20 Basic Genetics Exercises

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Exercis e- Basic Genetic<=. _e~HCISE - BASI C G ENETI CS E === Science, Technology. Society and E . srs . - 1 1v ,r o11rn e n1 Scl ·entific Inquiry · SI === ... T he photograph bc l1>,, . 'i hu\\-, 1 ,, 11 phnt f, . l. _ . . ·, . . ' · Ill !Ir(' ' ,; 1 111 '- I Wt 1 1·,. l'l:ifli ;\ 1 , 1 nr ·,•, lv rl i• ,cr ,ve rc cl vanet \' which 1s mul h s li~) rl~ r tlt · ui ii . , •i 1 , - ' s v 1 < type, pl.,nt H. Plant A Plant B (a) Both plant A and plant B were self-pollinated and all the offspring obtained fr om pl an t A are dwarf plants whereas those obtained from plant B are all tall. ( i) Assuming that the height of the stem in this plant species is inherited in a Mendelian manner, deduce the genotypes of plants A and B. Give one reason to support your answers. (3 mar ks) (ii) Describe an d explain how you could determine the recessive phenotype for the height of the stem. (3 mark s) 113 .~
114 . d e,e r ciseS 'ogJ' - /11/elJSfl,e No/es an . - . .... wnll n ll y gr ee n 111 colou r. O cc as io na l! . 1·, 1\· 1111 ,p c< " ' • 11 1 1 . Y, an . , hl n ic ,1 :L 'dl1n t ' nl 1 11 I · 1 . 1 . , 1 w ,1w ws a ll alb 111 0 a nd its gr ee n co <lb;" \ '\ ' 1 \l lllll" r: 11 I I ll (l . u nt er " ,n ,11 1 11 0 111'1 ' 1,,. /ll ll ll d " I r Par t: albino green r 1 1 Su gg cs t a ge ne tic ca use for the occurrence of the albino seed Ii n g. ( J mar k) (ii! As sumi ng that the inheritance of the seedling colour also follows the Mendelian pattern, ex pl ai n w hether you can use the same method you described in (a) to detennine the recess iven ess of thi s trait. ( 3 mark s) Total: 10 marks
Exercise - Basic Genetics 2 In humans. body pigmentatio . . . . . . n is co11tro ll cd h ' ., . . . pi gmentation (A) 1s dominant uvn 1 . . ) ' " 111 g lc pu,r of ;tl/clc '>. The , ill elc for normal . f I C' ,dick for alhill( J ( ; 1J Answer the questions with rci, . , ll<. ll 1.'(.' In !h e r II . I 2 3 4 5 6 8 0 ii w ,11 μ PL 'di 1!r C'1 ·· K ey: 0 nr 1rm;il in;iJ D ,d h1nr> male Q norm al female Q albino fcrml c (a) From the information given ab d d . ove, e uce the genotypes of th e par ents (incl i vidu ah I and 2 J. Explain how you arrive at . . your answer. (Genetic diagrams are not acce pt ed.) r 4 mar ks J ( b) What is the chance of a second child of the couple 6 and 7 being normal? Explain your answer with the help of a genetic diagram. ( 3 marks ) 115 -:::;:;;::} ,i J.
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Biology- !ntons,ve N otes and Exercises (c) Indi v idual 4 marri ed an albino man nnd a bab y with normal pigmentati on i . . . . . Ls I Cce nu to he r. Her husband de ni ed bein g the fath er of th e bab y. Do y ou agr ee to hi s d . ) hri ~, " .. - e n1 al an c1 \\!h ) I ( J n, c,,- k IJ -- Total: 10 mark s 3. The di stribution of blood gro u ps in a certain co un try is represented by th e bar chart below: 50 45 C 40 0 ~ 35 ~ ::I Q. 35 0 Q. .~ 25 Q) 0) 20 Cll - C Q) 15 (.) >-.. Q) 0.. 10 5 0 A 0 AB B Blood group (a) Wilh reference lo the i nfonnat ion given, state the type of variation shown by th e bl ood groups in the population. Explain your answer. ( 2 marks ) ----- - - - --- ilill.,.., .... , .... 116
Exercise - Basic Genetic (b ) A co up le. both belo . ng 111 0 to bl . ::::. ood group 13 ' . ( ') KnO\v in g that the . II ~ . . . gc1ve birth to a g ro up O g ir l. a elc tor bl . lhe ge not , .- ooci group B is I · ._ )' p es ol the couple. Expl· . . , co 111111c111l o ve r llwl l <, r grou p 0 , de du ce <llll your an swers . . - · w,tlwut us 111 g " j.!C llclic dia grnm . (4 11 wr h) ( ii) With the aid of a oenetic dia . b gram, predict th e chance of their second child havi no bl d gro up B. b oo (4 mark s) Total: IO marks ..J. Mrs . Lee g ;i vc birth Lo th ree sons in one pregnanc y. Two of them were identic al twins. The table hclmv li~ts S tl mc cha ra cteristics s hown by the three boys al the age of 10 : { 'h"rac terisfi< Ste ph en Ke nn y Edwin --- Ton~m 1 -r o/li11,: 11hilily able able unabk - ---- II lou d grotl{J 0 0 0 - - I I(! 109 106 IOX -- I --- 150 cm 14~ cm I_') I L'l ll ! I/, tght - 11 7
