Chapter 9.5, Problem 19E

To determine

Tofind:Midpoint of segment $\overline{EF}$

Answer to Problem 19E

  $M=\left(1,2\right)$

Explanation of Solution

Given information:

  $\begin{array}{l}E=\left(x_1,y_1\right)=\left(-1,3\right)\\ F=\left(x_2,y_2\right)=\left(3,1\right)\end{array}$

Concept Used:

Midpoint of two points - $M=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)$

Calculation:

  $\begin{array}{l}M=\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)\\ \Rightarrow M=\left(\frac{-1+3}{2},\frac{3+1}{2}\right)\\ \Rightarrow M=\left(\frac{2}{2},\frac{4}{2}\right)\\ \Rightarrow M=\left(1,2\right)\end{array}$