Explanation The given expression is ( x + y ) 1 2 ≠ x 1 2 + y 1 2 . It is enough to show that the left hand side is not equal to the right hand side of the expression. There are so many choices for x and y to prove this. Consider the case when x = y = 1 . Substitute the values x = y = 1 in ( x + y ) 1 2 and x 1 2 + y 1 2

Calculus for Business, Economics, Life Sciences, and Social Sciences - Boston U.

15th Edition

ISBN: 9781323047620

Author: Barnett, Ziegler, Byleen

Publisher: Pearson Education

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Chapter A.6, Problem 67E

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To find: The numerical example to prove (x+y)12≠x12+y12.

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Chapter A.6, Problem 66E

Chapter A.6, Problem 68E

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Chapter A.6 Solutions

Calculus for Business, Economics, Life Sciences, and Social Sciences - Boston U.

Ch. A.6 - Evaluate each of the following: (A)161/2 (B)16...Ch. A.6 - Convert to radical form. (A)u1/5 (B)(6x2y5)2/9...Ch. A.6 - Prob. 3MP Ch. A.6 - Prob. 4MP Ch. A.6 - Write the following expression in the form axp +...Ch. A.6 - Prob. 6MP Ch. A.6 - Prob. 7MP Ch. A.6 - Rationalize each numerator. (A)332 (B)2n4n...Ch. A.6 - Change each expression in Problems 16 to radical...Ch. A.6 - Change each expression in Problems 16 to radical...

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The numerical example to prove ( x + y ) 1 2 ≠ x 1 2 + y 1 2 .

Solution Summary: The author explains the numerical example to prove (x+y)12ne, which shows that the left hand side is not equal to the right.

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To find: The numerical example to prove (x+y)12≠x12+y12.

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Chapter A.6 Solutions