50 0.0 - 4.4 0- 53 0- 50 0.000 - 0.054 0.0- 12.0 0- 54 0- 35 Good Moderate 51 to 100 55 - 154 54 - 100 0.055 - 0.070 12.1 - 4.5 - 9.4 36 - 75 51 - 100 Moderate 35.4 Unhealthy for Sensitive Groups 101 to 150 0.125 - 155 - 254 9.5 - 12.4 76 - 185 101 - 360 101 - 150 Unhealthy for Sensitive Groups 0.071 - 35.5 - 0.085 0.164 55.4 0.086 - 0.165 - 255 - 354 361 -649 151 - 200 Unhealthy 151 to 200 (55.5 - 150.4) (186 - 304)* 12.5 - Unhealthy 0.105 0.204 15.4 Very Unhealthy 201…arrow_forwardExperiment 4: Preparation and Properties of Hydrogen and Oxygen Gases Toriana Mieer -Jones Name: Section: Lab Instructor: L/26 Date: Pre-Lab Exercise 4 1. In this experiment, simple chemical reactions are used to generate small quantities of hydrogen and oxygen gases. These methods would be too expensive and too complicated if large quantities of these gases were needed, however. Use your textbook, a chemical encyclopedia, or an online source to look up the major industrial methods of preparing very large quantities of these gases. Summarize your findings here. ono od te led bateono to narrow_forward
- Mind Tap - Cengage Learning X om/ilrn/takeAssignment/takeCovalent Activity.do?locator=assignment-take me teaching and le X [Review Topics] [References] Use the References to access important values if needed for this question. An 1.11 mol sample of nitrogen gas at a temperature of 10.0°C is found to occupy a volume of 27.5 liters. The pressure of this gas sample is atm. Submit Answer 888 F4 + A FS Retry Entire Group 8 more group attempts remaining Cengage Learning Cengage Technical Support MacBook Air VA DII DD Previousarrow_forwardCFCs are family of compounds containing the elements carbon, fluorine and chlorine. Which of the following statements is NOT true about CFCs? a. Ozone is attacked by chlorine atom that breaks free from the CFC molecule b. CFCs were to be found in aerosol sprays and refrigerants c. CFCs can remain in the atmosphere from up to 100 years d. Each CFC molecule destroys a single ozone moleculearrow_forward7. You can see an MSDS below. Please answer the following questions related to the MSDS. a) What is the name of this chemical? b) What should you do if someone drinks the chemical? c) Would this chemical catch on fire if it was exposed to flames? d) If this chemical gets in your eye what should you do? e) What color is this chemical? f) What should you do if someone spills a small amount of the chemical?arrow_forward
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