Postion, Velocity, and Acceleration lab 1611 Edited 1.30.20
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San Antonio College *
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Course
1611
Subject
Aerospace Engineering
Date
Dec 6, 2023
Type
Pages
4
Uploaded by CorporalBook6857
1
Analysis of Position, Velocity and Acceleration Lab
Name:
Course/Section:
PHY 1611
Table (16 points)
Position vs Time
Value
Linear Fit
m
0.363
B
-0.0181
y = mx + b
0.363x-0.0181
Quadratic Fit
A
0.124
B
0.0285
C
0.130
y = Ax
2
+ Bx + C
0.124x
2
+0.0285x+0.130
(x
1
, y
1
)
(1.100s,0.302m)
(x
2
, y
2
)
(1.650s,0.524m)
Slope
2.84m/s
Velocity vs. Time
Value
m
0.204
b
0.0513
y = mx + b
0.204x+0.0513
(x
1
, y
1
)
(0.050s,0.04m/s)
(x
2
, y
2
)
(2.650s,0.00m/s)
v
avg
0.02
v
avg
time
0.650s
Acceleration vs.
Time
Value
m
-0.604
b
0.802
y = mx + b
-0.604x+0.802
The mean
-0.014
1.
What are the appropriate units for the slope of the
:
(a)
Position vs Time graph? (2 points)
2
-
m/s
(b)
Velocity vs Time graph? (2 points)
-
m/s
2
(c)
Acceleration vs Time graph? (2 points)
-
m/s
3
2.
For Position vs Time data:
(a)
Did your quadratic fit of this graph provide initial position? If yes, what is its value?
(4 points)
-
Yes, the value of our initial position is 0.153m
(b)
Did your quadratic fit of this graph provide initial velocity? If yes, what is its value?
(4 points)
-
Yes, the initial velocity was 0.0285m/s
(c)
Did your quadratic fit of this graph provide acceleration? If yes, what is its value?
(4 points)
-
Yes, the acceleration is 0.248m/s
2
(our A value, 0.124, times 2 )
(d)
What specific physical quantity does the slope of the two middle points from the
Position vs. Time graph represent?
(4 points)
-
The average velocity is represented by the slope of the two center dots on the Postion vs
Time graph.
3.
For Velocity vs Time data:
(a)
Did your linear fit of this graph provide initial position? If yes, what is its value?
(4 points)
-
No, my graph did not provide the initial position.
(b)
Did your linear fit of this graph provide initial velocity? If yes, what is its value?
(4 points)
-
Yes, the initial velocity was 0 m/s
(c)
Did your linear fit of this graph provide acceleration? If yes, what is its value?
(4 points)
-
Yes, the acceleration of the graph was 0.802m/s
2
3
(d)
How does the time your calculated average velocity occurred at compare to the times
of the two middle points from the position vs. time graph? (3 points)
-
The two values are the same.
(e)
How does the time your calculated average velocity value occurred at relate to the
time values of the first and last good data points in the Velocity vs. Time graph?
(3 points)
-
Between our first and last point the calculated average of the velocity occurred in the
middle.
4.
For Acceleration vs Time data:
(a)
Did your linear fit of this graph provide initial position? If yes, what is its value?
(4 points)
-
No it did not.
(b)
Did your linear fit of this graph provide initial velocity? If yes, what is its value?
(4 points)
-
No it did not
(c)
Did your linear fit of this graph provide acceleration? If yes, what is its value?
(4 points)
-
Yes the acceleration is 0.802m/s
2
(d)
Which method, the mean or the linear fit, gives an acceleration value that in better
agreement with the values of acceleration given by the position and velocity data?
(2 points)
-
The method is mean due to the best fit line being an estimate.
(e)
Did your linear fit of this graph yield Jerk? If yes, what is its value?
(5 points)
-
Yes, the Jerk was -0.604m/s
3
(f)
If Jerk was observed, was its value small enough to be neglected (i.e., close to zero)?
(5 points)
-
The jerk is small enough to be neglected due to it being close to zero.
(g)
What are the SI units of the Jerk?
(2 points)
-
The SI units of the Jerk is m/s
3
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4
5.
Name at least one physical source of error for this experiment.
Do not include
human
error, equipment malfunction or rounding errors. (4 points)
-
One source of error could be labeled as random error. This can occur from transitioning
the measurements from one to the other.
6. Can the Linear Kinematic Equations of Motion be used in a situation in which the
acceleration varies with time?
(4 points)
-
No, the linear kinematic equation of motion cannot be used in a situation which
acceleration varies with time since the equations of linear kinematic of motion can only
work if acceleration is constant during the time interval. If the acceleration is varying
with the time duration this equation would not be applicable
7.
What is the general shape of each graph and why does each have that shape? (10
points)
-
Due to the cart’s speed not being constant and how it continues to accelerate over the
period. The Position vs Time graph’s overall shape is curved line going in a positive
direction. Since the cart’s acceleration and velocity are both positive, the basic shape of
the Velocity vs. Time graph is a linear line traveling in a positive direction. Since the
cart’s acceleration remains the constant throughout time, the acceleration vs time graph’s
general shape is a straight horizontal line.