Explanation Definition used: A number expressed in the form a × 10 n , 1 ≤ a ≤ 10 , where a is in decimal form and n is an integer, is said to be in scientific notation. Theorem used: Exponent Properties For n and m integers and a and b real numbers, a m a n = a m + n a m a n = a m − n = 1 a n − m , a ≠ 0 Calculation: Consider the number ( 60 , 000 ) ( 0.000003 ) ( 0.0004 ) ( 1 , 500 , 000 ) . The above number can be expressed as follows. ( 60 , 000 ) ( 0.000003 ) ( 0.0004 ) ( 1 , 500 , 000 ) = ( 0 .6 × 10 5 ) ( 0.3 × 10 − 5 ) ( 0.4 × 10 − 3 ) ( 1.5 × 10 6 ) Then by the above stated definition, the scientific notation of the number 9,600,000,000 ( 1,600,000 ) ( 0 .000000 25 ) is ( 0 .6 × 10 5 ) ( 0.3 × 10 − 5 ) ( 0.4 × 10 − 3 ) ( 1.5 × 10 6 ) . Simplify the expression ( 0 .6 × 10 5 ) ( 0.3 × 10 − 5 ) ( 0.4 × 10 − 3 ) ( 1.5 × 10 6 ) as follows ( 0

Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)

14th Edition

ISBN: 9780134668574

Author: Raymond A. Barnett, Michael R. Ziegler, Karl E. Byleen, Christopher J. Stocker

Publisher: PEARSON

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Chapter A.5, Problem 48E

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To convert: The number (60,000)(0.000003)(0.0004)(1,500,000) to scientific notation and simplify it.

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Chapter A.5, Problem 47E

Chapter A.5, Problem 49E

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Chapter A.5 Solutions

Calculus for Business, Economics, Life Sciences, and Social Sciences (14th Edition)

Ch. A.5 - Simplify, and express the answers using positive...Ch. A.5 - Prob. 2MP Ch. A.5 - (A)Write each number in scientific notation:...Ch. A.5 - In Problems 114, simplify and express answers...Ch. A.5 - Prob. 2E Ch. A.5 - Prob. 3E Ch. A.5 - Prob. 4E Ch. A.5 - In Problems 114, simplify and express answers...Ch. A.5 - Prob. 6E Ch. A.5 - Prob. 7E

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The number ( 60 , 000 ) ( 0.000003 ) ( 0.0004 ) ( 1 , 500 , 000 ) to scientific notation and simplify it.

Solution Summary: The author explains the scientific notation of the number (60,000), where a is in decimal form and n is an integer.

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To convert: The number (60,000)(0.000003)(0.0004)(1,500,000) to scientific notation and simplify it.

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Chapter A.5 Solutions