CM156-Midterm II-Winter 2021-final KEY
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CM156
Subject
Biology
Date
Dec 6, 2023
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1
CM156/256 Midterm Exam I (February 22, 2021)
1.
Please indicate your TA and Discussion section
(1 point)
:
Aileen Nava:
1A
1B
1C
Kevyn Hart:
1D
1E
1F
EACH MIDTERM QUESTION IS WORTH
3 POINTS
2.
You are counseling the 20-year-old son and 22-year-old daughter of a man who developed
Huntington Disease at 54 years of age. You tell them that:
i)
The son is at higher risk of the inheriting disease than the daughter
ii)
The daughter is at higher risk of inheriting the disease than the son
iii)
If they inherited the mutation, the son will develop the disease earlier than the
daughter
iv)
If they inherited the mutation, the daughter will develop the disease earlier than the
son
v)
If they inherited the mutation, the age of onset will likely be earlier than the
father
The principle here is that HD alleles expand upon paternal transmission, leading to the strong
possibility that there will be an earlier age of onset among the offspring who inherit the
mutation from an HD father.
3.
Fragile X syndrome is an X-linked disorder that results from lack of expression of the FMR1
gene. Unaffected parents have a daughter with Fragile X syndrome. This could be explained by:
i)
Inheritance of a premutation from her father.
ii)
Expansion of a premutation inherited from her carrier mother.
iii)
Skewed inactivation of the daughter’s Fragile X mutant allele.
iv)
Skewed inactivation of the daughter’s normal allele.
v)
A new mutation in FMR1
The principle here is that although there is maternal expansion of the FMR1 trinucleotide
repeat, because FMR1 is subject to X-inactivation, an inherited mutation in a daughter is not
expected to result in Fragile X syndrome unless there is skewed inactivation of the normal
allele, leading to reduced FMR1 expression. There was a slide in class that showed this, noting
that in rare cases there can be mild Fragile X in such daughters but not the full Fragile X
syndrome. This question was exploring understanding of that topic.
4.
A man with a heteroplasmic mitochondrial disorder has a son and a daughter. Which of the
following is true?
i)
The daughter is at risk for the disorder but the son is not
ii)
The son is at risk for the daughter but the daughter is not
iii)
The risk to each child depends on the level of heteroplasmy in the father
iv)
The children are not at risk for the disorder
v)
Both children will inherit the disorder
The principle here is that mitochondria are not transmitted to the offspring of males.
5.
You are counseling a woman with a mitochondrial disease who is homoplasmic for the
causal mutation. You can tell her:
2
i)
Her offspring will be at reduced risk due to purifying selection during oocyte
maturation
ii)
Her offspring are at unknown risk for the disease
iii)
Her offspring will be homoplasmic for the mutation and affected
iv)
Her offspring will be heteroplasmic for the mutation and may or may not be affected
v)
Since the father is unaffected, there will be reduced risk among her offspring
The principle here is that there is exclusively maternal transmission of mitochondria and that
when a woman is homoplasmic, the only mitochondria she can transmit will have the
mutation so that her offspring would be predicted to be homoplasmic and therefore affected.
6.
The UBE3A gene associated with Angelman syndrome is paternally imprinted. A boy has
unaffected parents and a brother and sister with Angelman syndrome. What is his risk of having a
child with the disorder?
i)
100%
ii)
50%
iii)
25%
iv)
0
v)
Unable to tell with certainty
The principle here is that with two unaffected siblings, the only way the boy will not be
affected is if he inherited the normal allele from his heterozygous parent. Consequently, his
children are not at risk for the disease. His heterozygous parent is unaffected because the
mutant allele is imprinted and therefore not expressed but the other allele is expressed,
leading to an unaffected phenotype.
7.
Shown below is part of Fig 2A from Carrette et al. (paper #5) on X chromosome
reactivation.
Which of the following statements is
NOT
accurate?
i)
The difference between the red and black curves is due to the addition of 5-aza-
2”
-
deoxycytidine (Aza)
ii)
The large fold change in expression between 0-0.25 and 0.75-1.0 cumulative fraction
is due to natural and experimental variation
iii)
The p-value is for the significance of the shift between black and red lines
iv)
The shift is dependent on the absence of Xist expression
v)
None of the genes on the X chromosomes is activated more than 1.3-fold
8.
