A farmer sells organic zucchini, yellow squash, and corn in two different roadside stands. Matrix Q represents the number of pounds of each type of vegetable sold at each stand. Matrix P gives the price per pound of each item. Find the product Q P and interpret the result. Yellow Zucchini squash Corn Q = 42 40 84 30 36 90 Stand 1 Stand 2 P = $ 4.00 $ 3.40 $ 4.20 Zucchini Yellow squash Corn
A farmer sells organic zucchini, yellow squash, and corn in two different roadside stands. Matrix Q represents the number of pounds of each type of vegetable sold at each stand. Matrix P gives the price per pound of each item. Find the product Q P and interpret the result. Yellow Zucchini squash Corn Q = 42 40 84 30 36 90 Stand 1 Stand 2 P = $ 4.00 $ 3.40 $ 4.20 Zucchini Yellow squash Corn
Solution Summary: The author calculates the product, QP, and interprets it. The matrix represents the total revenue from two different stands.
A farmer sells organic zucchini, yellow squash, and corn in two different roadside stands. Matrix
Q
represents the number of pounds of each type of vegetable sold at each stand. Matrix
P
gives the price per pound of each item. Find the product
Q
P
and interpret the result.
Yellow
Zucchini
squash
Corn
Q
=
42
40
84
30
36
90
Stand 1
Stand 2
P
=
$
4.00
$
3.40
$
4.20
Zucchini
Yellow squash
Corn
C erka
LG Middle School X
ign in to Outloo
Cvr iol
Math To Do, i-Rez X
/student/dashboard/home
Joel maps his house and his school on a coordinate grid where each unit is 1 block.
His school is at (-7,-2). His house is at (3,-2). How many blocks from his house is his
school?
10
10 blocks
4 blocks
4 blocks
-X10 -9 -8-7 -6-5-4 -3 -2 -1o
10 blocks
-7
10
Done >
Progress
5:20 PM
G dx
not be reproduced or shared in any manner without express written consent of Curiculum Associates
Find AB,
-2 -1 -4
A=3 -1
B=
%3D
%3D
2 7
6 3
6
4-8
EVALUATION.
Matching Type. Match Column A with Column B. Write the letter of your choice from Column B in
the blank before each item number.
Column A
Column B
1. у %3D х2 + 2х —3 at (-2,-3)
а. 6
2. y = 2x2 – 3x + 1 at (2,3)
b. 5
3. y = x2 – 4x + 1 at (2, –3)
С. -2
4. y = 3x² + 4x at (1, 7)
d. 0
5. y = 3x2 + 2 at (1,5)
е. 10
Single Variable Calculus: Early Transcendentals (2nd Edition) - Standalone book
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