Compute the value of the test statistic. b. use the t distribution table to compute a range for the p-value. c. At α = 0.05 , what is your conclusion? d. what is the rejection rule using the critical value? what is your conclusion?
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H0:μ = 18 Ha:μ ≠ 18
A sample of 48 provided a sample
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- Use the given information to find the P-value. Also, use a 0.05 significance level and state theconclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).With H1: p (does not equal) 3/5, the test statistic is z = 0.78For the hypothesis test Ho: u = 14 against H1:µ < 14 and variance known, calculate the P-value for the following test statistic: Z0 = - 1.96. Round your answer to three decimal places (e.g. 98.765). P-valueAssume a significance level of α=0.05 and use the given information to complete parts (a) and (b) below. Original claim: The mean pulse rate (in beats per minute) of a certain group of adult males is 68 bpm. The hypothesis test results in a P-value of 0.0901. a. State a conclusion about the null hypothesis. (Reject H0 or fail to reject H0.) Choose the correct answer below. A. Reject H0 because the P-value is greater than α. B. Fail to reject H0 because the P-value is greater than α. C. Reject H0 because the P-value is less than or equal to α. D. Fail to reject H0 because the P-value is less than or equal to α. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to warrant rejection of the claim that the mean pulse rate (in beats per minute) of the group of adult males is 68 bpm. B.…
- Perform the following hypothesis test: HO: µ = 10 H1: µ 10 The sample mean is 9.55, population standard deviation of 1.5 and a sample size of 51. Use a 5% significance level. What is the value of the test statistic? (Give your answer rounded to 2 decimals) (Be careful to make sure your + or - sign is correct)Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With H 1: p≠0.377, the test statistic is z=3.06.Q1: A researcher was interested in the effect of exercise on stress levels. For the general population, the distribution of the Stress Battery Scale scores is normal with the mean of µ = 25 and the standard deviation of σ = 5. A sample of n = 100 participants was asked to exercise for three weeks and then reported their stress levels. The sample mean was ?X = 23. Conduct a hypothesis test and determine the effect of exercise. Use the two-tailed test α = .01 1.Type the null and research hypotheses in complete sentences. 2.Cut off points 3.Standard error and z-score -show your computation process 4.Your conclusion thoroughly.
- You wish to test the following claim (HaHa) at a significance level of α=0.01α=0.01. Ho:μ=67.6Ho:μ=67.6 Ha:μ<67.6Ha:μ<67.6You believe the population is normally distributed. You obtain a sample mean of 64.2 and a sample standard deviation of 10.4 for a sample of size 34.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05. Ho:μ=58.7Ho:μ=58.7 Ha:μ>58.7Ha:μ>58.7You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=12n=12 with mean M=61.2M=61.2 and a standard deviation of SD=7.8.What is the test statistic for this sample? (Report answer accurate to three decimal places.)test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value = The p-value is... less than (or equal to) α greater than α This test statistic leads to a decision to... reject the null accept the null fail to reject the null As such, the final conclusion is that... There is sufficient evidence to warrant rejection of the claim that the population mean is greater than 58.7. There is not sufficient evidence to warrant rejection of the claim that the population mean is greater than 58.7. The sample data support the…For the following claim, find the null and alternative hypotheses, test statistic, critical value, and draw a conclusion. Assume that a simple random sample has been selected from a normally distributed population. Claim: The mean IQ score of statistics professors is less than 122. Sample data: n=21, x=120, s=14. The significance level is α=0.05. 1. Determine the test statistic t. t= ____ (Round to three decimal places as needed.) 2. Find the critical value using a t-distribution table. The critical value is ____ (Round to three decimal places as needed.) 3. What is the conclusion? A. Fail to reject the null hypothesis and do not support the claim tha μ>130. B. Reject the null hypothesis and do not support the claim that μ>130. C. Reject the null hypothesis and support the claim that μ>130. D. Fail to reject the null hypothesis and support the claim that μ>130.
- If the t-statistic for a single sample t-test is 1.58, what can you conclude? a. The test is significant at an alpha level of .05. b. The sample size of the test was at least 30. c. The sample mean was larger than the population mean. d. The population standard deviation was smaller than the difference between the sample mean and the population mean.You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05. Ho:μ=67.5Ho:μ=67.5 Ha:μ>67.5Ha:μ>67.5You believe the population is normally distributed, but you do not know the standard deviation. You obtain a sample of size n=10n=10 with mean M=77.3M=77.3 and a standard deviation of SD=19.4SD=19.4.What is the p-value for this sample? (Report answer accurate to four decimal places.)p-value =Use the t-distribution and the sample results to complete the test of the hypotheses. Use a 5% significance level. Assume the results come from a random sample, and if the sample size is small, assume the underlying distribution is relatively normal.Test H0 : μ=15 vs Ha : μ>15 using the sample results x¯=17.2, s=6.4, with n=40. (a) Give the test statistic and the p-value.Round your answer for the test statistic to two decimal places and your answer for the p-value to three decimal places.test statistic = p-value =
