Chapter 9.6, Problem 9.14WE

Interpretation Introduction

Interpretation:

Mass present of $Cl$ present in given sample should be calculated.

Concept introduction:

Precipitation reaction:

• If precipitate is formed, when the two salt solutions are mixed together is called precipitation reaction and precipitate is an insoluble new product of reaction of two solutions.
• The mass of produced precipitate is depends on the mass of reactants.

Mass present:

The mass present is given by the ratio between mass of the analyte and total mass of the sample is multiplied with hundred.

$Masspresent=\frac{Massofanalyte}{Samplemass}\times 100$