Chapter FRP, Problem 21P

An alkane (A) with the formula $C_6{H}_{14}$ reacts with chlorine to yield three compounds with the formula $C_6{H}_{13}Cl$; B, C, and D. Of these only C and D undergo dehydrohalogenation with sodium ethoxide in ethanol to produce an alkene. Moreover C and D yield the same alkene E $\left(C_6{H}_{12}\right)$. Hydrogenation of E produces A. Treating E with HCl produces a compound (F) that is an isomer of B, C, and D. Treating F with magnesium in dry ether followed by aqueous acid gives a compound (G) that is isomeric with A. Propose structures for A-G.