To prove: The simplest form of the expression 2 3 x ( 2 x − 3 ) 3 2 − 2 15 ( 2 x − 3 ) 5 2 is 2 5 x ( 2 x − 3 ) 3 2 − 2 15 ( 2 x − 3 ) 5 2 . Also, use the same technique to simplify the expression 2 3 x ( 4 + x ) 3 2 − 2 15 ( 4 + x ) 5 2 .

Question

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Answer 1

Question

Chapter A, Problem 62E

To determine

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52.

Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.

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Now consider equations of the form ×-a=v = √bx + c, where a, b, and c are all positive integers and b>1. (f) Create an equation of this form that has 7 as a solution and an extraneous solution. Give the extraneous solution. (g) What must be true about the value of bx + c to ensure that there is a real number solution to the equation? Explain.

The equation ×+ 2 = √3x+10 is of the form ×+ a = √bx + c, where a, b, and c are all positive integers and b > 1. Using this equation as a model, create your own equation that has extraneous solutions. (d) Using trial and error with numbers for a, b, and c, create an equation of the form x + a = √bx + c, where a, b, and c are all positive integers and b>1 such that 7 is a solution and there is an extraneous solution. (Hint: Substitute 7 for x, and choose a value for a. Then square both sides so you can choose a, b, and c that will make the equation true.) (e) Solve the equation you created in Part 2a.

Answer 2

Question

Chapter A, Problem 62E

To determine

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52.

Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.

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Answer 3

Question

Chapter A, Problem 62E

To determine

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52.

Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.

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Answer 4

Question

Chapter A, Problem 62E

To determine

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52.

Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.

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Answer 5

Chapter A, Problem 62E

To determine

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52.

Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.

Answer 6

Chapter A, Problem 62E

To determine

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52.

Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.

Answer 7

Chapter A, Problem 62E

To determine

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52.

Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. A - Describe and correct the error. x2+4=x+2 Ch. A - Prob. 2ECP Ch. A - Prob. 3ECP Ch. A - Prob. 4ECP Ch. A - Prob. 5ECP Ch. A - Rewrite each fraction as the sum of three terms....Ch. A - Prob. 1E Ch. A - Fill in the blanks. When dividing fractions,...Ch. A - Prob. 3E Ch. A - Prob. 4E

To prove: The simplest form of the expression 2 3 x ( 2 x − 3 ) 3 2 − 2 15 ( 2 x − 3 ) 5 2 is 2 5 x ( 2 x − 3 ) 3 2 − 2 15 ( 2 x − 3 ) 5 2 . Also, use the same technique to simplify the expression 2 3 x ( 4 + x ) 3 2 − 2 15 ( 4 + x ) 5 2 .

Solution Summary: The author explains how to simplify the expression by adding tions with unlike denominators.

Videos

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52.

Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.

Want to see the full answer?

Chapter A Solutions

To prove: The simplest form of the expression 2 3 x ( 2 x − 3 ) 3 2 − 2 15 ( 2 x − 3 ) 5 2 is 2 5 x ( 2 x − 3 ) 3 2 − 2 15 ( 2 x − 3 ) 5 2 . Also, use the same technique to simplify the expression 2 3 x ( 4 + x ) 3 2 − 2 15 ( 4 + x ) 5 2 .

Solution Summary: The author explains how to simplify the expression by adding tions with unlike denominators.

Videos

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52. Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.

Want to see the full answer?

Chapter A Solutions

To prove: The simplest form of the expression 23x(2x−3)32−215(2x−3)52 is 25x(2x−3)32−215(2x−3)52.

Also, use the same technique to simplify the expression 23x(4+x)32−215(4+x)52.