Chapter A.9, Problem 68AYU

To determine

To solve: Each inequality. Express your answer using set notation or interval notation. Graph the solution set.

Answer to Problem 68AYU

$\left\{x|x \ge 12\right\}$ or $\left[12, \infty \right)$

Explanation of Solution

Given:

$\frac{x}{3} \ge 2 + \frac{x}{6}$

Calculation:

$\frac{x}{3} \ge 2 + \frac{x}{6}$

Multiply by $6$

$2x \ge 12 + x$

$2x - x \ge 12 + x - x$   -----(Subtract $x$ on both sides)

$x \ge 12$

The solution set is $\left\{x|x \ge 12\right\}$ or using interval notation, all numbers in the interval $\left[12, \infty \right)$