( a) r: mciso s 1, , ,nrl t f, . I i y ~qlc.:, lnt cn ,vu No . ' . I I ro111 i. 1 "'ng c . . pr() d11 cc < . 11 win ., ,ir i; I )c "t ',h,· \\n W ,d e ll\ t( ,1 . 1 . mation in the table prn vidt, th t . · ,, Wh at 1n or \ . I I ' ho\ 1 ", ·,re th e iu e nu c. al tWlll ~. (2 mar h , Ill) \V)\L) \\ U ; · ' ' ) L ' ' 1drn u: . . . . I ( f continuous variation? Gi ve a r ea so n ( b) Wh ich ol th e above charactens ttc s is / are examp c s) o 2 k ( mar sJ tor yo ur cho i ce,. (c) Both M r. a nd Mr s. L ee have blood group A. Based on the given information, which bl oo d g roup A or O, is th e dominant character? Explain your an swer without uc;;;ino a ~e net ic ) 0 .__, diagr am. (5 mark s) -- -- -- -- - ------------- --- - -------------- - - 118
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Exe, ,se - Ba Jc Ganet,cs ( d) II th l' cnupl L' we re tu "" c hi rt li 1 1 1 t- l l , lll t ll l l'I \ 11 1d . \~ ,, ti I \ 11 11 p1,1h.ihtl1! \ 111 1l11 , l hdd h;1\'lt1g blnod grnup o ·_ , r I 111(/d i I olol . 12 m or k , ~. /1 1ha l as s;1cm ia is an inhcriteJ Ii , A l'I- - l ., c ,:-. c - ccteJ per <., 011 ., cn nnot pr uJuu: fl(lrtrnd h,1, : 111 <,:.:lr,h1 n Thi :- di s casc is co ntrol led by a pa ir of a ll el e<; . The pedigrcr '1c lmv ..,h o w<; the inhcri1crn u.: ol 1 h1 -. di :-ca se in a fa mily: -- 2 3 4 5 9 10 l I 12 Q normal female Q diseased female nom1al male D diseased male (a) Deduce , with reasons, whether the allele for~ thalassaemia is dominant or recessive. ( Mark s will not be awarded for genetic diagrams.) ( 5 m ar ks) 119
-f Exercise s · 11 L I ,.-J\e Nole' J" L , . ·ltild. w hc1 l w1 i) e ti c chan ce or . -----:--~;n--; 0 og - 1nte - 1 . , , nnn th ct c lh ~ . " 11 1 1,1 \l ( I I , I X :I l l' b tlll lr 117ork r · du ,1h ' , irn J ( h) " ll!'\1l) '-L ll1l I\ 1 . ,, • I · 11 \, \\ 111 1• 1, 1\ 1, 11. 1 .., :.;; tl' llll ;I . l 11 l ' .- - - . 1 .- ,sion <; 011 c1 r eg ular hc.1 \i\. . ., b loo d t ran s L · " ' 11lil tl C( d l() ! 'C l'C I YC . 1 · '. ( \ ) \ · h ,, in•' I\ tha la .., s ,11.: 1 , . it bl ood t ra ns us10 11 \. / mor kJ (<'I Cl'!' , , ~ . t I w ith lr e qu e1 I t · . assoc rn CL , l , lt \1 ha z ard t w is ' "' . r' ' 11,c one \La ( I mar kJ . for thi s di se a se . I ii I S ug~e~ t one per mane nt cu 1e I d o-roup B respectiv el y. Is it p oss ib le bl d oroup AB and b oo o ( d) The co upl e 3 and 4 be long to 00 0 ( 3 mark s J d Q ? Explain your answer. that in di v idu al 10 belongs to b\oo g roup · Total: 11 marks 6. Human blood gro up s a nd respon se to colour vision are discrete characters that are inherited fr om parents to children. The following table s hows the inheritance of blood groups and colour res pon se of a family : Mr . & Mrs . Chan; their two twin daughters, Alice and Betty; and their two tw in s on s, Andy and Ja cky. Me mber of the.family Blood group Colour response Mr . Chan AB normal Mr s. Chan 0 normal A li ce B normal Be tt y B normal A nd y A no rm al Ja ck y B co lou rblind '== 1 20
Exercise - Basic Genetic (a) E.\ptiin lhc follow in g f' acls bas in g on your k no w led ge aboul !h e inhcrilancc of human blood ~rn 11 p a nd colour response. Gcnc li c diag ram s wi ll not b e.: acccr lcd. (i) The twin g irl s ha ve th e s arn c inherited d1 ,1n1clcri s li cs whcrl';, .., lh c.: I w in h oy.., do not. (4mork\J ( ii ) None of the children have the same blood group as their parents. 1 Oloul . response whereas Jacky is colourblind. ( iii) Andy has norma c (4 marks) (4 mark s) 1 21
