Explanation Given information: The interval − 1 ≤ x ≤ 2 is dividedin n = 5 . Explanation: By comparing the interval − 1 ≤ x ≤ 2 to a ≤ x ≤ b , it becomes, a = − 1 and b = 2 . The length of each subinterval Δ x = b − a n = 2 + 1 5 = 3 5 = 0.6 Consider the interval, a ≤ x ≤ b If the interval divides in n subintervals, the endpoints of the subinterval are a 0 , a 1 , ... , a n . Where a 0 = a , a 1 = a 0 + Δ x , a 2 = a 1 + Δ x , .... , a n = a n − 1 + Δ x Now, a 0 = a ⇒ a 0 = − 1 a 1 = a 0 + Δ x = − 1 + 0

Calculus & Its Applications (14th Edition)

14th Edition

ISBN: 9780134437774

Author: Larry J. Goldstein, David C. Lay, David I. Schneider, Nakhle H. Asmar

Publisher: PEARSON

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Chapter 9.4, Problem 2E

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The value of Δx and the end points a0,a1,a2...,an are of the subintervals where the interval −1≤x≤2 is dividedin n=5 subintervals.

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Chapter 9.4, Problem 1E

Chapter 9.4, Problem 3E

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The value of Δ x and the end points a 0 , a 1 , a 2 ... , a n are of the subintervals where the interval − 1 ≤ x ≤ 2 is dividedin n = 5 subintervals.

Solution Summary: The author explains the value of Delta x and the end points of the subintervals.

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The value of Δx and the end points a0,a1,a2...,an are of the subintervals where the interval −1≤x≤2 is dividedin n=5 subintervals.

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