Chapter 9.5, Problem 6PE

Suppose that the given system has one solution.

$\begin{array}{c}{a}_{1}x+b_{1}y=c_1\\ a_{2}x+b_{2}y=c_2\end{array}$

Cramer’s rule gives the solution as $x=\frac{\boxed{}}{\boxed{}}$ and $y=\frac{\boxed{}}{\boxed{}}$ , where $D=\left|\begin{array}{cc}\boxed{}& \boxed{}\\ \boxed{}& \boxed{}\end{array}\right|,D_x=\left|\begin{array}{cc}\boxed{}& \boxed{}\\ \boxed{}& \boxed{}\end{array}\right|$ , and $D_y=\left|\begin{array}{cc}\boxed{}& \boxed{}\\ \boxed{}& \boxed{}\end{array}\right|$ .