Operations Management: Processes and Supply Chains (11th Edition)
Operations Management: Processes and Supply Chains (11th Edition)
11th Edition
ISBN: 9780133872132
Author: Lee J. Krajewski, Manoj K. Malhotra, Larry P. Ritzman
Publisher: PEARSON
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Chapter D, Problem 8P

A

Summary Introduction

Interpretation:The number of bottles of each type that can be produced every month should be determined.

Concept Introduction:The company is a producer of light beer and dark beer. However, the company is facing scarcity in resources and also experiencing troubled profits.

B

Summary Introduction

Interpretation:Any constraints in the produce with slack or surplus should be defined.

Concept Introduction: A business student requires completing 65 courses to attain graduation. While the business courses should be greater than or equal to 23, the non-business should be greater than or equal to 20. While an average business course needs a textbook that costs $60 and 120 hours of study; the non-business courses require a textbook that costs $24 and 200 hours of study.

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Mark has a company that produces tables and chairs, both having two different models. The product models and related information are given in the following table. Wood costs 3000 $ per cubic meter and 200 m3 of wood are available for the upcoming month. The cost of labor is 40 $/hour and there are 6000 hours of labor available in a month. Mark sells his products to a big chain retail company. The company purchases all products whatever Mark produces.  Mark formulates an LP as follows to determine the optimal monthly production plan such that he maximizes the total profit. Decision Variables: X1 : number of basic tables to be produced. X2 : number of elegant tables to be produced. X3 : number of basic chairs to be produced. X4 :number of elegant chairs to be produced. Max Z = 140 X1 +  345 X2 + 120 X3  +  260 X4    ( maximize total profit) Subject to 0.11 X1 +  0.13 X2 + 0.06 X3  +  0.07 X4  ≤ 200  (constraint on the available amount of wood) 2 X1  +  4.5 X2 + 1.5 X3  +  4 X4  ≤  6000…
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