PRECALCULUS:GRAPH...-NASTA ED.(FLORIDA)
PRECALCULUS:GRAPH...-NASTA ED.(FLORIDA)
10th Edition
ISBN: 9780136174318
Author: Demana
Publisher: PEARSON
Expert Solution & Answer
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Chapter P.4, Problem 31E
Solution

Which line shown here has the greater slope, the line contains the origin and the point in the upper right corner of the grapher screen.

Graph (a) has greater slope.

Given:

  1. −10,10  by  −15,15

  2. −10,10  by −10,10

  PRECALCULUS:GRAPH...-NASTA ED.(FLORIDA), Chapter P.4, Problem 31E , additional homework tip 1

(a)

  PRECALCULUS:GRAPH...-NASTA ED.(FLORIDA), Chapter P.4, Problem 31E , additional homework tip 2

(b)

Concept Used:

  • The slope of a line is defined as rise over run

Calculation:

In order to find the greater slope of the line, in the given graph y-axis is -15 to 15, so in the first (a) graph the slope is 1510 because from 0,0 it rise 15 units and then run 10 units to the right top corner, so slope of a line in (a) is 1510 or 1.5

Now in graph (b) y-axis is -10 to 10 , so in graph (b) slope is 1010 , because from 0,0 it rises 10 units and then run 10 units to the right top corner , so the slope of line (b) is 1010 or 1.

So, graph (a) has greater slope.

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Chapter P.4, Problem 30E
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Chapter P.4, Problem 32E

Chapter P Solutions

PRECALCULUS:GRAPH...-NASTA ED.(FLORIDA)

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