Concept explainers
Wildlife Management. A common technique for estimating populations of birds or fish is to tag and release individual animals in two different outings. This procedure is called catch and release. If the wildlife remain in the sampling area and are randomly caught, a fraction of the animals tagged during the first outing are likely to be caught again during the second outing. Based on the number tagged and the fraction caught twice, the total number of animals in the area can be estimated. a. Consider a case in which 200 fish are lagged and released during the first outing. During a second outing in the same area, 200 fish are again caught and released, of which one- hall ate already tagged. Estimate N, the total number of fish In the entire sampling area. Explain your reasoning. b. Consider a case in which 200 fish ate tagged and released during the lira outing. During a second outing in the same area, 200 fish ate again caught and released, of which one- fourth are already tagged. Estimate N the total number of fish to the entire sampling area Explain your reasoning. c. Generalize your results hum parts (a) and (b) by letting p be the fraction of tagged fish that are caught during the second outing. Find a formula for the function N = f(p) that relates the total number of fish, N, to the fraction lagged during the second outing, p. d. Graph the function obtained in part (c). What is the domain? Explain. e. Suppose that 15% of the fish in the second sample are tagged. Use the formula hum part (c) to estimate the total number of fish in the sampling area. Confirm your result on your graph. f. Locate a real study in which catch and release methods were used. Report on the specific details of the study and how closely it followed the theory outlined in this problem.
Want to see the full answer?
Check out a sample textbook solutionChapter 9 Solutions
EP USING+UNDERSTANDING MATH.-MYMATHLAB
- use a graphing utility to sketch the graph of the function and then use the graph to help identify or approximate the domain and range of the function. f(x)=xsqrt(9-(x^2))arrow_forward4. Select all of the solutions for x²+x - 12 = 0? A. -12 B. -4 C. -3 D. 3 E 4 F 12 4 of 10arrow_forward2. Select all of the polynomials with the degree of 7. A. h(x) = (4x + 2)³(x − 7)(3x + 1)4 B h(x) = (x + 7)³(2x + 1)^(6x − 5)² ☐ Ch(x)=(3x² + 9)(x + 4)(8x + 2)ª h(x) = (x + 6)²(9x + 2) (x − 3) h(x)=(-x-7)² (x + 8)²(7x + 4)³ Scroll down to see more 2 of 10arrow_forward
- 1. If all of the zeros for a polynomial are included in the graph, which polynomial could the graph represent? 100 -6 -2 0 2 100 200arrow_forward3. Select the polynomial that matches the description given: Zero at 4 with multiplicity 3 Zero at −1 with multiplicity 2 Zero at -10 with multiplicity 1 Zero at 5 with multiplicity 5 ○ A. P(x) = (x − 4)³(x + 1)²(x + 10)(x — 5)³ B - P(x) = (x + 4)³(x − 1)²(x − 10)(x + 5)³ ○ ° P(x) = (1 − 3)'(x + 2)(x + 1)"'" (x — 5)³ 51 P(r) = (x-4)³(x − 1)(x + 10)(x − 5 3 of 10arrow_forwardMatch the equation, graph, and description of transformation. Horizontal translation 1 unit right; vertical translation 1 unit up; vertical shrink of 1/2; reflection across the x axis Horizontal translation 1 unit left; vertical translation 1 unit down; vertical stretch of 2 Horizontal translation 2 units right; reflection across the x-axis Vertical translation 1 unit up; vertical stretch of 2; reflection across the x-axis Reflection across the x - axis; vertical translation 2 units down Horizontal translation 2 units left Horizontal translation 2 units right Vertical translation 1 unit down; vertical shrink of 1/2; reflection across the x-axis Vertical translation 2 units down Horizontal translation 1 unit left; vertical translation 2 units up; vertical stretch of 2; reflection across the x - axis f(x) = - =-½ ½ (x − 1)²+1 f(x) = x²-2 f(x) = -2(x+1)²+2 f(x)=2(x+1)²-1 f(x)=-(x-2)² f(x)=(x-2)² f(x) = f(x) = -2x²+1 f(x) = -x²-2 f(x) = (x+2)²arrow_forward
- What is the vertex, increasing interval, decreasing interval, domain, range, root/solution/zero, and the end behavior?arrow_forwardCalculate a (bxc) where a = i, b = j, and c = k.arrow_forwardi+2j+3k = (1,2,3) and b = -i-k. Calculate the cross product a x b where a Next calculate the area of the parallelogram spanned by a and b.arrow_forward
- The measured receptance data around two resonant picks of a structure are tabulated in the followings. Find the natural frequencies, damping ratios, and mode shapes of the structure. (30 points) (@)×10 m/N α₁₂ (@)×10 m/N w/2z (Hz) 99 0.1176 0.17531 0.1114 -0.1751i 101 -0.0302 0.2456i -0.0365 -0.2453i 103 -0.1216 0.1327i -0.1279-0.1324i 220 0.0353 0.0260i -0.0419+0.0259i 224 0.0210 0.0757i |-0.0273 +0.0756i 228 -0.0443 0.0474i 0.0382 +0.0474iarrow_forwardQ3: Define the linear functional J: H(2) R by 1(v) = a(v. v) - L(v) Let u be the unique weak solution to a(u,v) = L(v) in H() and suppose that a(...) is a symmetric bilinear form on H(2) prove that 1- u is minimizer. 2- u is unique. 3- The minimizer J(u,) can be rewritten under algebraic form u Au-ub. J(u)=u'Au- Where A. b are repictively the stiffence matrix and the load vectorarrow_forward== 1. A separable differential equation can be written in the form hy) = g(a) where h(y) is a function of y only, and g(x) is a function of r only. All of the equations below are separable. Rewrite each of these in the form h(y) = g(x), then find a general solution by integrating both sides. Determine whether the solutions you found are explicit (functions) or implicit (curves but not functions) (a) 1' = — 1/3 (b) y' = = --- Y (c) y = x(1+ y²)arrow_forward
- Holt Mcdougal Larson Pre-algebra: Student Edition...AlgebraISBN:9780547587776Author:HOLT MCDOUGALPublisher:HOLT MCDOUGALGlencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw HillCollege Algebra (MindTap Course List)AlgebraISBN:9781305652231Author:R. David Gustafson, Jeff HughesPublisher:Cengage Learning
- Big Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt