MAE206-L03-Ch2.3-4.Vectors-Cartesian Representation of Vectors in 3-D Vector Dot Product

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MAE 206 Engineering Statics Prof. Mary Zadeh Assistant Teaching Professor in Mechanical and Aerospace Engineering Department Fall 2023 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Lecture 3 Vectors: Force and Position Ch 2.3. Cartesian Representation of Vectors in 3-D Ch 2.4. Vector Dot Product
Ch. 2.3 Page: 2 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh 1 0 . M o m e n t s o f I n e r t i a 9 . F r i c t i o n 7 . C e n t r o i d s & D i s t r i b u t e d F o r c e S y s t e m s 8 . I n t e r n a l F o r c e s 6 . S t r u c t u r a l A n a l y s i s a n d M a c h i n e s 5 . E q u i l i b r i u m o f b o d i e s 4 . M o m e n t o f a F o r c e 3 . E q u i l i b r i u m o f P a r t i c l e s 2 . V e c t o r s : F o r c e a n d P o s i t i o n 1 . I n t r o d u c t i o n t o S t a t i c s MAE 206 Engineering Statics
Ch. 2.3 Page: 3 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Announcement HW #1 (Ch. 1 & 2.1-2) Due: Wednesday, Aug. 30 at the beginning of the lecture Exam 1 (Ch. 1-3) Monday, Sep. 25 Exam 2 (Ch. 4-6) Monday, Oct. 23 Exam 3 (Ch. 7-9) Monday, Nov. 20
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Ch. 2.3 Page: 4 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Review A vector has both size and direction. A vector has a head and a tail , as well as a line of action , which is the line of infinite extent along which the vector is positioned. The magnitude of a vector is the measure of its size, or length, including appropriate units. The magnitude of a vector is a positive scalar of any vector that has nonzero size, and is zero only for a vector of zero size. The magnitude can never be negative.
Ch. 2.3 Page: 5 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Review - Unit Vector A unit vector is defined to be a dimensionless vector that has unit magnitude . Given any arbitrary vector having nonzero magnitude, we may construct a unit vector that has the same direction, using ො? = Ԧ? Ԧ? We will use a “hat” symbol ( ) over unit vectors, whereas all other vectors will use an arrow symbol ( ). The vector Ԧ? and its magnitude Ԧ? have the same units, thus unit vector ො? is dimensionless.
Ch. 2.3 Page: 6 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Review - Position Vectors The spatial position of one point (head of vector) relative to another point (tail of vector) is provided by a position vector . For example, in figure below, the two points T and H denote the tail and the head of a position. The position vector from T to H is denoted by Ԧ ? 𝑇𝐻 which is given as Ԧ ? 𝑇𝐻 = ? 𝐻 − ? 𝑇 Ƹ ? + ? 𝐻 − ? 𝑇 Ƹ ?
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Ch. 2.3 Page: 7 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Lecture 3 Objectives Chapter 2.3 Understand Right-hand Cartesian coordinate system. Chapter 2.4 Find the vector dot product of two vectors. Calculate the angle between two vectors.
Ch. 2.3 Page: 8 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Right-Hand Cartesian Coordinate System Three dimensions Cartesian coordinate system uses three orthogonal reference directions consisting of x , y , and z directions. Proper interpretation of many vector operations, such as the cross product , requires the x , y , and z directions arranged in a consistent manner. The universal convention in mechanics and vector mathematics in general is z must be taken in the direction shown in Figure and the result is called a right-hand coordinate system .
Ch. 2.3 Page: 9 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Cartesian Vector Representation A vector Ԧ? can be written as Ԧ? = Ԧ? ? + Ԧ? ? + Ԧ? ? = ? ? Ƹ ? + ? ? Ƹ ? + ? ? 𝑘 The magnitude of Ԧ? is given by Ԧ? = ? ? 2 + ? ? 2 + ? ? 2 First a vector Ԧ? 𝑎 that lies in the xy plane is defined. Because ? ? , ? ? , and ? 𝑎 form a right triangle, use Pythagorean theorem ? 𝑎 2 = ? ? 2 + ? ? 2 Then ? 𝑎 and ? ? also form a right triangle, and the Pythagorean theorem provides ? 2 = ? 𝑎 2 + ? ? 2 Substituting for ? 𝑎 2 in this latter expression yields ? 2 = ? ? 2 + ? ? 2 + ? ? 2
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Ch. 2.3 Page: 10 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Direction Angles An effective way to characterize a vector’s orientation is to use direction angles . Direction angles 𝜃 ? , 𝜃 ? , 𝜃 ? and are defined to be the angles measured from the positive x , y , and z directions, respectively, to the direction of the vector. Direction angles have the values between 0° and 180°. Direction angles can be used to obtain vector’s components, and vice versa.
