
Vector Mechanics for Engineers: Statics
12th Edition
ISBN: 9781259977244
Author: BEER
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 9.6, Problem 9.162P
(a)
To determine
Find the mass product of inertia
(b)
To determine
Deduce
Expert Solution & Answer

Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A simply supported T-shaped beam of 6m in length has to be
designed to carry an inclined central point load W. Find the max-
imum value of this load such that the maximum tensile and com-
pression stresses on the beam do not exceed 30 and 60
respectively.
N
mm²
N
mm²,
90 mm
80 mm
Y
W
60 mm
30°
10 mm
10 mm
X
Problem 9.5
9.5 A 1080-kg car is parked on a sloped street. The figure shows its wheels and the position of
its center of mass. The street is icy, and as a result the coefficient of static friction between
the car's tires and the street surface is μs = 0.2. Determine the steepest slope (in degrees
relative to the horizontal) at which the car could remain in equilibrium if
a. the brakes are applied to both its front and rear wheels;
b. the brakes are applied to the front (lower) wheels only.
Problem 9.5
1380 mm
532 mm
2370 mm
Can someone explain please with conversions
Chapter 9 Solutions
Vector Mechanics for Engineers: Statics
Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - 9.1 through 9.4 Determine by direct integration...Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - 9.5 through 9.8 Determine by direct integration...Ch. 9.1 - 9.9 through 9.11 Determine by direct integration...Ch. 9.1 - 9.9 through 9.11 Determine by direct integration...
Ch. 9.1 - 9.9 through 9.11 Determine by direct integration...Ch. 9.1 - 9.12 through 9.14 Determine by direct integration...Ch. 9.1 - Prob. 9.13PCh. 9.1 - 9.12 through 9.14 Determine by direct integration...Ch. 9.1 - 9.15 and 9.16 Determine the moment of inertia and...Ch. 9.1 - Prob. 9.16PCh. 9.1 - 9.17 and 9.18 Determine the moment of inertia and...Ch. 9.1 - Prob. 9.18PCh. 9.1 - Determine the moment of inertia and the radius of...Ch. 9.1 - Prob. 9.20PCh. 9.1 - Prob. 9.21PCh. 9.1 - Determine the polar moment of inertia and the...Ch. 9.1 - 9.23 and 9.24 Determine the polar moment of...Ch. 9.1 - 9.23 and 9.24 Determine the polar moment of...Ch. 9.1 - (a) Determine by direct integration the polar...Ch. 9.1 - (a) Show that the polar radius of gyration kQ of...Ch. 9.1 - Determine the polar moment of inertia and the...Ch. 9.1 - Determine the polar moment of inertia and the...Ch. 9.1 - Using the polar moment of inertia of the isosceles...Ch. 9.1 - Prove that the centroidal polar moment of inertia...Ch. 9.2 - 9.31 and 9.32 Determine the moment of inertia and...Ch. 9.2 - 9.31 and 9.32 Determine the moment of inertia and...Ch. 9.2 - 9.33 and 9.34 Determine the moment of inertia and...Ch. 9.2 - 9.33 and 9.34 Determine the moment of inertia and...Ch. 9.2 - Prob. 9.35PCh. 9.2 - Determine the moments of inertia of the shaded...Ch. 9.2 - Prob. 9.37PCh. 9.2 - Fig. P9.37 and P9.38 9.38 Knowing that the shaded...Ch. 9.2 - Prob. 9.39PCh. 9.2 - Fig. P9.39 and P9.40 9.40 The polar moments of...Ch. 9.2 - Prob. 9.41PCh. 9.2 - 9.41 through 9.44 Determine the moments of inertia...Ch. 9.2 - 9.41 through 9.44 Determine the moments of inertia...Ch. 9.2 - 9.41 through 9.44 Determine the moments of inertia...Ch. 9.2 - 9.45 and 9.46 Determine the polar moment of...Ch. 9.2 - 9.45 and 9.46 Determine the polar moment of...Ch. 9.2 - Prob. 9.47PCh. 9.2 - Prob. 9.48PCh. 9.2 - Prob. 9.49PCh. 9.2 - Prob. 9.50PCh. 9.2 - Four L3 3 14 - in. angles are welded to a rolled...Ch. 9.2 - Two 20-mm steel plates are welded to a rolled S...Ch. 9.2 - A channel and a plate are welded together as shown...Ch. 9.2 - The strength of the rolled W section shown is...Ch. 9.2 - Two L76 76 6.4-mm angles are welded to a C250 ...Ch. 9.2 - Two steel plates are welded to a rolled W section...Ch. 9.2 - 9.57 and 9.58 The panel shown forms the end of a...Ch. 9.2 - 9.57 and 9.58 The panel shown forms the end of a...Ch. 9.2 - 9.59 and 9.60 The panel shown