Precalculus: A Unit Circle Approach (3rd Edition)
3rd Edition
ISBN: 9780134433042
Author: J. S. Ratti, Marcus S. McWaters, Leslaw Skrzypek
Publisher: PEARSON
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Chapter A.1, Problem 119E
To determine
To simplify the expression and write the answer without negative exponents.
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Students have asked these similar questions
Given lim x-4 f (x) = 1,limx-49 (x) = 10, and lim→-4 h (x) = -7 use the limit properties
to find lim→-4
1
[2h (x) — h(x) + 7 f(x)] :
-
h(x)+7f(x)
3
O DNE
17. Suppose we know that the graph below is the graph of a solution to dy/dt = f(t).
(a) How much of the slope field can
you sketch from this information?
[Hint: Note that the differential
equation depends only on t.]
(b) What can you say about the solu-
tion with y(0) = 2? (For example,
can you sketch the graph of this so-
lution?)
y(0) = 1
y
AN
(b) Find the (instantaneous) rate of change of y at x = 5.
In the previous part, we found the average rate of change for several intervals of decreasing size starting at x = 5. The instantaneous rate of
change of fat x = 5 is the limit of the average rate of change over the interval [x, x + h] as h approaches 0. This is given by the derivative in the
following limit.
lim
h→0
-
f(x + h) − f(x)
h
The first step to find this limit is to compute f(x + h). Recall that this means replacing the input variable x with the expression x + h in the rule
defining f.
f(x + h) = (x + h)² - 5(x+ h)
=
2xh+h2_
x² + 2xh + h² 5✔
-
5
)x - 5h
Step 4
-
The second step for finding the derivative of fat x is to find the difference f(x + h) − f(x).
-
f(x + h) f(x) =
= (x²
x² + 2xh + h² -
])-
=
2x
+ h² - 5h
])x-5h) - (x² - 5x)
=
]) (2x + h - 5)
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Chapter A.1 Solutions
Precalculus: A Unit Circle Approach (3rd Edition)
Ch. A.1 - In Exercises 1-4, write each of the following...Ch. A.1 - In Exercises 1-4, write each of the following...Ch. A.1 - In Exercises 1-4, write each of the following...Ch. A.1 - Prob. 4ECh. A.1 - Prob. 5ECh. A.1 - Prob. 6ECh. A.1 - Prob. 7ECh. A.1 - Prob. 8ECh. A.1 - In Exercises 5-10, classify each of the following...Ch. A.1 - Prob. 10E
Ch. A.1 - Prob. 11ECh. A.1 - Prob. 12ECh. A.1 - Prob. 13ECh. A.1 - Prob. 14ECh. A.1 - Prob. 15ECh. A.1 - Prob. 16ECh. A.1 - Prob. 17ECh. A.1 - Prob. 18ECh. A.1 - Prob. 19ECh. A.1 - Prob. 20ECh. A.1 - Prob. 21ECh. A.1 - Prob. 22ECh. A.1 - Prob. 23ECh. A.1 - Prob. 24ECh. A.1 -
In Exercises 25-38, rewrite each expression...Ch. A.1 - Prob. 26ECh. A.1 - Prob. 27ECh. A.1 - Prob. 28ECh. A.1 - Prob. 29ECh. A.1 - Prob. 30ECh. A.1 - Prob. 31ECh. A.1 - Prob. 32ECh. A.1 - Prob. 33ECh. A.1 - Prob. 34ECh. A.1 - Prob. 35ECh. A.1 - Prob. 36ECh. A.1 - Prob. 37ECh. A.1 - Prob. 38ECh. A.1 - Prob. 39ECh. A.1 - Prob. 40ECh. A.1 - Prob. 41ECh. A.1 - Prob. 42ECh. A.1 - Prob. 43ECh. A.1 - Prob. 44ECh. A.1 - Prob. 45ECh. A.1 - Prob. 46ECh. A.1 - Prob. 47ECh. A.1 - Prob. 48ECh. A.1 - Prob. 49ECh. A.1 - Prob. 50ECh. A.1 - Prob. 51ECh. A.1 - Prob. 52ECh. A.1 - Prob. 53ECh. A.1 - Prob. 54ECh. A.1 - Prob. 55ECh. A.1 - Prob. 56ECh. A.1 - Prob. 57ECh. A.1 - Prob. 58ECh. A.1 - Prob. 59ECh. A.1 - Prob. 60ECh. A.1 - Prob. 61ECh. A.1 - Prob. 62ECh. A.1 - Prob. 63ECh. A.1 - Prob. 64ECh. A.1 - Prob. 65ECh. A.1 - Prob. 66ECh. A.1 - Prob. 67ECh. A.1 -