What was the purpose of using the hybrid fibroblast line which contained the
Mus musculus
and
Mus casteneus
strain
used to produce the data above from the Carrette et al. paper (paper #5)?
3
i)
Using two mouse strains instead of just one gives the experiment more confidence
that the Xist ASO + Aza is increasing gene expression from genes on the Xi
ii)
Mus casteneus
X chromosome genes are expressed at higher levels than those from
Mus musculus
, thus increasing Xi gene reactivation
iii)
Mus casteneus
X chromosome genes are expressed at lower levels than those from
Mus musculus
, thus increasing Xi gene reactivation
iv)
It enabled the researchers to determine if the RNA-seq reads mapped to the Xa
or the Xi chromosome
v)
Mus casteneus
have reduced levels of
Xist
expression as compared to
Mus musculus
9.
The children of first cousins are at increased risk of autosomal recessive disorders because
of:
i)
Higher mutation rates in cousins
ii)
Reduced genetic diversity
iii)
Identity by descent
iv)
Higher heterozygosity
v)
Lower homozygosity
The principle here is that in inbred families there is a higher frequency of recessively
inherited disorders because of inheritance of the mutant allele identical by descent, meaning
that the affected individual is homozygous for the mutation transmitted from an ancestor
down both sides of the pedigree. None of the other answers explain the question.
10.
Individuals with the karyotype below have developmental abnormalities and reduced life
expectancy. A potential contributing factor(s) is:
i)
Failure of X chromosome inactivation
ii)
Imprinting of genes on the X chromosome
iii)
Abnormal dosage of genes that typically escape X chromosome inactivation
iv)
Both failure of X chromosome inactivation and imprinting of genes on the X
chromosome
v)
Both imprinting of genes on the X chromosome and abnormal dosage of genes
that typically escape X chromosome inactivation
The principle here is that XO individuals have abnormal sex chromosome dosage. This leads
to abnormalities through multiple mechanisms. Compared to an XX individual, these
individuals will have reduced expression levels of genes present on a second X chromosome
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4
that escape X inactivation AND will inherit an X chromosome with either maternal or
paternal imprints, but will not have both. This will lead to abnormal gene expression levels of
genes that are imprinted. ‘Failure of X chromosome inactivation’ will not be a concern.
11.
The genetic basis for differences in phenotypes between a typical man and woman include
all
EXCEPT
:
i)
Differential expression levels of autosomal genes
ii)
Differences in the number of Barr bodies in every cell
iii)
The presence only in women of
Xist
gene expression
iv)
Differential expression levels of genes in the pseudoautosomal region of sex
chromosomes
v)
Differential expression levels of several genes that function in gene transcription,
splicing, and translation
There are two correct answers to this question, as expression of autosomal genes and
differential expression of a few pseudoautosomal genes may differ between male and female
cells. Either answer is accepted.
12.
The following are
TRUE
of genetic variation in the human genome
EXCEPT
:
i)
Simple sequence repeats are highly variable due to errors in replication
ii)
Linkage disequilibrium is extensive in regions undergoing selective sweep
iii)
Common variations are a major cause of common diseases
iv)
Most genetic variations occurred after modern humans migrated out of Africa
v)
The “Regional Hypothesis” that modern humans evolved separately in various parts
of the world, predicts greater variation between populations than the “Out of Africa”
hypothesis
As discussed in the lecture on population genetics, the vast majority of genetic variation
occurred early in the origin of modern humans when the human population was small,
perhaps in the hundreds or thousands. Moreover, all ethnic groups share about 90% of the
total variation, and this would not be the case if the variations arose after the migration.
13.
At linkage equilibrium, what is the frequency of the haplotype SNP1, allele 2
–
SNP2, allele
2
–
SNP3, allele1, given the below frequencies?
SNP
Frequency
Allele 1
Frequency
Allele 2
1
75%
25%
2
80%
20%
3
60%
40%
i)
0.03
ii)
0.06
iii)
0.09
iv)
0.012
v)
None of these choices
The principle here is that even at linkage equilibrium, there are haplotypes on each
chromosome. For the haplotype described in the question, the answer is (.25)(.20)(.6)=.03
5
14.
