_Module One Lesson Four Assignment -
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Module 1 Lesson 4 Mastery Assignment – Phase Diagram Analysis
Honors Chemistry NCVPS
Use the diagram below to answer the questions that follow. Please answer the questions in a different
colored font. Submit your completed document in the course.
1. What state of matter is represented by the area surrounding the letter A?
The solid state of matter is being represented.
2. What state of matter is represented by the area surrounding the letter B?
The liquid state of matter is represented.
3. What state of matter is represented by the area surrounding the letter C?
The gas state of matter is being represented.
4. Locate the triple point. Explain what is happening at that data point.
What is happening at the triple point is all three phases of a substance—solid, liquid, and
gas—meet and coexist in balance.
5. Locate the critical point. Explain what is happening at that data point.
What is happening at the critical point is a substance reaches a certain temperature and
pressure where it can no longer be distinguished from either a liquid or a gas.
6. Describe the phase change (example: boiling, melting, condensation, deposition, freezing or
sublimation) as the substance moves from …
a. Region A to Region B -
melting
b. Region A to Region C -
sublimation
c.
Region B to Region A -
freezing
d. Region B to Region C -
boiling
e. Region C to Region B -
condensation
f.
Region C to Region A -
deposition
7. How does increasing the pressure affect the temperature required for this substance to
boil
?
Increasing the pressure raises the temperature required for a substance to boil.
8.
True
or False
At higher temperatures,
deposition
is less likely.
9. Estimate the
normal melting point
and
normal boiling point
of this substance.
around melting - 30
°C
and boiling around
50
°C
10. If at the triple point the temperature is 30 degrees Celsius and the pressure is 0.75 atm, in
what state of matter would the substance
most likely
be at 20 degrees Celsius and 1.5 atm?
It would be a solid
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Related Questions
Part B
The seventh ionization energy of manganese.
Express your answer as a chemical equation. Identify all of the phases in your answer.
ΑΣφ
OA chemical reaction does not occur for this question.
Submit
Request Answer
< Return to Assignment
Provide Feedback
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B.
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Unlimited tries
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Edit
View Insert
Format Tools
Table
12pt v
Paragraph v
|BIUAv
D2
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After a dye diffuses uniformly throughout a glass of
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they become evenly distributed.
Select one:
True
False
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5
MODEL#3: Understanding How SFs Propagate in Calculations.
C. 4.0000 cm²
136.8 mm
C. 3800. g
f. 1.70×104 g/cm³
a. Calculate the volume (length x width x height) in units of mm³ (mm × mm x mm) for the
large eraser shown below. Report your answer to as many digits as your calculator displays.
254.7 mm
fufc
25.3 mm
Jef
b. Estimated uncertainties in measurements are at least ±1 value in last reported digit.
Estimate the new volume if each of the above measurements were 0.1 mm larger (136.9 mm
x 254.8 mm x 25.4 mm).
2
c. Starting from the left, which digit is the 1st digit in the answers from a & b that differ? If you
report all the values that agree plus the 1st value where the answers disagree, how many SFs
should you report?
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8
Hello Tutor,
i need help with this problem.
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PHOTOSYNTHETIC PIGMENTS
1.6
0.7
1.4
Qy
CH
0.6
1.2
Soret
0.5
1
H
0.4
0.8
0.3
COOCH
0.6
phytyl bacteriochlorophyll a
0.2
0.4
Qx
0.1
0.2
300
400
500
600
700
800
700 750 800 850 900
2 (nm)
2 (nm)
Figure 4.7 Absorption (left) and fluorescence (right) spectra of bacteriochlorophyll a in diethyl ether
5. Look at this figure from Blankenship's book, Molecular Mechanisms of Photosynthesis.
You can see the structure for bacteriochlorophyll a, along with its absorption spectrum.
a. What is the molecular shape around the labeled carbon atom?
b. What is the hybridization around that same carbon?
c. Based on this structure, would you expect this molecule to absorb light in the
visible spectrum? Why or why not?
Absorbance
Fluorescence (Arbitrary units)
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Station 2: Density column
In the graduated cylinder, you have molasses, water (blue), corn oil, and ethanol (red). They
have the following densities:
Substance
Molasses
Water
Corn Oil
Ethanol
Density
1.45 g/mL
1.0 g/mL
0.92 g/mL
0.79 g/mL
Polarity
Polar
Polar
Nonpolar
Polar
Viscosity
High
Low
Low
Low
1. Explain why the column is arranged in the order it is according to density.
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at eq
2+ x. 2 + x. -2 x
We get x= 1. Therefore
k = 4. Please help us.
Questin 9. See conditions from 8
This is not a graded question as it is a practice question . I am 60 years old and helping my son prepare for the AP exam in a few months. We do questions at the back of the textbook by Zumdahl and Zumdahl
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Sound light feelings and ideas
are not consider to be matter which of the following best explains
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Calculate delta H for the graph below. y = -59.88x -1.6547
Pen
-1.84
188003100032
-1.85
-1.805
-1.86
-1.005
-1.87
1875
Ink vs 1/T
0.0033 0.0034 0.0035 0.0036 00037
ya-59 885x-1,6547
R² -0.9000
1/T (10)
N
What is the concentration of Magnesium in 20mL of water if 35mL of 0.1M EDTA is
used to titrate?
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3
E
D
20
F3
[Review Topics]
[References]
Use the References to access important values if needed for th
a. When 52.70 and 44.375 are divided, the answer should be based on 4
Enter the answer with the correct number of digits.
52.70 44.375= 1.188
An error has been détected in your answer. Check for typos,
miscalculations etc. before submitting your answer.
C
b. When 44.375 is subtracted from 52.70, the answer should be based on 2 decimal place(s).
Enter the answer with the correct number of digits.
52.70 44.375= 8.32
Submit Answer
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Answer questions on both images
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Hello sir, I have an exam in English, please be the solution to the text of the keyboard.
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Spot in R
lane
Spot in Y
lane
Upper
spot in U
lane
Distance
traveled by
spot (cm)
Lower
spot in U
lane
3.00
Spot in B 5.00
lane
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2.90
Solvent Rf
front
(cm)
5.90
5.90
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5.90
5.90
Based on your TLC, which best describes
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B)Plastic
C)Glass or Quartz
D)Any of them
E) Quartz.
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A direct enzyme-linked immunosorbent assay (ELISA) test on a patient's sample is shown below. Development of a strong (dark) color reaction would indicate:
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complementary antigen
binds to antibody.
3 Enzyme-linked antibody specific 4 Enzyme's substrate () is added,
for test antigen is added and binds and reaction produces a product
that causes a visible color change (O).
to antigen, forming sandwich.
A low concentration of a specific antigen in the patient's sample
O A high concentration of a specific enzyme in the patient's sample
The patient's antibody is specific for the enzyme's substrate
O A high concentration of a specific antigen in the patient's sample
A high concentration of a specific antibody (against the test antigen) in the patient's sample
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