Chapter 9.5, Problem 20E

To determine

Tofind:Midpoint of segment $\overline{FG}$

Answer to Problem 20E

  $M=\left(2,-1\right)$

Explanation of Solution

Given information:

  $\begin{array}{l}F=\left(x_1,y_1\right)=\left(3,1\right)\\ G=\left(x_2,y_2\right)=\left(1,-3\right)\end{array}$

Concept Used:

Midpoint of two points - $M=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)$

Calculation:

  $\begin{array}{l}M=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)\\ \Rightarrow M=\left(\frac{3+1}{2},\frac{1-3}{2}\right)\\ \Rightarrow M=\left(\frac{4}{2},\frac{-2}{2}\right)\\ \Rightarrow M=\left(2,-1\right)\end{array}$