Concept explainers
(a)
Interpretation:
The complete IUPAC name of the given molecule is to be written.
Concept introduction:
The IUPAC name of a compound consists of three parts, prefix, root and suffix. The root is the longest continuous carbon chain or the largest ring that bears the highest priority functional group. The suffix refers to the highest priority functional group. The functional group name suffix replaces the last ‘e’ in the root alkyl/aryl name. The root chain or ring carbons are numbered so that the highest priority group gets the lowest possible location numbers. The number is inserted between the root and the suffix unless redundant. Any other, low priority
(b)
Interpretation:
The complete IUPAC name of the given molecule is to be written.
Concept introduction:
The IUPAC name of a compound consists of three parts, prefix, root, and suffix. The root is the longest continuous carbon chain or the largest ring that bears the highest priority functional group. The suffix refers to the highest priority functional group. The functional group name suffix replaces the last ‘e’ in the root alkyl/aryl name. The root chain or ring carbons are numbered so that the highest priority group gets the lowest possible location numbers. The number is inserted between the root and the suffix unless redundant. Any other low priority functional groups are listed alphabetically in the prefix, along with their location numbers. If the root is a ring compound, the ring is numbered in the direction that gives the lowest possible numbers to other substituents if present. A prefix di, tri, etc. is used in case two or more instances of the functional group are present.
(c)
Interpretation:
The complete IUPAC name of the given molecule is to be written.
Concept introduction:
The IUPAC name of a compound consists of three parts, prefix, root, and suffix. The root is the longest continuous carbon chain or the largest ring that bears the highest priority functional group. The suffix refers to the highest priority functional group. The functional group name suffix replaces the last ‘e’ in the root alkyl/aryl name. The root chain or ring carbons are numbered so that the highest priority group gets the lowest possible location numbers. The number is inserted between the root and the suffix unless redundant. Any other low priority functional groups are listed alphabetically in the prefix, along with their location numbers. If the root is a ring compound, the ring is numbered in the direction that gives the lowest possible numbers to other substituents if present. A prefix di, tri, etc. is used in case two or more instances of the functional group are present.

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Chapter E Solutions
ORG CHEM W/ EBOOK & SW5 + STUDY GUIDE
- V Biological Macromolecules Drawing the Haworth projection of an aldose from its Fischer projection Draw a Haworth projection of a common cyclic form of this monosaccharide: H C=O HO H HO H H OH CH₂OH Explanation Check Click and drag to start drawing a structure. Xarrow_forwardComplete the mechanismarrow_forwardComplete the mechanismarrow_forward
- 8 00 6 = 10 10 Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 11. If you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than unstable, you can pick any of them to redraw.) Check OH stable HO stable Ounstable unstable O OH stable unstable OH 80 F6 F5 stable Ounstable X Save For Later Sub 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy C ཀྭ་ A F7 매 F8 F9 4 F10arrow_forwardJust try completing it and it should be straightforward according to the professor and TAs.arrow_forwardThe grading is not on correctness, so if you can just get to the correct answers without perfectionism that would be great. They care about the steps and reasoning and that you did something. I asked for an extension, but was denied the extension.arrow_forward
- Show your work and do something that is reasonable. It does not have to be 100% correct. Just show something that looks good or pretty good as acceptable answers. Something that looks reasonable or correct would be sufficient. If you can get many of them correct that would be great!arrow_forwardShow your work and do something that is reasonable. It does not have to be 100% correct. Just show something that looks good or pretty good as acceptable answers. Something that looks reasonable or correct would be sufficient. If you can get many of them correct that would be great!arrow_forwardTake a look at the following molecule, and then answer the questions in the table below it. (You can click the other tab to see the molecule without the colored regions.) with colored region plain 0= CH2-0-C-(CH2)16-CH3 =0 CH-O-C (CH2)7-CH=CH-(CH2)5-CH3 D CH3 | + OMPLO CH3-N-CH2-CH2-0-P-O-CH2 B CH3 A Try again * 000 Ar 8 0 ?arrow_forward
