Stats: Modeling the World Nasta Edition Grades 9-12
Stats: Modeling the World Nasta Edition Grades 9-12
3rd Edition
ISBN: 9780131359581
Author: David E. Bock, Paul F. Velleman, Richard D. De Veaux
Publisher: PEARSON
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Chapter PI, Problem 27RE

(a)

To determine

To plot these data.

(a)

Expert Solution
Check Mark

Explanation of Solution

It is given in the question the list of number of pieces of mail received at a school office. Thus, the plot of this data will be as:

Stats: Modeling the World Nasta Edition Grades 9-12, Chapter PI, Problem 27RE

(b)

To determine

To find appropriate summary statistics.

(b)

Expert Solution
Check Mark

Answer to Problem 27RE

  Mean=100.25pieces of mailStandard deviation=25.54 pieces of mail

Explanation of Solution

It is given in the question the list of number of pieces of mail received at a school office. Thus, the appropriate summary statistics will be calculated through the calculator TI89 . Thus, if we have to compute the summary statistics then press F4 , that is Calc. and then input the name of the list using VAR-LINK and then press enter. The summary statistics will appear/ thus, the result will be:

  Mean=100.25pieces of mailStandard deviation=25.54 pieces of mail

(c)

To determine

To write a brief discussion of the school’s mail deliveries.

(c)

Expert Solution
Check Mark

Explanation of Solution

It is given in the question the list of number of pieces of mail received at a school office. Thus, as we look at the histogram of the data we can say that the distribution is somewhat symmetric in nature as the shape of the histogram appears to be bell-shaped. And the distribution appears to be uni-modal but the centre is rather flat and almost uniform in nature.

(d)

To determine

To find out what percentage of days actually lie within one standard deviation of the mean.

(d)

Expert Solution
Check Mark

Answer to Problem 27RE

  64% .

Explanation of Solution

It is given in the question the list of number of pieces of mail received at a school office. Thus, as we look at the histogram of the data we can say that the distribution is somewhat symmetric in nature. Thus, the percentage of days actually lie within one standard deviation of the mean is 64% . The normal model seems to work perfectly well since it predicts 68% .

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