Chapter A.2, Problem 36AYU

To determine

To find: The volume $V$ and surface area $S$ of a closed right circular cylinder with radius 8 inches and height 9 inches.

Answer to Problem 36AYU

$V=576\pi {\text{in}}^3$ and $S=272\pi {\text{in}}^2$.

Explanation of Solution

Formula Used:

Volume $V=\pi r^{2}h$ and surface area $S=2\pi r^2+2\pi rh$.

Volume of a right circular cylinder $V=\pi r^{2}h=\pi {\left(8\right)}^2\times 9=576\pi {\text{in}}^3$.

Surface area of a right circular cylinder.

$S=2\pi r^2+2\pi rh=2\pi \times 8^2+2\pi \times 8\times 9=272\pi {\text{in}}^2$