Ch. 2.3 Page: 11 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Direction Angles Consider a vector polygon shown in the figure. This polygon is a right triangle that consists of the vector’s magnitude Ԧ? . Using elementary trigonometry: ? ? = Ԧ? 𝑐𝑜?𝜃 ? ? ? = Ԧ? 𝑐𝑜?𝜃 ? ? ? = Ԧ? 𝑐𝑜?𝜃 ? Hence, Ԧ? = ? ? Ƹ ? + ? ? Ƹ ? + ? ? 𝑘 Ԧ? = Ԧ? cos 𝜃 ? Ƹ ? + Ԧ? cos 𝜃 ? Ƹ ? + Ԧ? cos 𝜃 ? 𝑘 Ԧ? = Ԧ? cos 𝜃 ? Ƹ ? + cos 𝜃 ? Ƹ ? + cos 𝜃 ? 𝑘 Eqn. (2.25) unit vector that points in the direction of 𝒗
Ch. 2.3 Page: 12 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Direction Cosines In Eqn. (2.25), note that cos 𝜃 ? Ƹ ? + cos 𝜃 ? Ƹ ? + cos 𝜃 ? 𝑘 is a unit vector that points in the direction of Ԧ? . Because cosines of the direction angles play such an important role in writing Eqn. (2.25), the quantities cos 𝜃 ? , cos 𝜃 ? , and cos 𝜃 ? are called direction cosines . Examination of Eqn. (2.25) shows that the direction cosines constitute components of a unit vector. That is substituting the expression from Eqn. (2.25) for ? ? , ? ? , ? ? into Ԧ? = ? ? 2 + ? ? 2 + ? ? 2 provides cos 2 𝜃 ? + cos 2 𝜃 ? + cos 2 𝜃 ? = 1 where cos 2 𝜃 ≡ cos 𝜃 2 .
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Ch. 2.3 Page: 13 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Position Vectors Construction of a position vector in three dimensions is analogous to the procedure described in the previous section. Given points T and H have the coordinates ? 𝑇 , ? 𝑇 , ? 𝑇 and ? 𝐻 , ? 𝐻 , ? 𝐻 . The position vector from the tail T to head H is denoted by Ԧ ? 𝑇𝐻 = ? 𝐻 − ? 𝑇 Ƹ ? + ? 𝐻 − ? 𝑇 Ƹ ? + ? 𝐻 − ? 𝑇 𝑘
Ch. 2.3 Page: 14 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Use of Position Vectors to Write Expressions for Force Vectors If a force vector Ԧ 𝐹 lies along the line of action of a position vector Ԧ ? , or is know to be parallel to the position vector, then a vector expression for the force may be written as Ԧ 𝐹 = 𝐹 ො? 𝑟 = 𝐹 Ԧ 𝑟 Ԧ 𝑟 where Ԧ 𝑟 Ԧ 𝑟 is a unit vector that gives Ԧ 𝐹 proper direction, and F is the component of the force Ԧ 𝐹 along the direction Ԧ ? . Often, the location of two points on the line of action of a force will be known, and Ԧ ? can be obtained by taking the difference between coordinates of the position vector’s head and tail . Note that in an expression such as Ԧ 𝐹 = 𝐹 Ԧ 𝑟 Ԧ 𝑟 if F > 0, then the direction of the force is the same as direction of Ԧ ? . if F < 0, then the direction of the force is opposite direction of Ԧ ? .
Ch. 2.3 Page: 15 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Some Simple Structural Members One category of forces that are important in mechanics is forces that develop within structural members. These are called internal forces . Simply stated, it is because structural members have the capability to develop internal forces that are used to make structures, and these structures are used to support the external forces that are applied to them.
