MAE206-L05-Ch3.1-2.Behavior of Cables, Bars, and Springs Equilibrium of Particles in 2-D (1)

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MAE 206 Engineering Statics Lecture 5 Equilibrium of Particles Ch 3.1. Equilibrium of Particles in Two Dimensions Ch 3.2 Behavior of Cables, Bars, and Spring Prof. Mary Zadeh Assistant Teaching Professor in Mechanical and Aerospace Engineering Department Fall 2023 NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
Ch.3.1 Page: 2 : y /’ /’ 4 MAE 206 Engineering Statics Ay ‘n = R S R 2, . & ! WA\ i o. 5 A\m ;‘\\_-.sh\ P s & Dijstri dfo(('e —= s ) & stribute \P’/'l, ‘\\ 30 Ctural Analvsis a“d N\ NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh o&‘es N EQUiIibrium ofb
Ch. 3.1 Announcement Page: 3 ®Quiz #1 (Ch. 1 & 2) " Due: Monday, Sep. 11 » Closed book/notes/formula sheet. " Calculator ®Exam 1 (Ch. 1-3) /you are restricted to solely\ = Monday, Sep. 25 using the equations and methods provided in the lecture notes. Any other equations or methods from ®Exam 3 (Ch. 7-9) external sources are not = Monday, Nov. 20 K permitted. / NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh ®Exam 2 (Ch. 4-6) " Monday, Oct. 23
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h. 3. Lecture 5 Objectives g 4 ®Review free body diagram (FBD) ®Cables and Bars ®pPulleys ® Reactions NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
cnep o . . . . Ch.3.1 Equilibrium of Particles in Two Dimensions Page: 5 ®In mechanics, a particle is an object whose mass is concentrated at a point. It is defined to have zero volume. ® An object that is small compared to other objects and/or dimensions in a problem may often be idealized as a particle. ®|f the lines of action of all forces intersect at a common point, this is called a concurrent force system. An object subjected to a concurrent force system may be idealized as a particle as shown in the figure. NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
h. 3. Static Equilibrium oo 6 ®Static equilibrium means @ = 0. ® A particle is in static equilibrium if it has no motion (i.e., is at rest) or if it moves with constant velocity (i.e., has uniform speed and uniform direction). ®The conditions for equilibrium of a particle are, > F=0 or X F)i+ (ZF)=0 (@) or), ,b,=0 and X FE =0 (2) " Equation (1) states the condition for equilibrium in vector form. " Equation (2) states the conditions for equmbrlum m scalar form. NC STATE %@ Let's GO PACK | UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
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Ch.3.1 Free Body Diagram (FBD) Page: 7 ® A free body diagram (FBD) is a sketch of a body or a portion of a body that is separated, or made free, from its environment and/or other parts of the structural system and all forces that act on the body must be shown in the sketch. ®Once an FBD is drawn, application of Newton’s second law Y F = md may proceed. ® |n statics, we seek conditions so that a = 0 (equilibrium) whereas in subjects that follow statics, such as dynamics and vibrations, we seek to determine a and how the motion of a body or structure evolves with time. cutj lw =1501b W =1501b N eand l - i Y 5T _____ Bridget Clyde /Sto kSh t/Alamy Stock Photo (b) (c) (d) NC STATE Let’s GO PACK | UNIVERSITY % @MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
Procedure for Drawing FBDs g ® Decide on the particle whose equilibrium you want to analyze. ® magine that this particle is "cut" completely free (isolated) from the structure and/or its environment. = |n 2-D, think of a closed line that completely encircles the point. = |n 3-D, think of a closed surface that completely surrounds the point. ® Sketch the particle ® Sketch the forces = Forces from the environment (e.g., weight). = Forces where a cut passes through a structural member (internal forces). = Forces where a cut passes through a support (support reactions or simply reactions). ®Select a coordinate system and show dimensions. Add pertinent dimensions and angles to the FBD to fully define the locations and orientations of all forces. cut W = 1501b W = 1501b i | \ T \\: = LY 4 r -—"|\—— ® X - ,\\ A E \\\ y 2 00*\1 R R 2007 K g < ' X Bridget Clyde/StockShot/Alamy Stock Photo ' (b) (c) (d) (a) NC STAl E fi @ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
Ch. 3.1 Cables and Bars Page: 9 ® Cables buckle when subjected to very low compressive force, it is common to assume they can support only tensile forces. Thus, we will always assign cable forces in FBDs so that positive values correspond to tension. ®Bars can support both tensile and compressive forces, and thus, we always confront the question of what direction should be used to represent the forces they support when drawing FBDs. Thus, a good practice when drawing FBDs is to assign the forces supported by all bars such that positive values correspond to tension. D ::‘\\\‘“/,;: T (a) (b) (c) NC STA-i E % - Let’s GO PACK - UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
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Ch.3.1 PUIIGVS Page: 10 ® A pulley is a simple device that changes the orientation of a cable and hence, changes the direction of the force a cable supports. " |f a pulley is idealized as being frictionless and the cable has negligible weight, then the magnitude of the force supported by the cable is unchanged as it wraps around the pulley. " |f 2 cable with negligible weight is wrapped around several frictionless pulleys, then the magnitude of the force is the same throughout the entire cable. " To idealize a pulley as a particle, such as when drawing an FBD, you can look for the point of intersection of all forces applied to the pulley, or better yet, you can simply “shift” the cable forces to the bearing of the pulley. . | If the pulley has friction, g\ T u then in general 7} # 7T». - R JT Tz\ If the pulley is frictionless, ' @/ + Tl then Tl = T2 always. Frictionless pulleys (a) (b) NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
. Ch. 3.1 Reactions Page: 11 ® A reaction force, or simply reaction, is a force exerted by a support on a body or a structure. ® Consider yourself as you stand on a horizontal floor, as shown in figure (a). The floor exerts a force on your body that you remain in equilibrium. Thus, the floor exerts on your body a vertical force of magnitude R, and your body in turn exerts on the floor a force of magnitude R in the opposite direction. VW ! AR R (a) (b) (a) (b) Person standing on a horizontal surface. Person standing on a rough incline. NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
