Chapter A.5, Problem 6AYU

To determine

To find: Reduced to lowest terms.

Answer to Problem 6AYU

$\frac{x}{3}$

Explanation of Solution

Given:

$\frac{4x^2+8x}{12x+24}$

Calculation:

$\frac{4x^2+8x}{12x+24}=\frac{4x\left(x+2\right)}{12\left(x+2\right)}=\frac{4x}{12}=\frac{x}{3}$