Actice learning discussion 2
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As a secondary chemistry teacher, techniques of active learning will be important to include
as the students will be more engaged and will satisfy their need for peer acceptance. In this
assignment I will discuss how this can be done while also considering the challenges in
meeting the motivational desires of the secondary student. I will also analyze the following:
"Active learning doesn't just happen" (ViewSonic, 2019, para. 9) and provide an example to
illustrate.
Through active learning strategies such as think-pair-share and concept mapping, students’
attention is captured and enhance peer acceptance. The think-pair-share involves students
thinking about an issue by themselves, later followed by peer discussions and then an
exchange of ideas with the whole class. This will promote learning among the students in
class as they collaborate and have their ideas confirmed by their peers, a need for
acceptance (Seifert & Sutton, 2018).
Concept mapping, on the other hand, promotes critical thinking and problem-solving. While
the students work in groups to develop concept maps, they are not only being actively
engaged in the content, but they are also learning from one another. This collaborative
feature motivates the students as they realize the importance of peer input (Karageorgakis,
2019).
However, it is still difficult to meet the motivational needs of the secondary students. One
challenge is the diversity of learning preferences and motivations in any class. A few of the
students may be very extrinsically motivated because of their being liked by their peers, and
a few may be intrinsically motivated because of their liking for the subject. Such balancing is
very delicate to be carried out by the teachers.
In fact, proper execution of active-learning strategies would also require sufficient planning
and actual implementation. Thinking of these strategies and just considering them in the
curriculum without preparing well enough may not even lead to success. Active learning
does not just happen; it is an intentional scheme that must take place in line with learning
targets (ViewSonic, 2019).
For example, in chemistry class, I might use the concept mapping technique to explore the
periodic table. I would assign small groups of students the task of creating a concept map
that links various elements, their properties, and their uses. Each group would then present
their map to the class. This activity not only promotes active engagement but also allows
students to appreciate the diverse perspectives and ideas presented by their peers, fulfilling
their need for acceptance.
Overall, active-learning strategies such as think-pair-share and concept mapping can
effectively engage secondary students in the classroom, while also satisfying the need for
peer acceptance. However, the challenges of adequately satisfying the wide range of
motivational needs and interests of students must be recognized. As the ViewSonic article
addresses, active learning demands an active approach to curriculum planning and
implementation. It is by carefully designing and implementing active-learning activities that
the teacher can build a stimulating and inclusive classroom climate that benefits all
students.
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Related Questions
General Chemistry 4th Edition
McQuarrie • Rock • Gallogly
University Science Books
presented by Macmillan Learning
A critical reaction in the production of energy to do work or drive chemical reactions in biological systems is the hydrolysis of
adenosine triphosphate, ATP, to adenosine diphosphate, ADP, as described by the reaction
АТР(аq) + H,О() — ADP(aq) + HРО (аq)
ADP(aq) + HPO, (aq)
for which AG;ixn
= -30.5 kJ/mol at 37.0 °C and pH 7.0. Calculate the value of AGrxn in a biological cell in which
[ATP] = 5.0 mM, [ADP] = 0.10 mM, and [HPO;-] = 5.0 mM.
kJ/mol
rxn
Is the hydrolysis of ATP spontaneous under these conditions?
О yes
no
Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemsitry | Publisher: University Science Books
?
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[References]
Cobra venom helps the snake secure food by binding to acetylcholine receptors on the diaphragm of a bite victim, leading to the loss of function of the
diaphragm muscle tissue and eventually death. In order to develop more potent antivenins, scientists have studied what happens to the toxin once it has
bound the acetylcholine receptors. They have found that the toxin is released from the receptor in a process that can be described by the rate law
Rate
k[acetylcholine receptor-toxin complex]
If the activation energy of this reaction at 37.0°C is 26.2 kJ/mol and A= 0.850 s', what is the rate of reaction if you have a 0.400-M solution of
S
receptor-toxin complex at 37.0°C?
(Enter your answer to two significant figures.)
