Chapter B.2, Problem 9E

To determine

To Find: The mean,median and mode of the data.

Answer to Problem 9E

Mean is $12.83$ ,median is $12$ and mode is all numbers.

Explanation of Solution

Given information: Given data is $21,4,18,6,25,3$ .

Calculation: Given data is $21,4,18,6,25,3$ .

Mean of the data :

  $\begin{array}{l}=\frac{\mathrm{s}\mathrm{u}\mathrm{m}\mathrm{o}\mathrm{f}\mathrm{o}\mathrm{b}\mathrm{s}\mathrm{e}\mathrm{r}\mathrm{v}\mathrm{a}\mathrm{t}\mathrm{i}\mathrm{o}\mathrm{n}}{\mathrm{n}\mathrm{u}\mathrm{m}\mathrm{b}\mathrm{e}\mathrm{r}\mathrm{o}\mathrm{f}\mathrm{o}\mathrm{b}\mathrm{s}\mathrm{e}\mathrm{r}\mathrm{v}\mathrm{a}\mathrm{t}\mathrm{i}\mathrm{o}\mathrm{n}}\\ =\frac{21+4+18+6+25+3}{6}\\ =\frac{77}{6}=12.83\end{array}$

Median :

Data in ascending order $3,4,6,18,21,25$ .

  $\begin{array}{l}\mathrm{Median}=\frac{\frac{\mathrm{n}}{2}\mathrm{t}\mathrm{h}+(\frac{\mathrm{n}}{2}+1)\mathrm{t}\mathrm{h}}{2}\\ \mathrm{Median}=\frac{\frac{6}{2}\mathrm{t}\mathrm{h}+(\frac{6}{2}+1)\mathrm{t}\mathrm{h}}{2}\\ \mathrm{Median}=\frac{3\mathrm{t}\mathrm{h}+4\mathrm{t}\mathrm{h}}{2}\\ \mathrm{Median}=\frac{6+18}{2}=\frac{24}{2}=12\end{array}$

Mode :

All number comes equal times.

So mode is all numbers.