For Exercises 131-132, refer to the formula F = G m 1 m 2 d 2 . This gives the gravitational force F (in Newtons, N) between two masses m 1 and m 2 (each measured in kg) that are a distance of d meters apart. In the formula, G = 6.6726 × 10 − 11 N-m 2 /kg 2 . Determine the gravitational force between the Earth mass = 5.98 × 10 24 kg and an 80-kg human standing at sea level. The mean radius of the Earth is approximately 6.371 × 10 6 m .
For Exercises 131-132, refer to the formula F = G m 1 m 2 d 2 . This gives the gravitational force F (in Newtons, N) between two masses m 1 and m 2 (each measured in kg) that are a distance of d meters apart. In the formula, G = 6.6726 × 10 − 11 N-m 2 /kg 2 . Determine the gravitational force between the Earth mass = 5.98 × 10 24 kg and an 80-kg human standing at sea level. The mean radius of the Earth is approximately 6.371 × 10 6 m .
Solution Summary: The author explains the formula used to calculate the gravitational force between the Earth and a human weighing 80kg.
For Exercises 131-132, refer to the formula
F
=
G
m
1
m
2
d
2
.
This gives the gravitational force
F
(in Newtons, N) between two masses
m
1
and
m
2
(each measured in kg) that are a distance of
d
meters apart. In the formula,
G
=
6.6726
×
10
−
11
N-m
2
/kg
2
.
Determine the gravitational force between the Earth
mass
=
5.98
×
10
24
kg
and an 80-kg human standing at sea level. The mean radius of the Earth is approximately
6.371
×
10
6
m
.
Consider the current flow of electricity within an electrical circuit. The formula of Ohm's Law says that when electric current is flowing through a
resistor, the current i (measured in amps) can be calculated from the voltage v (measured in volts) and the resistance R of the resistor (measured in
ohms).
Complete Part (a) and Part (b) using the given formula:
R
Part (a). The resistor in a radio circuit was measured to be 5000 ohms.
I. What is the formula for the current i in the radio circuit?
Use lower-case letter v for voltage.
IL. Select the graph of your formula for i versus v.
2.5
1.5
1.5
0.5
05
3000 4000 5000 6000
1000 2000 3000 4000 s000 6000
OGraph 1
OGraph 2
25
2.5
1.5
1.5
0.5
0.5
1000 2000 3000 4000 5000 6000
1000 2000 3000 4000 5000 6000
OGraph 3
OGraph 4
II. What happens to the current when voltage increases?
O As the resistance increases, so does the current.
A
O As the voltage increases, so does the resistance.
As the voltage increases, so does the current.
Part (b). The…
Show your all calculation
The National Weather Service uses the following formula to calculate the wind chill:W = 35.74 + 0.6215 Ta − 35.75 V0.16 + 0.4275 Ta V0.16where W is the wind chill temperature in ◦F, Ta is the air temperature in ◦F, and V is thewind speed in miles per hour. Note that W is defined only for air temperatures at or lowerthan 50◦F and wind speeds above 3 miles per hour.(a) Suppose the air temperature is 42◦ and the wind speed is 7 miles per hour. Find thewind chill temperature. Round your answer to two decimal places.(b) Suppose the air temperature is 37◦F and the wind chill temperature is 30◦F. Find thewind speed. Round your answer to two decimal places.
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