Get Ready for Organic Chemistry
Get Ready for Organic Chemistry
2nd Edition
ISBN: 9780321774125
Author: KARTY, Joel
Publisher: PEARSON
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Chapter B, Problem B.20P
Interpretation Introduction

(a)

Interpretation:

The IUPAC name for the given compound is to be written.

Concept introduction:

In the case of molecules containing a C=C  or a CC, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered as the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene, if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

If the root is a chain, numbering begins from that end of the chain which encounters the C=C  or CC at the earliest. If there is a tie, then the chain is numbered such that the substituents get the lowest locator numbers.

If the root is a ring, then the double or triple bonded carbon atoms are designated as C1 and C2. This must be done such that the locator numbers for the substituents are minimized. The lower of the two locator numbers for the C=C  or CC is written before the ene or yne suffix. Prefixes and locator numbers are used for the substituents attached.

Interpretation Introduction

(b)

Interpretation:

The IUPAC name for the given compound is to be written.

Concept introduction:

In the case of molecules containing a C=C  or a CC, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered as the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene, if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

If the root is a chain, numbering begins from that end of the chain which encounters the C=C  or CC at the earliest. If there is a tie, then the chain is numbered such that the substituents get the lowest locator numbers.

If the root is a ring, then the double or triple bonded carbon atoms are designated as C1 and C2. This must be done such that the locator numbers for the substituents are minimized. The lower of the two locator numbers for the C=C  or CC is written before the ene or yne suffix. Prefixes and locator numbers are used for the substituents attached.

Interpretation Introduction

(c)

Interpretation:

The IUPAC name for the given compound is to be written.

Concept introduction:

In the case of molecules containing a C=C  or a CC, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered as the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene, if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

If the root is a chain, numbering begins from that end of the chain which encounters the C=C  or CC at the earliest. If there is a tie, then the chain is numbered such that the substituents get the lowest locator numbers.

If the root is a ring, then the double or triple bonded carbon atoms are designated as C1 and C2. This must be done such that the locator numbers for the substituents are minimized. The lower of the two locator numbers for the C=C  or CC is written before the ene or yne suffix. In the case of cycloalkene or cycloalkyne, the locator number is not included explicitly. Prefixes and locator numbers are used for the substituents attached.

Interpretation Introduction

(d)

Interpretation:

The IUPAC name for the given compound is to be written.

Concept introduction:

In the case of molecules containing a C=C  or a CC, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered as the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene, if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

If the root is a chain, numbering begins from that end of the chain which encounters the C=C  or CC at the earliest. If there is a tie, then the chain is numbered such that the substituents get the lowest locator numbers.

If the root is a ring, then the double or triple bonded carbon atoms are designated as C1 and C2. This must be done such that the locator numbers for the substituents are minimized. The lower of the two locator numbers for the C=C  or CC is written before the ene or yne suffix. Prefixes and locator numbers are used for the substituents attached.

Interpretation Introduction

(e)

Interpretation:

The IUPAC name for the given compound is to be written.

Concept introduction:

In the case of molecules containing a C=C  or a CC, the longest continuous carbon chain or largest ring that contains the double or triple bond is considered as the root. It is possible that the longest carbon chain has more carbons than specified by the root. But the double or triple bond must be a part of the root. The root is named from the name of the analogous alkane or cycloalkane by replacing the suffix ane by ene, if a double bond is present. The suffix ane is replaced by yne if a triple bond is present.

If the root is a chain, numbering begins from that end of the chain which encounters the C=C  or CC at the earliest. If there is a tie, then the chain is numbered such that the substituents get the lowest locator numbers.

If the root is a ring, then the double or triple bonded carbon atoms are designated as C1 and C2. This must be done such that the locator numbers for the substituents are minimized. The lower of the two locator numbers for the C=C  or CC is written before the ene or yne suffix. Prefixes and locator numbers are used for the substituents attached.

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Students have asked these similar questions
1) a) Give the dominant Intermolecular Force (IMF) in a sample of each of the following compounds. Please show your work. (8) SF2, CH,OH, C₂H₂ b) Based on your answers given above, list the compounds in order of their Boiling Point from low to high. (8)
19.78 Write the products of the following sequences of reactions. Refer to your reaction road- maps to see how the combined reactions allow you to "navigate" between the different functional groups. Note that you will need your old Chapters 6-11 and Chapters 15-18 roadmaps along with your new Chapter 19 roadmap for these. (a) 1. BHS 2. H₂O₂ 3. H₂CrO4 4. SOCI₂ (b) 1. Cl₂/hv 2. KOLBU 3. H₂O, catalytic H₂SO4 4. H₂CrO4 Reaction Roadmap An alkene 5. EtOH 6.0.5 Equiv. NaOEt/EtOH 7. Mild H₂O An alkane 1.0 2. (CH3)₂S 3. H₂CrO (d) (c) 4. Excess EtOH, catalytic H₂SO OH 4. Mild H₂O* 5.0.5 Equiv. NaOEt/EtOH An alkene 6. Mild H₂O* A carboxylic acid 7. Mild H₂O* 1. SOC₁₂ 2. EtOH 3.0.5 Equiv. NaOEt/E:OH 5.1.0 Equiv. NaOEt 6. NH₂ (e) 1. 0.5 Equiv. NaOEt/EtOH 2. Mild H₂O* Br (f) i H An aldehyde 1. Catalytic NaOE/EtOH 2. H₂O*, heat 3. (CH,CH₂)₂Culi 4. Mild H₂O* 5.1.0 Equiv. LDA Br An ester 4. NaOH, H₂O 5. Mild H₂O* 6. Heat 7. MgBr 8. Mild H₂O* 7. Mild H₂O+
Li+ is a hard acid.  With this in mind, which if the following compounds should be most soluble in water? Group of answer choices LiBr LiI LiF LiCl
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