Chapter 9, Problem 9.64QP

Interpretation Introduction

Interpretation:

The mass of $\text{RbOH}$ present in a $\text{35}\text{.0}\text{mL}$ $\text{5}\text{.50 M}$ $\text{RbOH}$ solution has to be determined.

Concept introduction:

Mole

The mole of the solute is calculated by multiplication of concentration of solution and volume of the solution and it is,

$\text{Mole}\text{=}\text{Concentration}\text{(M)×}\text{volume}\text{(L)}$

The mass of compound is given by the multiplication of mole of the compound and molar mass of the compound in gram.

$\text{Mass}\text{=}\text{Mole×}\text{Molar}\text{mass}$