Rate
mol/L s
Submit Answer
Try Another Version
10 item attempts remaining
12:45 PM
arch
12/6/2021
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The disassociation of barium hydroxide in water is an exothermic process. Which of the following statements is correct?
Group of answer choices
The potential energy of solid barium hydroxide plus pure water is less than that of the disassociated solution.
The potential energy of solid barium hydroxide plus pure water is greater than that of the disassociated solution.
The potential energy of solid barium hydroxide plus pure water is the same as the disassociated solution.
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Please help me with my he. I can't seem to solve this problem. I hope you can help me
This is a guide to answer the activity.
HESS LAW (Law of Heat Summation)
“The enthalpy change of the overall process is the sum of the enthalpy changes of the individual component steps.”
- It is the standard enthalpy of Reaction, ΔHᵒ.
- It can be illustrated in the following example
Consider the following reactions:
(a) Fe(s) + O2(g) à FeO(s)ΔHᵒ = -272 kJ
(b) 2 Fe(s) + O2 (g) à Fe2O3(s)ΔHᵒ = -82.5 kJ
1. Make sure to write the balance equation.
2. The final equation requires 2 moles of FeO which means we will multiply equation (a) and its enthalpy change by 2.
3. Reverse equation (a), which means, the product goes to the reactant side,
(2) (FeO(s) à Fe(s) + O2(g))ΔHᵒ = (-272 kJ)(2) = 544 kJ
2 FeO(s) à 2 Fe(s) + O2(g))ΔHᵒ = -825.5 kJ
4. Combine the final equation (a) and the initial equation (b). And then cancel the same components with same number of particles. In this…
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How would you solve c?
Transcribed Image Text:Temperature (°C) AN A student conducts an experiment to determine the value of for the dissolution of Na₂C₂H₂O₂ (s). The student dissolves 10.0 g of Na₂C₂H₂O₂ (s) in room-temperature water in a beaker and measures the temperature over time. The data are given in the graph above. 24- 22- 20 18 16 14 12- 10 Time (a) The student touches the side of the beaker after the dissolution has occurred and observes that it is cold. What experimental evidence is consistent with the student's observation? (b) Is the dissolution of endothermic or exothermic? Justify your answer in terms of the flow of energy between the system and surroundings. in kJ/mol. (c) The student calculated the energy change for the dissolution to be 4600 J. Based on this value, calculate AH soln
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Non-Commercial Substances
Hypothesis: Soluble in
Test
Bond
Molecular Structure
ΔΕΝ
H2O?
Result: H20 Solubility
Result: Hexane
Substance
Classification
Solubility
Hexane?
H2O: pS
Sodium
Na--Br
lonic
Bromide
1.9
Hexane: I
|--|
lodine
NP C
0.0
Ammonium
N/A
lonic
Carbonate
NH4* O
O NH4*
Sodium
N/A
lonic
Acetate
C--H
NP C
0.4
H-C-OH
C--O
PC
H-C-OH
Glycerol
1.0
H-C-OH
O--H
PC
1.4
HI
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Pessoas
Home Page | The Q
Guia
Janela Ajuda
101 Chem101
←→ C仑
A app.101edu.co
4 Answer in General Chemistry fo X
C4 Sat 15:24 Q
: Apps M Gmail
YouTube
四 Maps
Traduzir
GE Notícias
Atualizar :
Question 10 of 15
Consider the Haber-Bosch process for the synthesis of ammonia from its elements.
Submit
Calculate the theoretical yield in moles NH3 from the complete reaction of 15.6
grams H2 in the presence of excess N2 gas according to the following balanced
chemical equation:
N2(g) +
3
H2(g) →
2 NH3(g)
STARTING AMOUNT
ADD FACTOR
ANSWER
RESET
* ( )
%3D
15.6
5.15
197
2.57
0.306
11.6
28.02
10.3
17.04
1.01
7.72
87.7
0.918
0.612
2.02
14.01
1
mol H2
g/mol H2
g H2
g/mol NH3
g NH3
mol NH3
W
PAGE
APR 1
286
17
MacBook Air
F12
!!
