Precalculus with Limits
Precalculus with Limits
3rd Edition
ISBN: 9781133947202
Author: Ron Larson
Publisher: Cengage Learning
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Chapter A.6, Problem 74E

a .

To determine

To solve:The inequality by graphical analysis and approximate the value of x for satisfy the given inequality.

a .

Expert Solution
Check Mark

Answer to Problem 74E

The inequality of x is −10≤x≤6 .

Explanation of Solution

Given:

  y=|12x+1|,y≤4

  y=|12x+1|

be a given equation and y≤4 be given inequality and it has to use graphing utility to graph the equation.

  Precalculus with Limits, Chapter A.6, Problem 74E , additional homework tip 1

  y=|12x+1|

When value of y is 4 then, value of x is lies between −10 and 6 .

  y=|12x+1|    4=|12x+1|         4=±(12x+1)     4=12x+1                  4=−12x−13=12x                      5=−12xx=6                        x=−10

When value of y is 3 then, value of x is lies between −8 and 4 .

  y=|12x+1|    3=|12x+1|         3=±(12x+1)     3=12x+1                  3=−12x−12=12x                      4=−12xx=4                        x=−8

Hence the inequality of x is −10≤x≤6 .

b .

To determine

To solve: The inequality by graphical analysis and approximate the value of x for satisfy the given inequality.

b .

Expert Solution
Check Mark

Answer to Problem 74E

The inequality of x is −4≤x≤0 .

Explanation of Solution

Given:

  y=|12x+1|,y≥1

  y=|12x+1|

be a given equation and y≥1 be given inequality and it has to use graphing utility to graph the equation.

  Precalculus with Limits, Chapter A.6, Problem 74E , additional homework tip 2

  y=|12x+1|

When value of y is 1 then, value of x is lies between −4 and 0 .

  y=|12x+1|    1=|12x+1|         1=±(12x+1)     1=12x+1                  1=−12x−10=12x                      2=−12xx=0                        x=−4

When value of y is 2 then, value of x is lies between −6 and 2 .

  y=|12x+1|    2=|12x+1|         2=±(12x+1)     2=12x+1                  2=−12x−11=12x                      3=−12xx=2                        x=−6

Hence the inequality of x is −4≤x≤0 .

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Chapter A.6, Problem 73E
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Chapter A.6, Problem 75E

Chapter A Solutions

Precalculus with Limits

Ch. A.1 - Prob. 1ECh. A.1 - Prob. 2ECh. A.1 - Prob. 3ECh. A.1 - Prob. 4ECh. A.1 - Prob. 5ECh. A.1 - Prob. 6ECh. A.1 - Prob. 7ECh. A.1 - Prob. 8ECh. A.1 - Prob. 9ECh. A.1 - Prob. 10E
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