CALCULUS & ITS APPLICATIONS+MYMATHLAB
CALCULUS & ITS APPLICATIONS+MYMATHLAB
16th Edition
ISBN: 9781323161470
Author: BITTINGER
Publisher: PEARSON C
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Chapter PSDT, Problem 28AP

Solve.

4 x 3 = x

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• • Let > be a potential for the vector field F = (−2 y³, −6 xy² − 4 z³, −12 yz² + 4 2). Then the value of sin((-1.63, 2.06, 0.57) – (0,0,0)) is - 0.336 -0.931 -0.587 0.440 0.902 0.607 -0.609 0.146

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