Chapter A.5, Problem 11AYU

To determine

To find: Reduce lowest terms.

Answer to Problem 11AYU

$\frac{\left(y+5\right)}{2\left(y+1\right)}$

Explanation of Solution

Given:

$\frac{y^2-25}{2y^2-8y-10}$

Calculation:

$\frac{y^2-25}{2y^2-8y-10}=\frac{y^2-5^2}{2(y^2-4y-5)}=\frac{\left(y+5\right)\left(y-5\right)}{2\left(y-5\right)\left(y+1\right)}=\frac{\left(y+5\right)}{2\left(y+1\right)}$