Two genetic markers, A and B, reside about 10 kb apart on human Chr. 3.
They each have
two alleles:
A
1
and A
2
, and B
1
and B
2
.
What are the likely haplotypes at the Chr. 3 locus that are carried by individual I-1?
i)
A
1
B
1
and A
2
B
2
ii)
A
1
B
2
and A
1
B
1
iii)
A
1
B
2
, and A
2
B
1
iv)
A
2
B
1
and A
1
B
1
v)
None of these choices
The idea here is that the two markers are only 10kb apart so it can be assumed that
recombination between them will not occur. The haplotype of I-1 can be derived by looking at
the genotypes of his offspring. Since II-2 is homozygous for markers A1 and B2, the father
must have this haplotype on one allele. Given his genotype, the other haplotype must then be
A2B1. Originally the question was stuck under the Fig. We apologize. This was corrected and
student questions were answered during the exam.
15.
A deletion mutation of the chemokine receptor 5 (CCR5D32) confers resistance to HIV, and
individuals carrying the mutation share the same haplotype of the CCR5D32 gene.
This suggests
that:
i)
The mutation exhibits a “gain of function”
ii)
The mutation has been under strong positive selection
iii)
The mutation occurred only once in history
iv)
The mutation is most likely recessive
v)
The mutation is an example of a triplet repeat disease
The idea here is that independent occurrence of the same mutation would be most likely to
have occurred on a different haplotype (and also would have been under positive selection).
Since there is only a single haplotype, the most parsimonious answer is that the mutation
occurred only once.
II-1
II-2
I-1
I-2
Genotype:
A
1
A
2
B
1
B
2
A
1
A
1
B
1
B
2
A
1
A
1
B
1
B
2
A
1
A
1
B
2
B
2
6
16.
The Finnish population exhibits less genetic diversity, as judged by SNP genotyping, than
most other European populations.
What is the most likely explanation?
i)
Population bottleneck
ii)
Selection
iii)
Random drift
iv)
Violation of Hardy-Weinberg
v)
Ethnic admixture
This question tests the idea that Finland was founded by a small number of people, restricting
the genetic diversity in the population (and leading to increased frequency of a set of recessive
disorders due to ancestral identity by descent).
17.
In 1918, R.A. Fisher proposed a model to explain continuously inherited, or quantitative,
traits such as height and blood pressure.
His model:
i)
Assumes that the traits are determined by additive Mendelian factors
ii)
Postulates nonadditive interactions
iii)
Assumes that environment plays an important role
iv)
Is based on the fact that standard deviations due to environment and genetics are
additive
v)
None of these choices
18.
In an association study for an autoimmune disease, 300 patients and 300 controls are studied
for a SNP in a candidate gene.
The results are presented in Table I.
What is the odds ratio for the
disorder?
Risk Allele
+
-
Patients
250
50
Controls
200
100
i)
1.5
ii)
2.0
iii)
2.5
iv)
3.0
v)
None of these choices
19.
For most disorders, large numbers of subjects are required for genome-wide association
studies because:
i)
Heritability of common disease tends to be very low
ii)
Ethnic admixture is a great problem
iii)
Individual loci have very modest impacts on disease
iv)
Linkage disequilibrium is extensive
v)
In any one population, most SNPs are uninformative
Some students felt that ethnic admixture was an appropriate answer. Ethnic admixture can
complicate analyses, but that is not the main reason why large populations are required. This
was addressed in the GWAS lecture.
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7
20.
For the following two questions (#20-21) refer to the figure below. Your GWAS analysis for
plasma cholesterol levels identified the lead SNP shown below in red.
The following are likely to be true
EXCEPT
:
i)
The lead SNP is not present within a protein coding region
ii)
Dozens of genetic loci are associated with cholesterol levels, suggesting that this
locus likely contributes a small effect
iii)
An examination of linkage disequilibrium may help identify candidates for the causal
variant
iv)
Chromatin Conformation Capture may help identify whether histone marks
near the variant suggest a role in gene regulation
v)
Reporter gene assays may help determine if the causal variant has regulatory activity
A GWAS was performed for a complex trait, cholesterol levels, and identified a lead SNP that
lies outside of protein coding regions. The figure also shows that the genotype influences
expression levels of several genes. Therefore answers i, ii, iii, and v are all true. Answer iv is
not true, because Chromatin Conformation Capture is a technique that identifies regions of
chromosomes that interact; it does not inform about histone marks.
