STANDALONE CODE MECHANICS OF MATERIALS-M
11th Edition
ISBN: 9780137605200
Author: HIBBELER
Publisher: PEARSON
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Chapter 9.4, Problem 8FP
Also, find the corresponding orientation of the element with respect to the element shown.
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Chapter 9 Solutions
STANDALONE CODE MECHANICS OF MATERIALS-M
Ch. 9.3 - Determine the normal stress and shear stress...Ch. 9.3 - Determine the equivalent state of stress on an...Ch. 9.3 - Also, find the corresponding orientation of the...Ch. 9.3 - Determine the equivalent state of stress on an...Ch. 9.3 - Determine the maximum principal stress at point B.Ch. 9.3 - Determine the principal stress at point C.Ch. 9.3 - Determine the stress components acting on the...Ch. 9.3 - Solve Prob.99 using the stress transformation...Ch. 9.3 - Determine the stress components acting on the...Ch. 9.3 - Determine the equivalent state of stress on an...
Ch. 9.3 - The stress along two planes at a point is...Ch. 9.3 - The state of stress at a point in a member is...Ch. 9.3 - The wood beam is subjected to a load of 12 kN. If...Ch. 9.3 - The internal loadings at a section of the beam are...Ch. 9.3 - Solve Prob.925 for point B. 925. The internal...Ch. 9.3 - Solve Prob.925 for point C. 925. The internal...Ch. 9.3 - It is subjected to a torque of 12 kip in. and a...Ch. 9.3 - A paper tube is formed by rolling a cardboard...Ch. 9.3 - Solve Prob.931 for the normal stress acting...Ch. 9.3 - Determine the principal stresses in the...Ch. 9.3 - The shaft has a diameter d and is subjected to the...Ch. 9.4 - Use Mohrs circle to determine the normal stress...Ch. 9.4 - Also, find the corresponding orientation of the...Ch. 9.4 - Draw Mohrs circle and determine the principal...Ch. 9.4 - Determine the principal stresses at a point on the...Ch. 9.4 - Determine the principal stresses at point A on the...Ch. 9.4 - Point A is just below the flange.Ch. 9.4 - Mohrs circle for the state of stress is shown in...Ch. 9.4 - Determine (a) the principal stresses and (b) the...Ch. 9.4 - Determine the equivalent state of stress if an...Ch. 9.4 - Draw Mohrs circle that describes each of the...Ch. 9.4 - Draw Mohrs circle trial describes each of the...Ch. 9.4 - Determine (a) the principal stresses and (b) the...Ch. 9.4 - Determine (a) the principal stresses and (b) the...Ch. 9.4 - Draw Mohrs circle that describes each of the...Ch. 9.4 - The grains of wood in the board make an angle of...Ch. 9.4 - A spherical pressure vessel has an inner radius of...Ch. 9.4 - The cylindrical pressure vessel has an inner...Ch. 9.4 - If the box wrench is subjected to the 50 lb force,...Ch. 9.4 - If the box wrench is subjected to the 50-lb force,...Ch. 9.5 - Draw the three Mohrs circles that describe each of...Ch. 9.5 - Draw the three Mohrs circles that describe the...Ch. 9.5 - Determine the principal stresses and the absolute...Ch. 9.5 - The solid shaft is subjected to a torque, bending...Ch. 9.5 - The frame is subjected to a horizontal force and...Ch. 9 - Prob. 1RPCh. 9 - The steel pipe has an inner diameter of 2.75 in....Ch. 9 - Determine the equivalent state of stress If an...Ch. 9 - The crane is used to support the 350-lb load....Ch. 9 - Determine the equivalent state of stress on an...Ch. 9 - The propeller shaft of the tugboat is subjected to...Ch. 9 - Determine the principal stresses in the box beam...Ch. 9 - Determine (a) the principal stresses and (b) the...Ch. 9 - Determine the stress components acting on the...
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- (Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forwardProblem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forward
- Problem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forwardAn experimental setup is being built to study the flow in a large water main (i.e., a large pipe). The water main is expected to convey a discharge (Qp). The experimental tube will be built at a length scale of 1/20 of the actual water main. After building the experimental setup, the pressure drop per unit length in the model tube (APm/Lm) is measured. Problem (20): Given the value of APm/Lm [kPa/m], and assuming pressure coefficient similitude, calculate the drop in the pressure per unit length of the water main (APP/Lp) in [Pa/m]. Givens: AP M/L m = 590.637 kPa/m meen Answers: ( 1 ) 59.369 Pa/m ( 2 ) 73.83 Pa/m (3) 95.443 Pa/m ( 4 ) 44.444 Pa/m *******arrow_forward
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