Ch.3.1 Common Supports for Bodies and the Associated Reactions ra.: 12 In all cases, the reaction forces for a particular support may be determined by considering the motion the support prevents. Support Reactions JI’ roller rocker roller h L L roller in |frictionless| collar on loose- surface frictionless fitting track b ing trac Rx =0 ar 6 N 6 N cable link or bar Mg e/ cable with curved link self-weight or bar j—xj Jrough surface | R, +0 Nc STATE i@ Let’s GO PACK UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
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Ch.3.1 Structured Problem-Solving Approach Page: 13 ®Road Map: Identify data and unknowns and create a solution strategy. * Modeling: Identify the system and make reasonable assumptions leading to the development of an FBD (or possibly multiple FBDs). A coordinate frame is required. " |n drawing an FBD, a real life problem is replaced by an idealization. " |n modeling, reasonable assumptions are made about what is physically important in a system and what is not, with the goal of developing a model that contains the essential physics while hopefully being simple enough to allow for a tractable mathematical solution. ® Governing Equations: Write the equations of equilibrium ); F= 6, and as needed, additional equations for other physical phenomena pertinent to the problem. ® Computation: Solve the system of governing equations. ®Discussion and Verification: The results are critically examined and interpreted. NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
ch. 3.1 Example 3.1 Page: 14 Consider the structure below where the loading consists of a vertical force P applied to point A. (a) If P=100 N, determine the forces supported by cable AB and bar AC. (b) If cable A B can support a tensile force of 1200 N before breaking, and bar AC can support a compressive force of 1600 N before buckling, determine the largest force P that can be applied. 30° B NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
. Ch.3.1 Example 3.1 Solution Page: 15 NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
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Ch.3.1 Example 3.2 Page: 16 A small cable car is used to transport passengers across a river. If the cable car and its contents have a mass of 400 kg, determine the forces in cables AC and ED and the force in bar AB. Point A is a pin. NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
. Ch.3.1 Example 3.2 Solution Page: 17 NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
h. 3. Equilibrium Geometry of a Structure page 15 ®\When analyzing equilibrium by summing forces in Newton’s law Y F = 6, the orientation of forces in the equilibrium configuration must be used, and this generally means the orientation or shape of the structure after loads have been applied must be known, or must be determined. ® Fortunately, for many problems, the members that constitute a structure are sufficiently stiff and appropriately arranged so that the structure’s geometry changes very little after loads are applied. ®\When this is the case, accurate results may be obtained by taking the geometries of the structure before loads are applied and after loads are applied to be the same. NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
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Ch. 3.2 Cables and Bars Page: 19 ®Cables " We generally assume cables to be inextensible and perfectly flexible. " A perfectly flexible cable will immediately buckle if it is subjected to a compressive force. " The cable may have a maximum tensile load limit, beyond which the cable will be unsafe or will fail. ®Bars " We generally assume bars to be rigid so that they are inextensible in both tension and compression. " |n addition, a bar may have maximum tensile load and compressive load limits, beyond which the bar will be unsafe or will fail. - ESSSSSSSSSSSSSsssssssssssssssssssssss§ —>» cable, rope, string, ... NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
Ch. 3.2 Springs Page: 20 ® A spring is a mechanical device that produces a force when it undergoes a deformation. ®Cables and bars are also springs when their deformation must be accounted for. [ 8 N c STATE i ® Let’s GO PACK UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
Ch. 3.2 Springs Page: 21 ®The equation governing the spring’s linear elastic behavior is often called the spring law and is‘FS =ké = k(L LO)| where » F.is the force supported by the spring 0 is the elongation of spring from its unstretched or undeformed length k is the spring stiffness (units: force/length) k = 0 " Ly is the initial (unstretched) spring length = L is the final spring length ' L = final length - L, = initial Iengthol . Sy | 'I‘ 'I‘ 'I. 'l| '0. 'l' -l' l' ]‘ '0."l. ’0. _0' ]'" a tenSTlon Tl k initial B :.:_'u_ VUV l_> | . 5 compresion /| £ =8 swat |—{{MII——> = k . . FS - k6 contraction -—{— elongation = k(L - Ly) NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
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Ch. 3.2 Springs Page: 22 Springs are used to represent a variety of deformable members in engineering problems. Examples of structures/devices that may be idealized as springs: FS' ' N /‘j5 fingernail clipper = 2. 5 N lock washer F l” o | > kgé H > W? F, | china teacup in box || " with foam packaging multistory building / wheelbarrow with pneumatic tire NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
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Ch. 3.2 Springs Page: 23 ®Occasionally springs are designed to be nonlinear, such as the leaf spring suspension for a truck shown in figure. ®\When the load supported by the axle is small, only a few of the leaves in the spring will engage and the stiffness is low. As the load increases, more leaves engage, and the stiffness becomes progressively higher. FS ®* Although nonlinear, a leaf ¢ spring is still elastic since it F, 3 7T Il elast | k returns to its original shape : . when the load is removed. FS /I k = k(0) L 5 NC STATE i@ Let’s GO PACK I UNIVERSITY MAE 206 Fall 2023 Lecture 5 Prof. Zadeh
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