forms the end of a...Ch. 9.2 - 9.59 and 9.60 The panel shown forms the end of a...Ch. 9.2 - A vertical trapezoidal gate that is used as an...Ch. 9.2 - The cover for a 0.5-m-diameter access hole in a...Ch. 9.2 - Determine the x coordinate of the centroid of the...Ch. 9.2 - Determine the x coordinate of the centroid of the...Ch. 9.2 - Show that the system of hydrostatic forces acting...Ch. 9.2 - Show that the resultant of the hydrostatic forces...Ch. 9.3 - 9.67 through 9.70 Determine by direct integration...Ch. 9.3 - 9.67 through 9.70 Determine by direct integration...Ch. 9.3 - 9.67 through 9.70 Determine by direct integration...Ch. 9.3 - Prob. 9.70PCh. 9.3 - 9.71 through 9.74 Using the parallel-axis theorem,...Ch. 9.3 - 9.71 through 9.74 Using the parallel-axis theorem,...Ch. 9.3 - 9.71 through 9.74 Using the parallel-axis theorem,...Ch. 9.3 - Prob. 9.74PCh. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - Prob. 9.78PCh. 9.3 - Determine for the quarter ellipse of Prob. 9.67...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - 9.75 through 9.78 Using the parallel-axis theorem,...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - Determine the moments of inertia and the product...Ch. 9.3 - Prob. 9.85PCh. 9.3 - 9.86 through 9.88 For the area indicated,...Ch. 9.3 - 9.86 through 9.88 For the area indicated,...Ch. 9.3 - 9.86 through 9.88 For the area indicated,...Ch. 9.3 - 9.89 and 9.90 For the angle cross section...Ch. 9.3 - 9.89 and 9.90 For the angle cross section...Ch. 9.4 - Using Mohrs circle, determine for the quarter...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - Using Mohrs circle, determine the moments of...Ch. 9.4 - For the quarter ellipse of Prob. 9.67, use Mohrs...Ch. 9.4 - Prob. 9.98PCh. 9.4 - 9.98 though 9.102 Using Mohrs circle, determine...Ch. 9.4 - 9.98 though 9.102 Using Mohrs circle, determine...Ch. 9.4 - 9.98 through 9.102 Using Mohrs circle, determine...Ch. 9.4 - 9.98 through 9.102 Using Mohrs circle, determine...Ch. 9.4 - Prob. 9.103PCh. 9.4 - 9.104 and 9.105 Using Mohrs circle, determine the...Ch. 9.4 - 9.104 and 9.105 Using Mohrs circle, determine the...Ch. 9.4 - Prob. 9.106PCh. 9.4 - it is known that for a given area Iy = 48 106 mm4...Ch. 9.4 - Prob. 9.108PCh. 9.4 - Using Mohrs circle, prove that the expression...Ch. 9.4 - Using the invariance property established in the...Ch. 9.5 - A thin plate with a mass m is cut in the shape of...Ch. 9.5 - A ring with a mass m is cut from a thin uniform...Ch. 9.5 - Prob. 9.113PCh. 9.5 - The parabolic spandrel shown was cut from a thin,...Ch. 9.5 - Prob. 9.115PCh. 9.5 - Fig. P9.115 and P9.116 9.116 A piece of thin,...Ch. 9.5 - A thin plate of mass m is cut in the shape of an...Ch. 9.5 - Prob. 9.118PCh. 9.5 - Prob. 9.119PCh. 9.5 - The area shown is revolved about the x axis to...Ch. 9.5 - Prob. 9.121PCh. 9.5 - Determine by direct integration the mass moment of...Ch. 9.5 - Fig. P9.122 and P9.123 9.123 Determine by direct...Ch. 9.5 - Determine by direct integration the mass moment of...Ch. 9.5 - Prob. 9.125PCh. 9.5 - A thin steel wire is bent into the shape shown....Ch. 9.5 - Shown is the cross section of an idler roller....Ch. 9.5 - Shown is the cross section of a molded flat-belt...Ch. 9.5 - Prob. 9.129PCh. 9.5 - Knowing that the thin cylindrical shell shown has...Ch. 9.5 - A circular hole of radius r is to be drilled...Ch. 9.5 - Prob. 9.132PCh. 9.5 - After a period of use, one of the blades of a...Ch. 9.5 - Determine the mass moment of inertia of the 0.9-lb...Ch. 9.5 - 9.135 and 9.136 A 2-mm thick piece of sheet steel...Ch. 9.5 - 9.135 and 9.136 A 2 -mm thick piece of sheet steel...Ch. 9.5 - Prob. 9.137PCh. 9.5 - A section of sheet steel 0.03 in. thick is cut and...Ch. 9.5 - Prob. 9.139PCh. 9.5 - Prob. 9.140PCh. 9.5 - The machine element shown is fabricated from...Ch. 9.5 - Determine the mass moments of inertia and the...Ch. 9.5 - Determine the mass moment of inertia of the steel...Ch. 9.5 - Fig. P9.143 and P9.144 9.144 Determine the mass...Ch. 9.5 - Determine the mass moment of inertia of the steel...Ch. 9.5 - Aluminum wire with a weight per unit length of...Ch. 9.5 - The figure shown is formed of 18-in.