关
....
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-4
The solubility of Co(OH), in water at 25 °C is measured to be 6.4 x 10
Use this information to calculate K,, for
L
Co(OH),.
Round your answer to 2 significant digits.
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1. Which, if any of the following, constitute a closed system?(a) A sealed container in which a chemical reaction occurs.(b) A dog.(c) An open beaker in the lab, in which a reaction occurs.(d) A mixture of gases inside a sealed impenetrable balloon.
2. What is the definition of an isolated system? How could you approximate anisolated system in the lab?
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3
eq
req
For the reaction
N₂ (9)+ 3H2(g) → 2NH3 (9)
AH = -92.2 kJ and AS = -199 J/K
The equilibrium constant for this reaction at 256.0 K is
Assume that AH and AS are independent of temperature.
Submit Answer
$
R
References to access important values if needed for this question.
Retry Entire Group 9 more group attempts remaining
Show Hint
Cengage Learning | Cengage Technical Support
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Aktiv Chemistry
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Hess's law can be used to solve for reaction enthalpy changes because enthalpy
is a
function.
► 11
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B) state
C) thermodynamic
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D) pressure-volume
Question 8 of 12
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Help me solve this problem
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The overall reaction energy (gibbs enegy) is negative
How could you explain the favorability of the reaction in terms of enthalphy and entrophy?
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NUMBER 3 ONLY (other two posted separately!)
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The results of your Solubility of a Salt experiment led to the following linear regression equation:
ln(s)= -4197(1/T)+ 17.96
What is the heat of solution, ΔH, in kJ/mol?
a.
25
b.
35
c.
45
d.
55
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Please help !!
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3. For the following reactions, ldentify the unknown, the ?, and circle the change for each of the
energy systems. Changes in the Strong Energy Interaction are determined by the net amount of
bounds broken or formed and changes in the Electric Energy are determined by the separation
of like charges.
i. 6429Cu → 6428NI + ? + V
a. The unknown "?" is
b. PEelectric: increases, decreases, no change
c. PEstrong: increases, decreases, no change
d. Energy: Exothermic
e. Mass: increases, decreases, no change
ii. 189F + ? → 1830 + v
a. The unknown "?" is
b. PEelectric: increases, decreases, no change
c. PEstrong: increases, decreases, no change
d. Energy: Exothermic
e. Mass: increases, decreases, no change
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A bicyclist is stopped at the entrance to a valley, as sketched below:
F
B
Where would the bicyclist have the highest potential energy?
|(choose one)
Where would the bicyclist have the lowest potenti
energy?
(choose one) v
Where would the bicyclist have the highest kinetic energy?
(choose one) ♥
Where would the bicyclist have the highest speed?
|(choose one) v
Would the bicyclist's kinetic energy be higher at A or B?
|(choose one)
Would the bicyclist's potential energy be higher at A or B?
(choose one)
Would the bicyclist's total energy be higher at A or B?
(choose one)
Suppose the bicyclist lets off the brakes and coasts down into
the valley without pedaling. Even if there is no friction or air
resistance to slow him down, what is the farthest point the
bicyclist could reach without pedaling?
(choose one) ▼
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Please don't provide handwritten solution ....
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The symbol A,G has a delta sign in it so something must be changing. What is changing and what is constant?