8
21.
Expression analysis in tissue samples from individuals with the genotypes indicated showed
the results in the figure above (see Question #20). The following are reasonable conclusions
EXCEPT
:
i)
The risk allele acts in a co-dominant manner to enhance gene expression
ii)
The variant affects gene expression across tissues
iii)
Likely target genes for the responsible variant are
SORT1
,
PSRC1
, and
CELSR2
iv)
The causal variant is likely to have physical interactions with multiple sites in the
region
v)
Studies in mouse models could be used to determine which gene(s) are most critical
for determining the cholesterol phenotype
The genotype is associated with expression levels of three genes (
SORT1
,
PSRC1
,
CELSR2
) in
liver, but not in adipose tissue. Therefore ii is a false statement. All other statements are true.
22.
You have identified a population that exhibits lactase persistence, but does not contain any
of the known SNPs to be associated with this trait. You decide to genotype 200 SNPs in the region
surrounding the
LCT
gene and see if any of the SNPs are correlated with the trait. Approximately
how many false positives are you willing to accept if you keep your Type I error rate (p-value)
threshold at 0.05?
i)
5
ii)
10
iii)
15
iv)
40
v)
None of these choices
23.
Below is Figure 2 from the paper from Week 6: Tishkoff
et al
. Convergent adaptation of
human lactase persistence in Africa and Europe.
Based on the genotypes and phenotypes, which of the following populations exhibit the highest
levels of lactase non-persistence?
i)
Afro-Asiatic in Kenya
ii)
Nilo-Saharan in Kenya
iii)
Afro-Asiatic in Tanzania
iv)
Sandawe in Tanzania
(
this is correct
)
v)
Nilo-Saharan in Sudan (incorrect, but mistakenly considered correct in CCLE)
9
This question was poorly worded so all answers will be considered correct.
24.
Based on the table in Fig. 2 (from Question #23), there appears to be only modest
correspondence between the genotypes and phenotypes.
Possible explanations include:
i)
Experimental variation in lactase persistence measures
ii)
Additional SNPs regulating lactase expression in cis
iii)
Environmental factors
iv)
Variations in trans-regulation by transcription factors mediating lactase expression
v)
All of these choices
25.
The researchers in Tishkoff have returned to their African DNA samples and examined an
additional variant for possible association with Lactase Persistence. Which allele appears correlated
based on the collected data in the figure below?
i)
A
ii)
C
iii)
Both A and C
iv)
There is evidence of “heterozygote advantage” at this locus
v)
Neither allele appears correlated based on the collected data
26.
Karen discussed the FTO locus that has a large impact on obesity.
The following re
properties of the locus
EXCEPT
:
i)
There were many SNPs at the peak of the locus in strong linkage disequilibrium
ii)
The peak SNPs were not in gene coding regions
iii)
The peak SNPs included a region that was regulatory as judged by epigenetic marks
iv)
The epigenetic signatures indicated that an enhancer in the locus functioned in
neurons in the brain
v)
The gene regulated by the enhancer was identified using a chromosome
conformation assay
A/C -14410
0
10
20
30
40
50
60
70
80
AA
AC
CC
LP
LIP
LNP
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10
27.
Which of the following observations would
NOT
support the “Out of Africa” hypothesis of
origin of modern humans?
i)
African populations are at the root of the phyl
ogenetic tree among the world’s
populations
ii)
European populations have a lower level of genetic diversity than Africans
iii)
Fossils of modern humans dating to over 100,000 years ago have been found in
Australia
iv)
Some populations but not others show admixture with Neanderthal DNA
v)
Modern human populations share the majority of genetic variants
As discussed in the Human History lecture, although modern humans originated about
100,000 thousand years ago, the migrations out of Africa occurred between about 70,000 and
30,000 years ago. Fossil remains in Australia dating to more than 100,000 years ago would be
in conflict with these dates. Moreover, all of the other answers are consistent with “Out of
Africa”.
28.