-diameter...Ch. 9.5 - A homogeneous wire with a mass per unit length of...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Determine the mass products of inertia Ixy, Iyz,...Ch. 9.6 - Prob. 9.153PCh. 9.6 - Prob. 9.154PCh. 9.6 - 9.153 through 9.156 A section of sheet steel 2 mm...Ch. 9.6 - 9.153 through 9.156 A section of sheet steel 2 mm...Ch. 9.6 - The figure shown is formed of 1.5-mm-diameter...Ch. 9.6 - Prob. 9.158PCh. 9.6 - 9.159 and 9.160 Brass wire with a weight per unit...Ch. 9.6 - Fig. P9.160 9.159 and 9.160 Brass wire with a...Ch. 9.6 - Complete the derivation of Eqs. (9.47) that...Ch. 9.6 - Prob. 9.162PCh. 9.6 - Prob. 9.163PCh. 9.6 - Prob. 9.164PCh. 9.6 - Shown is the machine element of Prob. 9.141....Ch. 9.6 - Determine the mass moment of inertia of the steel...Ch. 9.6 - The thin, bent plate shown is of uniform density...Ch. 9.6 - A piece of sheet steel with thickness t and...Ch. 9.6 - Determine the mass moment of inertia of the...Ch. 9.6 - 9.170 through 9.172 For the wire figure of the...Ch. 9.6 - Prob. 9.171PCh. 9.6 - 9.172 Prob. 9.146 9.146 Aluminum wire with a...Ch. 9.6 - For the homogeneous circular cylinder shown with...Ch. 9.6 - For the rectangular prism shown, determine the...Ch. 9.6 - Prob. 9.175PCh. 9.6 - Prob. 9.176PCh. 9.6 - Consider a cube with mass m and side a. (a) Show...Ch. 9.6 - Prob. 9.178PCh. 9.6 - Prob. 9.179PCh. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9.6 - Prob. 9.182PCh. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9.6 - 9.180 through 9.184 For the component described in...Ch. 9 - Determine by direct integration the moments of...Ch. 9 - Determine the moment of inertia and the radius of...Ch. 9 - Determine the moment of inertia and the radius of...Ch. 9 - Determine the moments of inertia Ix and Iy of the...Ch. 9 - Determine the polar moment of inertia of the area...Ch. 9 - Two L4 4 12-in. angles are welded to a steel...Ch. 9 - Using the parallel-axis theorem, determine the...Ch. 9 - Prob. 9.192RPCh. 9 - Fig. P9.193 and P9.194 9.193 A thin plate with a...Ch. 9 - Fig. P9.193 and P9.194 9.194 A thin plate with...Ch. 9 - A 2-mm-thick piece of sheet steel is cut and bent...Ch. 9 - Determine the mass moment of inertia of the steel...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Correct Answer is written below. Detailed and complete fbd only please. I will upvote, thank you. 1: The assembly shown is composed of a rigid plank ABC, supported by hinge at A, spring at B and cable at C.The cable is attached to a frictionless pulley at D and rigidly supported at E. The cable is made of steel with E = 200,000MPa and cross-sectional area of 500 mm2. The details of pulley at D is shown. The pulley is supported by a pin, passingthough the pulley and attached to both cheeks. Note that E is directly above B.Given: H = 3 m; L1 = 2 m; L2 = 4 m; w = 12 kN/m; x:y = 3:4Spring Parameters:Wire diameter = 30 mmMean Radius = 90 mmNumber of turns = 12Modulus of Rigidity = 80 GPaAllowable stresses:Allowable shear stress of Pin at D = 85 MPaAllowable normal stress of cheek at D = 90MPaAllowable bearing stress of cheek at D = 110MPa1. Calculate the reaction of spring Band tension in cable at C.2. Calculate the vertical displacementat C and the required diameter ofpin at D.3.…arrow_forwardCorrect answer and complete fbd only. I will upvote. The compound shaft, composed of steel,aluminum, and bronze segments, carries the two torquesshown in the figure. If TC = 250 lb-ft, determine the maximumshear stress developed in each material (in ksi). The moduliof rigidity for steel, aluminum, and bronze are 12 x 106 psi, 4x 106 psi, and 6 x 106 psi, respectivelyarrow_forwardCan you explain the algebra steps that aren't shown but stated to be there, on how to get this equationarrow_forward
