Explanation Definition used: Rational Exponents: “If m and n are natural numbers without common prime factors, b is a real number, and b is non-negative when n is even, then b m n = { ( b 1 n ) m = ( b n ) m ( b m ) 1 n = b m n and b − m n = 1 b m n , b ≠ 0 ”. Calculation: Multiply the expression ( 6 m 1 2 + n − 1 2 ) ( 6 m − n − 1 2 ) and simplify it into simple form using positive exponents as follows. ( 6 m 1 2 + n − 1 2 ) ( 6 m − n − 1 2 ) = 6 m 1 2 ( 6 m − n − 1 2 ) + n − 1 2 ( 6 m − n − 1 2 ) = 6 ( 6 ) m 1 2 + 1 − 6 m 1 2 n −

Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)

14th Edition

ISBN: 9780134668574

Author: Raymond A. Barnett, Michael R. Ziegler, Karl E. Byleen, Christopher J. Stocker

Publisher: PEARSON

See similar textbooks

Concept explainers

Percentage

A percentage is a number indicated as a fraction of 100. It is a dimensionless number often expressed using the symbol %.

Algebraic Expressions

In mathematics, an algebraic expression consists of constant(s), variable(s), and mathematical operators. It is made up of terms.

Numbers

Numbers are some measures used for counting. They can be compared one with another to know its position in the number line and determine which one is greater or lesser than the other.

Subtraction

Before we begin to understand the subtraction of algebraic expressions, we need to list out a few things that form the basis of algebra.

Addition

Before we begin to understand the addition of algebraic expressions, we need to list out a few things that form the basis of algebra.

Videos

Question

Chapter A.6, Problem 45E

To determine

To simplify: The expression (6m12+n−12)(6m−n−12) using positive exponents only.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter A.6, Problem 44E

Chapter A.6, Problem 46E

Students have asked these similar questions

By considering appropriate series expansions, prove that ez · e²²/2 . e²³/3 . ... = 1 + x + x² + · ·. when <1.

Prove that Σ prime p≤x p=3 (mod 10) 1 Р = for some constant A. log log x + A+O 1 log x ,

Let Σ 1 and g(x) = Σ logp. f(x) = prime p≤x p=3 (mod 10) prime p≤x p=3 (mod 10) g(x) = f(x) logx - Ր _☑ t¯¹ƒ(t) dt. Assuming that f(x) ~ 1½π(x), prove that g(x) ~ 1x. 米 (You may assume the Prime Number Theorem: 7(x) ~ x/log x.) *

Chapter A.6 Solutions

Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)

Ch. A.6 - Evaluate each of the following: (A)161/2 (B)16...Ch. A.6 - Convert to radical form. (A)u1/5 (B)(6x2y5)2/9...Ch. A.6 - Prob. 3MP Ch. A.6 - Prob. 4MP Ch. A.6 - Write the following expression in the form axp +...Ch. A.6 - Prob. 6MP Ch. A.6 - Prob. 7MP Ch. A.6 - Rationalize each numerator. (A)332 (B)2n4n...Ch. A.6 - Change each expression in Problems 16 to radical...Ch. A.6 - Change each expression in Problems 16 to radical...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.

The expression ( 6 m 1 2 + n − 1 2 ) ( 6 m − n − 1 2 ) using positive exponents only.

Solution Summary: The author explains how to simplify the expression (6m12) using positive exponents only.

Concept explainers

Videos

To simplify: The expression (6m12+n−12)(6m−n−12) using positive exponents only.

Want to see the full answer?

Chapter A.6 Solutions