Changing
Constant
No Answers Chosen
No Answers Chosen
Possible answers
I temperature
total pressure
chemical structure (reactants to products)
| composition (e.g.concentration, partial pressures)
::::
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- General Chemistry 4th Edition McQuarrie • Rock • Gallogly University Science Books presented by Macmillan Learning A critical reaction in the production of energy to do work or drive chemical reactions in biological systems is the hydrolysis of adenosine triphosphate, ATP, to adenosine diphosphate, ADP, as described by the reaction АТР(аq) + H,О() — ADP(aq) + HРО (аq) ADP(aq) + HPO, (aq) for which AG;ixn = -30.5 kJ/mol at 37.0 °C and pH 7.0. Calculate the value of AGrxn in a biological cell in which [ATP] = 5.0 mM, [ADP] = 0.10 mM, and [HPO;-] = 5.0 mM. kJ/mol rxn Is the hydrolysis of ATP spontaneous under these conditions? О yes no Question Source: McQuarrie, Rock, And Gallogly 4e - General Chemsitry | Publisher: University Science Books ?arrow_forward[References] Cobra venom helps the snake secure food by binding to acetylcholine receptors on the diaphragm of a bite victim, leading to the loss of function of the diaphragm muscle tissue and eventually death. In order to develop more potent antivenins, scientists have studied what happens to the toxin once it has bound the acetylcholine receptors. They have found that the toxin is released from the receptor in a process that can be described by the rate law Rate k[acetylcholine receptor-toxin complex] If the activation energy of this reaction at 37.0°C is 26.2 kJ/mol and A= 0.850 s', what is the rate of reaction if you have a 0.400-M solution of S receptor-toxin complex at 37.0°C? (Enter your answer to two significant figures.) Rate mol/L s Submit Answer Try Another Version 10 item attempts remaining 12:45 PM arch 12/6/2021arrow_forwardThe disassociation of barium hydroxide in water is an exothermic process. Which of the following statements is correct? Group of answer choices The potential energy of solid barium hydroxide plus pure water is less than that of the disassociated solution. The potential energy of solid barium hydroxide plus pure water is greater than that of the disassociated solution. The potential energy of solid barium hydroxide plus pure water is the same as the disassociated solution.arrow_forward
- Please help me with my he. I can't seem to solve this problem. I hope you can help me This is a guide to answer the activity. HESS LAW (Law of Heat Summation) “The enthalpy change of the overall process is the sum of the enthalpy changes of the individual component steps.” - It is the standard enthalpy of Reaction, ΔHᵒ. - It can be illustrated in the following example Consider the following reactions: (a) Fe(s) + O2(g) à FeO(s)ΔHᵒ = -272 kJ (b) 2 Fe(s) + O2 (g) à Fe2O3(s)ΔHᵒ = -82.5 kJ 1. Make sure to write the balance equation. 2. The final equation requires 2 moles of FeO which means we will multiply equation (a) and its enthalpy change by 2. 3. Reverse equation (a), which means, the product goes to the reactant side, (2) (FeO(s) à Fe(s) + O2(g))ΔHᵒ = (-272 kJ)(2) = 544 kJ 2 FeO(s) à 2 Fe(s) + O2(g))ΔHᵒ = -825.5 kJ 4. Combine the final equation (a) and the initial equation (b). And then cancel the same components with same number of particles. In this…arrow_forwardHow would you solve c? Transcribed Image Text:Temperature (°C) AN A student conducts an experiment to determine the value of for the dissolution of Na₂C₂H₂O₂ (s). The student dissolves 10.0 g of Na₂C₂H₂O₂ (s) in room-temperature water in a beaker and measures the temperature over time. The data are given in the graph above. 24- 22- 20 18 16 14 12- 10 Time (a) The student touches the side of the beaker after the dissolution has occurred and observes that it is cold. What experimental evidence is consistent with the student's observation? (b) Is the dissolution of endothermic or exothermic? Justify your answer in terms of the flow of energy between the system and surroundings. in kJ/mol. (c) The student calculated the energy change for the dissolution to be 4600 J. Based on this value, calculate AH solnarrow_forwardNon-Commercial Substances Hypothesis: Soluble in Test Bond Molecular Structure ΔΕΝ H2O? Result: H20 Solubility Result: Hexane Substance Classification Solubility Hexane? H2O: pS Sodium Na--Br lonic Bromide 1.9 Hexane: I |--| lodine NP C 0.0 Ammonium N/A lonic Carbonate NH4* O O NH4* Sodium N/A lonic Acetate C--H NP C 0.4 H-C-OH C--O PC H-C-OH Glycerol 1.0 H-C-OH O--H PC 1.4 HIarrow_forward
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