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Ch. 2.3 Page: 16 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Example 2.10 Position Vectors and Force Vectors Two cables apply forces to the cantilever I beam. Cable AB applies a tensile force of magnitude 𝑃 = 2 kN , and cable CD applies a tensile force of magnitude 𝐹 = 1 kN . Write expressions for the forces 𝑊 , Ԧ 𝐹 , and 𝑃 applied to the I beam.
Ch. 2.3 Page: 17 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Example 2.14 Solution
Ch. 2.4 Page: 18 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Vector Dot Product The dot product between two vectors Ԧ ? and ? is an operation defined as Ԧ ? ⋅ ? = Ԧ ? ? cos 𝜃 𝜃 is the angle between lines of action of Ԧ ? and ? where 0° ≤ 𝜃 ≤ 180° The dot product yields a result that is a scalar , and thus the dot product is sometimes called the scalar product . The dot product has the following properties: Commutative Property: Ԧ ? ⋅ ? = ? ⋅ Ԧ ? Associative property w.r.t multiplication by a scalar: ? Ԧ ? ⋅ ? = ? Ԧ ? ? = Ԧ ? ⋅ ? ? Distributive property w.r.t vector addition: Ԧ ? + ? Ԧ ? = Ԧ ? ⋅ Ԧ ? + ? ⋅ Ԧ ?
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Ch. 2.4 Page: 19 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Dot Product using Cartesian Components The dot products between combinations of unit vectors are The dot product is between the vector Ԧ ? ⋅ ? = ? ? ? ? + ? ? ? ? + ? ? ? ? Angle between the two vectors is provided by 𝜃 = cos −1 Ԧ ? ⋅ ? Ԧ ? ? = cos −1 ? ? ? ? + ? ? ? ? + ? ? ? ? Ԧ ? ? Ƹ? ⋅ Ƹ? = 𝟏 Ƹ ? ⋅ Ƹ ? = 0 Ƹ ? ⋅ 𝑘 = 0 Ƹ ? ⋅ Ƹ ? = 0 Ƹ ? ⋅ Ƹ ? = 𝟏 Ƹ ? ⋅ 𝑘 = 0 𝑘 ⋅ Ƹ ? = 0 𝑘 ⋅ Ƹ ? = 0 𝒌 ⋅ 𝒌 = 𝟏
Ch. 2.4 Page: 20 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Component of a Vector in a Particular Direction Consider two vectors Ԧ 𝐹 and Ԧ ? and arrange them tail to tail, which leads to Figure below. The parallel component of Ԧ 𝐹 or in other words, the amount of Ԧ 𝐹 that acts in direction Ԧ ? , is denoted by 𝐹 where the subscript means parallel to 𝒓 and is given by 𝐹 = Ԧ 𝐹 ⋅ Ԧ ? Ԧ ? Basic trigonometry gives us the component of Ԧ 𝐹 in the direction of Ԧ ? as 𝐹 = Ԧ 𝐹 cos 𝜃
Ch. 2.4 Page: 21 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Component of a Vector in a Perpendicular Direction Once we have determined the component of a vector parallel to a particular direction Ԧ ? , it is straightforward to determine the component vector that is perpendicular to Ԧ ? , and we call this the perpendicular component of the vector . Consider the resolution of Ԧ 𝐹 into the parallel and perpendicular components shown in Figs. (a) and (b). Vector addition provides Ԧ 𝐹 = Ԧ 𝐹 + Ԧ 𝐹 . If 𝐹 is known, then Ԧ 𝐹 = Ԧ 𝐹 − Ԧ 𝐹 . Use Pythagorean theorem 𝐹 2 = 𝐹 2 + 𝐹 2 Once 𝐹 is known, 𝐹 may be obtained from the above equation as 𝐹 = 𝐹 2 − 𝐹 2
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Ch. 2.4 Page: 22 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Example 2.16 Component of a Force in a Particular Direction A tractor is stuck in mud, and to free it, a cable applying a force with magnitude F and direction Ԧ ? 1 is attached to the front of the tractor as shown. The operator estimates that a 400 lb force applied in the direction of the tractor’s chassis, which is Ԧ ? 2 , will be sufficient to free it. Determine the cable force F that should be applied and the component of this force perpendicular to the direction of the tractor’s chassis.
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Ch. 2.4 Page: 23 Let’s GO PACK MAE 206 Fall 2023 Lecture 3 Prof. Zadeh Example 2.16 Solution
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