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N t r1nd Exercises N:;~ B oitiay - Intensive o es c . . , . , nnth cr c hil d. calcul at e th e probabi li ty ()[ the ( b) If l\lr & M ,. , . Ch an '" °'' ~ ""' ~ I,, \, , 11 c ., Ill g 11 " ': birt h tu a h h,n d bni up f \. c1) 1ln11h l irnl li oy. (2 n1q, -~ - -- - (Total: J 4 mar k 1, / A I R d ' 7. ABO b lo od gro up s in hum ans are under th e co nt ro l of 3 a ll eles , , an 1: any t wo of the ,,: can occur t oge th er in an indi vidual. A baby h as bl ood group B. hi s mother has blood group -l , hi s paternal gra ndfather ha s blood group A, and hi s paternal grandmother has bl oo d group B Detem1ine the ge not ype of the baby and the po ss ible genotypes of th e bab y"s father. Use symbol , as above to s ho w ho w yo u an-i ve d at your conclusions. (6 mark s, 1 22
Exercise - Basic Geneti cs -~~~- "I Tlic pedig ree ti ell1w shows the inhe rit an ce (l j' G( 1 ") 1 ) I · . . S. . l I d 1c 1 n cy 1 11 ;1 1;1 1111 1\. 11 j .., ;1 di ..,c t1 "c cau ..,cd b) n n: ce~ s1 vc a li ck 0 11 I he X L 'hrn 111 11 ._u 11 ,~ ,. - 5 6 7 8 9 10 11 12 13 Ke y: Q norm al female D normal male Q fe male with G6 PD de fic iency D mal e w ith G6 PD deficiency (a) State the genotypes of individuals 2, 6 a nd l l . (X 0 represents the X chromosome with dominant a lJ ele while X ' represents th e X chromos om e w ith recessi ve a ll ele.) ( 3 marks) (b) What are the possible genotypes of indiv idu al 5? Wh at is th e chance that she is carrying the a ll ele fo r th e di sease? ( 2 111 arks) (c) 1f indi v id u al 8 is going to g iv e birth to a boy, what is the chance that th is boy has the d . ( I //] Cl /" I.··) 1 se as e? "' ., Total: 6 marks 123 '==-:J
--· Intensive Notes Jn<1 t.,,;:, L ,..,._ .. , 9. Bc\"ccn 1~50 a nd \8'1 3. Grc~o r Me nd el s tudi ed th e inh c ri1 , 111 cc of" numb er pc,1 pl ant,. Fnr e ach 1rai1 . he fir st cr oss -pullinat c<l pur e- br ee din g v ari c ti c, 1 1 '' 1 lr<1q 1 . . . _ ' plant, ,, , ,1n1 r ,i<l In~ charac rcf' 1,, prodilc"l ' 1h c fir st ge ne ral 1011 (i' 1 I. H c th en a 11 owed th e I' 1 1 hat . . . , 1y hrid , " 1 1 .rnd , c\1 -pnl\rnill( w 1wd11, ·c 1h c ,cco nd ,, ,,n ratmn (I ', ). 10 "r( . t- . C ' " ,, n the rL·" ul\ , for 1h c see d trait s tl1c1I Mc nJ cl ~ ,ucJi cd: - Trait\ ..;tudied Pnrc11tal characters F1 F 2 -····-- ·- S h, 1p ,' of :-.--:cd Round x Wrink led A ll round 5474 round : 185() w rin! - ~ - A ll ye ll ow 6022 ye l lo w : 200 I g r~ Cl1 h 1ur nf s;ccd Yellow X Green - (a l ln p rc-i\lendelian tim es. the Blending Theor y, w hich asserted th at in inh er it ance. par e nta l charact er s were mixed in the offsp rin g, was a widespread hypoth et ical model. H ow doc \ l hi~ result in F 1 disprove th e Blending Theory ? (2 mor ki, (b) One of the hy pothe s es propo s ed to explain the result in F 1 is as follows: ~ I ~ 1 24 Th e heredity fa c tor whic h contro ls th e " rec ess ive" character in F 1 has not pass ed to F 1 or has been destroyed during reproduction. Ba sed on the re s ult s in F 2 , explain why this hypothesis is rejected. (2 mark s) ( c) Belo w are the re s ult s of on e of Mendel's dihybrid ex perim e nt s: Trails studied Parental characters F, F2 Share and co lour Round and ye llow X All round and 315 round and ye llo w , of -;cc d Wrinkled and gr ee n ye llow IO I wrinkled and yell ow , l 08 round a nd gr ee n, 32 wr inkled and gr ee n.
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Exercise - Basic Genetics H:i sc d 1) 11 Me ndel 's laws or inherit·incc , . 1 . • h . ' · C'< p t1,n t c rcs ull 111 F 2 (5 111 ark s) . ---- ·--- - --- -- - - ( d) W hen Mendel proposed his laws of inheritance, chromosomes had not yet been discovered . Suggest how Mendel could have come up with his hypothesis. (3 ma rk s) (e) Give two limitations of Mendel's laws. (2 ,narks ) Total: 14 marks 125 -r:::JJIII' ,i,