Finding the Interval of Convergence In Exercises 15-38, find the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interval.)30.
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- Determine whether the sum of the infinite series is defined. k=115(0.3)karrow_forwardDetermine if the series converges or divergesarrow_forwardetermine whether the alternating series Σ (-1)+1 n=2 1 3(In n)² converges or diverges Choose the correct answer below and, if necessary, fill in the answer box to complete your choice. OA. The series does not satisfy the conditions of the Alternating Series Test but diverges because it is a p-series with p= OB. The series does not satisfy the conditions of the Alternating Series Test but converges because it is a p-series with p= OC. The series does not satisfy the conditions of the Alternating Series Test but diverges by the Root Test because the limit used does not exist. OD. The series does not satisfy the conditions of the Alternating Series Test but converges because it is a geometric series with r= OE. The series converges by the Alternating Series Testarrow_forward
- (-1)* /ī Given the series E " determine if the series converges conditionally, converges absolutely or diverges and select the test used to make your decision. Select the correct choice from each dropdown.arrow_forward00 ()" Determine whether the alternating series 2 (- 1)" converges or diverges. n= 1 Choose the correct answer below and, if necessary, fill in the answer box to complete your choice. A. The series converges by the Alternating Series Test. B. The series does not satisfy the conditions of the Alternating Series Test but converges because it is a geometric series with r= C. The series does not satisfy the conditions of the Alternating Series Test but converges because it is a p-series with p = D. The series does not satisfy the conditions of the Alternating Series Test but diverges because it is a p-series with p = E. The series does not satisfy the conditions of the Alternating Series Test but diverges by the Root Test because the limit used does not exist.arrow_forwardfind the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interval.)arrow_forward
- Tutorial Exercise Find the interval of convergence of the power series. (Be sure to include a check for convergence at the endpoints of the interval.) W (4x) no (3m)! Step 1 Recall the Ratio Test, which states that if a, is a series with nonzero terms, and lim 1, or lim =o, then diverges For any fixed value of x such that x = 0, let a (4x)" (3n)1 and find lim 918 (4x)+1 lim (3(n + 1))! = lim (4x) (an) lim (4x)+1 518 (3(n-1))! (3n)! 88,0 4x × (-00,00) X Step 2 By the Ratio Test, the series converges if lim -21. Therefore, the series converges for x such that lim an Submit Skip (you cannot come back)arrow_forwardHow to do this?arrow_forward∞ Expand the function in a power series Σ anx" with center c = 0. Find anx". 7+6x n=0 (Express numbers in exact form. Use symbolic notation and fractions where needed. For alternating series, include a factor of the form (-1)" in your answer.) anxh Determine the interval of convergence. (Give your answers as intervals in the form (*, *). Use symbol ∞ for infinity, U for combining intervals, and appropriate type of "1 parenthesis (",") ", "[" or "]" depending on whether the interval is open or closed. Enter DNE if interval is empty. Express numbers in exact form. Use symbolic notation and fractions where needed.) x E =arrow_forward
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