In Exercises 59-68, evaluate each expression for...Ch. A.1 - Prob. 69ECh. A.1 - Prob. 70ECh. A.1 - Prob. 71ECh. A.1 - Prob. 72ECh. A.1 - Prob. 73ECh. A.1 - Prob. 74ECh. A.1 - Prob. 75ECh. A.1 - Prob. 76ECh. A.1 - Prob. 77ECh. A.1 - Prob. 78ECh. A.1 - Prob. 79ECh. A.1 - Prob. 80ECh. A.1 - Prob. 81ECh. A.1 - Prob. 82ECh. A.1 - Prob. 83ECh. A.1 - Prob. 84ECh. A.1 - Prob. 85ECh. A.1 - Prob. 86ECh. A.1 - Prob. 87ECh. A.1 - Prob. 88ECh. A.1 - Prob. 89ECh. A.1 - Prob. 90ECh. A.1 - Prob. 91ECh. A.1 - Prob. 92ECh. A.1 - Prob. 93ECh. A.1 - Prob. 94ECh. A.1 - Prob. 95ECh. A.1 - Prob. 96ECh. A.1 - Prob. 97ECh. A.1 - Prob. 98ECh. A.1 - Prob. 99ECh. A.1 - Prob. 100ECh. A.1 - Prob. 101ECh. A.1 - Prob. 102ECh. A.1 - Prob. 103ECh. A.1 - Prob. 104ECh. A.1 - Prob. 105ECh. A.1 - Prob. 106ECh. A.1 - Prob. 107ECh. A.1 - Prob. 108ECh. A.1 - Prob. 109ECh. A.1 - In Exercises 101-134, simplify each expression....Ch. A.1 - Prob. 111ECh. A.1 - Prob. 112ECh. A.1 - Prob. 113ECh. A.1 - Prob. 114ECh. A.1 - Prob. 115ECh. A.1 - Prob. 116ECh. A.1 - Prob. 117ECh. A.1 - Prob. 118ECh. A.1 - Prob. 119ECh. A.1 - Prob. 120ECh. A.1 - Prob. 121ECh. A.1 - Prob. 122ECh. A.1 - Prob. 123ECh. A.1 - Prob. 124ECh. A.1 - Prob. 125ECh. A.1 - Prob. 126ECh. A.1 - Prob. 127ECh. A.1 - Prob. 128ECh. A.1 - Prob. 129ECh. A.1 - Prob. 130ECh. A.1 - Prob. 131ECh. A.1 - Prob. 132ECh. A.1 - Prob. 133ECh. A.1 - Prob. 134ECh. A.1 - Prob. 135ECh. A.1 - Prob. 136ECh. A.1 - Prob. 137ECh. A.1 - Prob. 138ECh. A.1 - Prob. 139ECh. A.1 - Prob. 140ECh. A.1 - Prob. 141ECh. A.1 - Prob. 142E
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- Evaluate the integral using integration by parts. Sx² cos (9x) dxarrow_forwardLet f be defined as follows. y = f(x) = x² - 5x (a) Find the average rate of change of y with respect to x in the following intervals. from x = 4 to x = 5 from x = 4 to x = 4.5 from x = 4 to x = 4.1 (b) Find the (instantaneous) rate of change of y at x = 4. Need Help? Read It Master Itarrow_forwardVelocity of a Ball Thrown into the Air The position function of an object moving along a straight line is given by s = f(t). The average velocity of the object over the time interval [a, b] is the average rate of change of f over [a, b]; its (instantaneous) velocity at t = a is the rate of change of f at a. A ball is thrown straight up with an initial velocity of 128 ft/sec, so that its height (in feet) after t sec is given by s = f(t) = 128t - 16t². (a) What is the average velocity of the ball over the following time intervals? [3,4] [3, 3.5] [3, 3.1] ft/sec ft/sec ft/sec (b) What is the instantaneous velocity at time t = 3? ft/sec (c) What is the instantaneous velocity at time t = 7? ft/sec Is the ball rising or falling at this time? O rising falling (d) When will the ball hit the ground? t = sec Need Help? Read It Watch Itarrow_forward
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