- Correct answer and complete fbd only. I will upvote. A flanged bolt coupling consists of two concentric rows of bolts. The inner row has 6 nos. of 16mm diameterbolts spaced evenly in a circle of 250mm in diameter. The outer row of has 10 nos. of 25 mm diameter bolts spaced evenly in a circle of 500mm in diameter. If the allowable shear stress on one bolt is 60 MPa, determine the torque capacity of the coupling. The Poisson’s ratio of the inner row of bolts is 0.2 while that of the outer row is 0.25 and the bolts are steel, E =200 GPa.arrow_forwardCorrect answer and complete fbd only. I will upvote. 10: The constant wall thickness of a steel tube with the cross sectionshown is 2 mm. If a 600-N-m torque is applied to the tube. Use G = 80 GPa forsteel.1. Find the shear stress (MPa) in the wall of the tube.2. Find the angle of twist, in degrees per meter of length.arrow_forwardCORRECT ANSWER WITH COMPLETE FBD ONLY. I WILL UPVOTE. A torque wrench is used to tighten the pipe shown.Dimensions: S1 = 400 mm; S2 = 250 mm; S3 = 100 mmModulus of Rigidity G = 78 GPa1. The diameter of the solid pipe is 20 mm. How much is themaximum force P (N) that can be applied based on theallowable shear stress of 60 MPa?2. For a hollow pipe with 50 mm outside diameter and is 6 mmthick, compute for the maximum force P (kN) that can beapplied such that the angle of twist at A does not exceed 5degrees.3. The torque applied to tighten the hollow pipe is 200 N-m.Given: Pipe outside diameter = 50 mm Pipe thickness = 6 mmSolve for the resulting maximum shear stress (MPa) in the pipe.arrow_forward
- Correct answer and complete fbd only. I will upvote. 6: The shaft carries a total torque T0 that is uniformly distributedover its length L. Determine the angle of twist (degrees) of the shaft in termsif T0 = 1.2 kN-m, L = 2 m, G = 80 GPa, and diameter = 120 mm.arrow_forward2. Calculate the force in all members of the trusses shown using the method of joints. A 5525 lb C 3500 lb BY 14'-0" D 10'- 0" 6250 lb 10'- 0" Earrow_forwardCorrect answer and complete fbd only. I will upvote. 8: The steel rod fits loosely inside the aluminum sleeve. Both components are attached to a rigid wall at A andjoined together by a pin at B. Because of a slight misalignmentof the pre-drilled holes, the torque T0 = 750 N-m was appliedto the steel rod before the pin could be inserted into theholes. Determine the torque (N-m) in each component afterT0 was removed. Use G = 80 GPa for steel and G = 28 GPa foraluminumarrow_forward
- Correct answer and complete fbd only. I will upvote. 9: The two steel shafts, each with one end builtinto a rigid support, have flanges attached to their freeends. The flanges are to be bolted together. However,initially there is a 6⁰ mismatch in the location of the boltholes as shown in the figure. Determine the maximumshear stress(ksi) in each shaft after the flanges have beenbolted together. The shear modulus of elasticity for steelis 12 x 106 psi. Neglect deformations of the bolts and theflanges.arrow_forwardCorrect answer and complete fbd only. I will upvote. The tapered, wrought iron shaft carriesthe torque T = 2000 lb-in at its free end. Determine theangle of twist (degrees) of the shaft. Use G = 10 x 106psi for wrought ironarrow_forwardCorrect answer and complete fbd only. I will upvote. The compound shaft, consisting of steel and aluminumsegments, carries the two torques shown in the figure. Determine themaximum permissible value of T subject to the following designconditions: τst ≤ 83 MPa, τal ≤ 55 MPa, and θ ≤ 6⁰ (θ is the angle ofrotation of the free end). Use G =83 GPa for steel and G = 28 GPa foraluminum.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- International Edition---engineering Mechanics: St...Mechanical EngineeringISBN:9781305501607Author:Andrew Pytel And Jaan KiusalaasPublisher:CENGAGE L

International Edition---engineering Mechanics: St...
Mechanical Engineering
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:CENGAGE L
moment of inertia; Author: NCERT OFFICIAL;https://www.youtube.com/watch?v=A4KhJYrt4-s;License: Standard YouTube License, CC-BY