Iceland was populated by a founder population from Norway with the mitochondrial
haplotype “1, 2, 2, 2, 1”.
At present, there are 5 common subpopulations in addition to the ancestral
haplotype:
"1, 2, 1, 2, 1"; “1, 2, 1, 1, 1”; "1, 2, 1, 1, 2"; “2, 2, 1, 1, 2”; and “2, 1, 1, 1, 2”
.
Which
subpopulation is the more recently derived?
i)
2, 2, 1, 1, 2
ii)
1, 2, 1, 1, 1
iii)
2, 1, 1, 1, 2
iv)
1, 2, 1, 2, 1
v)
1, 2, 1, 1, 2
For this question, there was a typo in the prompt such that the derived alleles in the question
were not the same as the derived alleles in the answers. While this was corrected in real time
during the exam, not everyone had the benefit of the correction. For the derived alleles in the
original question (
1, 2, 2, 1, 1”; “1, 2, 1, 1, 1”; “2, 2, 1, 1, 2”; “1, 2, 2, 1, 1”; and “2
, 2, 1, 1, 1
”
),
the correct answer was i) 2, 2, 1, 1, 2. For the derived alleles in the answers, the correct answer
was iii) 2, 1, 1, 1, 2. Either answer will be accepted as correct. The solution to the question was
a simple comparison between the ancestral haplotype and the derived haplotypes with the
most recent derived haplotype being the one in each instance with the most changes.
11
29.
A decomposed body is found in a wall in your family mansion.
You suspect it is your
distant relative, Jack, a greedy, unpleasant fellow, according to family folklore.
Among 5 living
individuals (I-V) in the pedigree below, who would be
best
to genotype to compare to Jack’s DNA?
i)
I
ii)
II
iii)
III
iv)
IV
v)
V
The principle here is that Jack is related to individual I through his mitochondria so their
mitochondrial genotypes would be expected to be identical.
30.
Shown below is part of Fig. 2B from the Chen et al. paper (Paper #7). For the European
population, what is the width of the locus if one considers SNPs with correlation greater than 0.2
with the lead SNP?
i)
~10kb
ii)
~50 kb
iii)
~100kb
(also correct)
iv)
~200 kb
v)
~1 megabase
For this question, the resolution of the figure made it reasonable to estimate the genomic
distance between the purple dots to the left and right at either 50 or 100 kb, so either answer
is correct.
II
I
V
IV
III
JACK
12
31.
In Fig. 2B from the Chen paper (from Question #30), what is a likely explanation for why
the EAS p value is much less significant than that of EUR?
i)
Different causal gene
ii)
Independent mutation
iii)
Smaller sample size
iv)
Linkage disequilibrium
v)
Population admixture
The question asks why the p value in EAS is much less than that of Eur. This is a function of
sample size. Some students confused this with the increase in fine-mapping, which is a
function of linkage disequilibrium.
32.
A genome wide association study (GWAS) has identified the same lead SNP and associated
haplotype in the Asian and European populations. This is likely to be explained by:
i)
Convergent evolution
ii)
Similar selective pressures in the two populations
iii)
Origin of the causal variant before the two populations diverged
iv)
Independent occurrence of the causal variant in the two populations
v)
Ancestral consanguinity
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13
33.
Which of the following statements is true about Figure 3A (below) from the Chen et al.
paper (paper #7)?
i)
As the PIP increases, the proportion of likely functional variants increases
ii)
As the PIP increases, the proportion of likely functional variants decreases
iii)
As the PIP increases, the proportion of likely functional variants is similar
iv)
Causal SNPs are most likely going to be located only in the Intergenic + ATAC
category
v)
Causal SNPs are most likely going to be located in the Intronic + Missense
categories
34.
Shown below is Fig 3D from Chen et al. (paper #7) dealing with blood cell genetics. The
authors conclude that rs941616 is an eQTL for
PTGRD
. This means that:
i)
The SNP is in an enhancer of
PTGRD.
ii)
The SNP is in linkage disequilibrium with a missense variant in the
PTGRD
gene.
iii)
The SNP is associated with
PTGRD
expression.
iv)
The SNP interacts with the promoter of
PTGRD.
v)
The SNP is subject to selection.
14
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